I have string in this from ["658681","655917","655904"]i want to change this string in this form 658681,655917,655904 how it can be changed? below is my code of string
- (IBAction)Searchbtn:(id)sender {
NSData *data=[NSJSONSerialization dataWithJSONObject:getmessageIDArray options:kNilOptions error:nil];
_finalIDStr=[[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(#"the final ID Str==%#",_finalIDStr);
}
Use following code:
NSCharacterSet *unwantedChars = [NSCharacterSet characterSetWithCharactersInString:#"\"[]"];
NSString *requiredString = [[_finalIDStr componentsSeparatedByCharactersInSet:unwantedChars] componentsJoinedByString: #""];
It's efficient and effective way to remove as many characters from your string in one single line..
this will do it in swift
var stringwithoutquotes = string1.stringByReplacingOccurrencesOfString("\"", withString: "")
var removebracket1 = stringwithoutquotes.stringByReplacingOccurrencesOfString("[", withString: "")
var removebracket2 = removebracket1.stringByReplacingOccurrencesOfString("]", withString: "")
or you could do the entire thing in one line
var string2 = string.stringByReplacingOccurrencesOfString("\"", withString: "").stringByReplacingOccurrencesOfString("[", withString: "").stringByReplacingOccurrencesOfString("]", withString: "")
Here is another cleaner option in swift
var string = "\"hello[]" // string starts as "hello[]
var badchar: NSCharacterSet = NSCharacterSet(charactersInString: "\"[]")
var cleanedstring: NSString = (string.componentsSeparatedByCharactersInSet(badchar) as NSArray).componentsJoinedByString("")
//cleanedstring prints as "hello"
Swift 3:
let string = "\"hello[]" // string starts as "hello[]
let badchar = CharacterSet(charactersIn: "\"[]")
let cleanedstring = string.components(separatedBy: badchar).joined()
//cleanedstring prints as "hello"
Swift 4 (String Array)
I wanted to convert String Array into String text to be placed in TextView:
FROM
["horse","cat","dog"]
TO
horse
cat
dog
var stringArray = ["horse","cat","dog"]
var stringArrayCleaned = stringArray.description.replacingOccurrences(of: "\"", with: "").replacingOccurrences(of: ",", with: "\n").replacingOccurrences(of: "[", with: "").replacingOccurrences(of: "]", with: "").replacingOccurrences(of: " ", with: "")
print(stringArrayCleaned)
You can try :
[[[_finalIDStr stringByReplacingOccurrencesOfString:#"\"" withString:#""] stringByReplacingOccurrencesOfString:#"[" withString:#""] stringByReplacingOccurrencesOfString:#"]" withString:#""];
I know this is an old question, but in case someone is still looking for answer.. I achieved this in swift using joined(separator:) see: apple documentation
var stringArray = ["alice","bob","cindy"]
print(stringArray.joined(separator: ","))
// this will print: alice,bob,cindy
NSString *str = ["658681","655917","655904"];
NSCharacterSet *cs = [NSCharacterSet characterSetWithCharactersInString:#"\"[]"];
str = [[string componentsSeparatedByCharactersInSet:cs] componentsJoinedByString:#""];
Related
So this is a string I get back from the server:
var arrayString = "IT34:1, IT35:2, IT36:1, IT35:3"
I want to get rid of any occurrences of ":1", ":2" and am using:
let cleanStr = arrayString.stringByReplacingOccurrencesOfString(":1", withString: "", options: NSStringCompareOptions.LiteralSearch, range: nil)
let cleanStr1 = cleanStr.stringByReplacingOccurrencesOfString(":2", withString: "", options: NSStringCompareOptions.LiteralSearch, range: nil)
And so on...
Which doesn't seem very efficient. Is it possible to accomplish this with just one .stringByReplacingOccurrencesOfString method? Like occurrences of ":(a number)"?
