dynamically set the header menudata like columns below
headermenu: { id: "headerMenu", css: "webix-contextmenu", width: 150, data: getHeaderMenuData(),
}
Like setting externally for columns, function add_column(){ var columns = webix.toArray(grid.config.columns); columns.insertAt({ id:"c"+webix.uid(), header:"New column" },2); grid.refreshColumns(); }
is there a way that I can set for headerMenu data.
Normally the header menu will regenerated self after refreshColumns call, and will include the newly added column. ( you may need to update to the latest version of Webix )
Also, you can add items to header menu directly, by using code like next
var menu_id = grid.config.headermenu;
$$(menu_id).add({
id:"new", value:"NEW"
});
Related
I tried to apply PasswordRenderer to a specific row and column based on the value of that row.
So my custom renderer looked like this -
function firstRowRenderer(instance, td, row, col, prop, value, cellProperties) {
Handsontable.renderers.PasswordRenderer.apply(this, arguments); }
However the problem I face is, while editing the cells, the field is no longer masked. Here is an example - http://jsfiddle.net/whxbv6