This can be done using regular expressions:
let string = "IT34:1, IT35:2, IT36:1, IT35:3"
var cleanStr = string
if let regex = NSRegularExpression(pattern: ":[0-9]", options:.CaseInsensitive, error: nil) {
cleanStr = regex.stringByReplacingMatchesInString(string, options: nil, range: NSMakeRange(0, countElements(string)), withTemplate: "")
}
println(cleanStr)
And in Objective-C:
NSString *string = #"IT34:1, IT35:2, IT36:1, IT35:3";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#":[0-9]" options:NSRegularExpressionCaseInsensitive error:nil];
NSString *newString = [regex stringByReplacingMatchesInString:string options:0 range:NSMakeRange(0, [string length]) withTemplate:#""];
NSLog(#"%#", newString);
I do not know the exact pattern of those ":1" thingies, but here's a solution you might fiddle with:
let cleanStr = ", ".join(arrayString.componentsSeparatedByString(", ").map { ($0 as NSString).substringToIndex(4) })
This solution will work as long as the ':1" things have one digit.
Here's a general solution:
let cleanStr = ", ".join(arrayString.componentsSeparatedByString(", ").map {
($0 as NSString).componentsSeparatedByString(":")[0] as String
})
I have an NSString like this
NSString *string = #"textTextTextTextText<br>textTextTextText<br>TextTextText"
I want to set this NSString to be the text of my UICell with a new line on each tag found on the string. How could I do that?
I've tried this, without success:
cell.textLabel.text = [[text componentsSeparatedByCharactersInSet:[NSCharacterSet newlineCharacterSet]] componentsJoinedByString:#"<br>"];
How about:
string = [string stringByReplacingOccurrencesOfString: #"<br>" withString: #"\n"]
or, if you're using Swift Strings
var string = "textTextTextTextText<br>textTextTextText<br>TextTextText"
string = Array(string).reduce("") {$0 + ($1 == "<br>" ? "\n" : $1)}
NSString * result =
[string stringByReplacingOccurrencesOfString:#"<br>" withString:#"\n"];
SWIFT 5:
If you are using Swift string (you can transform your NSString to String):
var string = "line1<br>line2<br>line3"
string = string..replacingOccurrences(of: "<br>", with: "\n"))
I am making an nsmutable array by separating a string by component it is causing a lot of new line and white spaces to be inserted in the array how to identify and remove them?
for (int i=0;i<contentsOfFile.count; i++)
{
if(!([[contentsOfFile objectAtIndex:i]isEqual:#"\n"]||[[contentsOfFile objectAtIndex:i]isEqual:#""]))
[arrayToBereturned addObject:[contentsOfFile objectAtIndex:i]];
}
this code which i am using cannot identify all new line charectors
thanks
To remove all extra space and \n from your string-
NSString* result = [yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
than prepare your contentsOfFile Array.
If you want an array without whitespace:
NSString *string = #"Hello, World!";
NSCharacterSet *separator = [NSCharacterSet whitespaceAndNewlineCharacterSet];
NSArray *stringComponents = [string componentsSeparatedByCharactersInSet:separator];
stringByTrimmingCharachersInSet: only removes desired characters from the end and the beginning of the string. To remove all occurences you should use stringByReplacingOccurrencesOfString:
Swift 5 version
let string = "Hello, stack overflow!"
let components = string.components(separatedBy: .whitespacesAndNewlines)
print(components) // prints ["Hello,", "stack", "overflow!"]
Also regarding string.replacingOccurrences
let string = " Hello, stack overflow ! "
let noSpacingsString = string.replacingOccurrences(of: " ", with: "")
print(components) // prints "Hello,stackoverflow!"
I'm developing an iPhone app. In a label, I want to show an user's first letter of the name uppercase. How do I do that?
If there is only one word String, then use the method
-capitalized
let capitalizedString = myStr.capitalized // capitalizes every word
Otherwise, for multi word strings, you have to extract first character and make only that character upper case.
(2014-07-24: Currently accepted answer is not correct) The question is very specific: Make the first letter uppercase, leave the rest lowercase. Using capitalizedString produces a different result: “Capitalized String” instead of “Capitalized string”. There is another variant depending on the locale, which is capitalizedStringWithLocale, but it's not correct for spanish, right now it's using the same rules as in english, so this is how I'm doing it for spanish:
NSString *abc = #"this is test";
abc = [NSString stringWithFormat:#"%#%#",[[abc substringToIndex:1] uppercaseString],[abc substringFromIndex:1] ];
NSLog(#"abc = %#",abc);
In case someone is still interested in 2016, here is a Swift 3 extension:
extension String {
func capitalizedFirst() -> String {
let first = self[self.startIndex ..< self.index(startIndex, offsetBy: 1)]
let rest = self[self.index(startIndex, offsetBy: 1) ..< self.endIndex]
return first.uppercased() + rest.lowercased()
}
func capitalizedFirst(with: Locale?) -> String {
let first = self[self.startIndex ..< self.index(startIndex, offsetBy: 1)]
let rest = self[self.index(startIndex, offsetBy: 1) ..< self.endIndex]
return first.uppercased(with: with) + rest.lowercased(with: with)
}
}
Then you use it exactly as you would for the usual uppercased() or capitalized():
myString.capitalizedFirst() or myString.capitalizedFirst(with: Locale.current)
Simply
- (NSString *)capitalizeFirstLetterOnlyOfString:(NSString *)string{
NSMutableString *result = [string lowercaseString].mutableCopy;
[result replaceCharactersInRange:NSMakeRange(0, 1) withString:[[result substringToIndex:1] capitalizedString]];
return result;
}
This is for your NSString+Util category...
- (NSString *) capitalizedFirstLetter {
NSString *retVal;
if (self.length < 2) {
retVal = self.capitalizedString;
} else {
retVal = string(#"%#%#",[[self substringToIndex:1] uppercaseString],[self substringFromIndex:1]);
}
return retVal;
}
You can do that with NSString stringWithFormat, of course. I use this weirdness:
#define string(...) \
[NSString stringWithFormat:__VA_ARGS__]
As an extension to the accepted answer
capitalizedString is used for making uppercase letters .
NSString *capitalizedString = [myStr capitalizedString]; // capitalizes every word
But if you have many words in a string and wants to get only first character as upper case use the below solution
NSString *firstCapitalChar = [[string substringToIndex:1] capitalizedString];
NSString *capString = [string stringByReplacingCharactersInRange:NSMakeRange(0,1) withString: capString];
// extract first character and make only that character upper case.
here's a swift extension for it
extension NSString {
func capitalizeFirstLetter() -> NSString {
return self.length > 1 ?
self.substringToIndex(1).capitalizedString + self.substringFromIndex(1) :
self.capitalizedString
}
}
This is how it worked for me:
NSString *serverString = jsonObject[#"info"];
NSMutableString *textToDisplay = [NSMutableString stringWithFormat:#"%#", serverString];
[textToDisplay replaceCharactersInRange:NSMakeRange(0, 1) withString:[textToDisplay substringToIndex:1].capitalizedString];
cell.infoLabel.text = textToDisplay;
Hope it helps.
Swift:
let userName = "hard CODE"
yourLabel.text = userName.localizedUppercaseString
I recommend using this localised version of uppercase, since names are locale sensitive.
I'm looking for a way to make sure a string can be used as a file name under iOS. I'm currently in the section of the code that deletes incompatible characters. I'm wondering if I'm doing it right.
NSString *filename = #"A file name";
fileName = [fileName stringByTrimmingCharactersInSet: [NSCharacterSet controlCharacterSet]];
fileName = [fileName stringByTrimmingCharactersInSet: [NSCharacterSet newlineCharacterSet]];
I'm also wondering if there's already a method that validates a string as a file name.
Thank you for your advice!
Use RegEx:
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"[^a-zA-Z0-9_]+" options:0 error:nil];
filename = [regex stringByReplacingMatchesInString:filename options:0 range:NSMakeRange(0, filename.length) withTemplate:#"-"];
I find this to be cleaner and probably much more performant. This is based on Angel Naydenov's solution, but first constructing Character set with all invalid characters and then calling components(separatedBy:) just once.
Swift 3 & 4
var invalidCharacters = CharacterSet(charactersIn: ":/")
invalidCharacters.formUnion(.newlines)
invalidCharacters.formUnion(.illegalCharacters)
invalidCharacters.formUnion(.controlCharacters)
let newFilename = originalFilename
.components(separatedBy: invalidCharacters)
.joined(separator: "")
Swift 2
let invalidCharacters = NSMutableCharacterSet(charactersInString: ":/")
invalidCharacters.formUnionWithCharacterSet(NSCharacterSet.newlineCharacterSet())
invalidCharacters.formUnionWithCharacterSet(NSCharacterSet.illegalCharacterSet())
invalidCharacters.formUnionWithCharacterSet(NSCharacterSet.controlCharacterSet())
let filename = originalFilename
.componentsSeparatedByCharactersInSet(invalidCharacters)
.joinWithSeparator("")
First of all, you're using the wrong method. Trimming the string will only remove characters in the beginning and the end of the string.
What you're looking for is something more like:
fileName = [fileName stringByReplacingOccurrencesOfString:#"/" withString:#"_"];
However, that's a suboptimal solution, since you'll have to do that for every character you want to exclude, so maybe you want to keep looking or write you're own method for manipulating the string.
iOS is UNIX based and as such I suppose it supports almost any characters in filenames. UNIX allows white spaces, <, >, |, \, :, (, ), &, ;, as well as wildcards such as ? and *, to be quoted or escaped using \ symbol. However I wouldn't use any of those characters in my filenames. In fact, I would restrict the characters in my filenames to 'a'-'z', '0'-'9', '_' and '.'.
As I did not see a list with allowed characters in this question but the question wanted a list with such characters I am adding a bit more details on this topic.
First we need to know what is the file system that iOS devices use. Using multiple online sources this seems to be HFSX which is the HFS+ case sensitive version. And including one link here for reference: https://apple.stackexchange.com/questions/83671/what-filesystem-does-ios-use
Now that we know what the file system is we can look for what characters are not allowed. And these seem to be: colon (:) and slash (/). Here is a link for reference: http://www.comentum.com/File-Systems-HFS-FAT-UFS.html
Having this information and what others have written in this thread my personal preference for removing not allowed characters from file names is the following Swift code:
filename = "-".join(filename.componentsSeparatedByCharactersInSet(NSCharacterSet.newlineCharacterSet()))
filename = "-".join(filename.componentsSeparatedByCharactersInSet(NSCharacterSet.illegalCharacterSet()))
filename = "-".join(filename.componentsSeparatedByCharactersInSet(NSCharacterSet.controlCharacterSet()))
filename = "-".join(filename.componentsSeparatedByString(":"))
filename = "-".join(filename.componentsSeparatedByString("/"))
The reason I am not preferring the RegEx approach is that it seems too restrictive to me. I do not want to restrict my users only to Latin characters. They may as well wish to use some Chinese, Cyrillic or whatever else they like.
Happy coding!
I've had to save remote files locally with filenames containing other characters than basic alpha-numeric characters. I use the method below to strip out potential invalid characters, ensuring it's a valid filename for the filesystem when generating a NSURL using URLWithString:
filename = [[filename componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]] componentsJoinedByString:#"" ];
filename = [[filename componentsSeparatedByCharactersInSet:[NSCharacterSet illegalCharacterSet]] componentsJoinedByString:#"" ];
filename = [[filename componentsSeparatedByCharactersInSet:[NSCharacterSet symbolCharacterSet]] componentsJoinedByString:#"" ];
fileURLString = [NSTemporaryDirectory() stringByAppendingPathComponent:filename];
fileURL = [NSURL URLWithString:fileURLString];
You may also want to test for collision errors first using:
[[NSFileManager defaultManager] fileExistsAtPath:[fileURL absoluteString]]
This String extension (Swift 4.2) will help convert an invalid iOS file name to a valid iOS file name.
extension String {
func convertToValidFileName() -> String {
let invalidFileNameCharactersRegex = "[^a-zA-Z0-9_]+"
let fullRange = startIndex..<endIndex
let validName = replacingOccurrences(of: invalidFileNameCharactersRegex,
with: "-",
options: .regularExpression,
range: fullRange)
return validName
}
}
For example
"name.name?/!!23$$#1asd".convertToValudFileName() // "name-name-23-1asd"
"!Hello.312,^%-0//\r\r".convertToValidFileName() // "-Hello-312-0-"
"/foo/bar/pop?soda=yes|please".convertToValidFileName() // "-foo-bar-pop-soda-yes-please"
I'm pretty happy with this solution:
NSString *testString = #"This*is::/legal.😀,?縦書き 123";
NSString *result = [[[testString componentsSeparatedByCharactersInSet:[[NSCharacterSet alphanumericCharacterSet] invertedSet]] filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:#"length > 0"]] componentsJoinedByString:#"-"];
Output:
"This-is-legal-縦書き-123"
What is this sorcery?
Let me break it up into multiple lines so it's clear what's going on:
NSString *testString = #"This*is::/legal.😀,?縦書き 123";
// Get a character set for everything that's NOT alphanumeric.
NSCharacterSet *nonAlphanumericCharacterSet = [[NSCharacterSet alphanumericCharacterSet] invertedSet];
// Split the string on each non-alphanumeric character, thus removing them.
NSArray *cleanedUpComponentsWithBlanks = [testString componentsSeparatedByCharactersInSet:nonAlphanumericCharacterSet];
// Filter out empty strings ("length" is a KVO-compliant property that the predicate can call on each NSString in the array).
NSArray *cleanedUpComponentsWithoutBlanks = [cleanedUpComponentsWithBlanks filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:#"length > 0"]];
// Put the components back together and join them with a "-".
NSString *result = [cleanedUpComponentsWithoutBlanks componentsJoinedByString:#"-"];
Enjoy!
Swift 4 Version
Added by john-pang on 2021-09-01 with Swift version:
let testString = "This*is::/legal.😀,?縦書き 123"
// Get a character set for everything that's NOT alphanumeric.
let nonAlphanumericCharacterSet = CharacterSet.alphanumerics.inverted
// Split the string on each non-alphanumeric character, thus removing them.
let cleanedUpComponentsWithBlanks = testString.components(separatedBy: nonAlphanumericCharacterSet)
// Filter out empty strings ("length" is a KVO-compliant property that the predicate can call on each NSString in the array).
let cleanedUpComponentsWithoutBlanks = cleanedUpComponentsWithBlanks.filter { $0.length > 0 }
// Put the components back together and join them with a "-".
let result = cleanedUpComponentsWithoutBlanks.joined(separator: "_")
I came up with the following solution. Works nice so far.
import Foundation
extension String {
func removeUnsupportedCharactersForFileName() -> String {
var cleanString = self
["?", "/", "\\", "*"].forEach {
cleanString = cleanString.replacingOccurrences(of: $0, with: "-")
}
return cleanString
}
}
let a = "***???foo.png"
let validString = a.removeUnsupportedCharactersForFileName()
Base on Marian Answers, here is a string extension to remove any unwanted characters.
extension String {
func stripCharacters() -> String {
var invalidCharacters = CharacterSet(charactersIn: ":/")
invalidCharacters.formUnion(.newlines)
invalidCharacters.formUnion(.illegalCharacters)
invalidCharacters.formUnion(.controlCharacters)
let newString = self
.components(separatedBy: invalidCharacters)
.joined(separator: "_")
return newString
}
}
Example:
let fileName = "Man(lop23/45"
let newFileName = fileName.stripCharacters()
print(newFileName)
Swift 5 extension:
I wanted to remove emojis as well and in windows \ is also an invalid character. So I added symbols charset and backslash \ as well.
extension String {
var validFilename: String {
let invalidCharsets = CharacterSet(charactersIn: ":/\\")
.union(.illegalCharacters)
.union(.controlCharacters)
.union(.symbols)
.union(.newlines)
return self.components(separatedBy: invalidCharsets).joined()
}
}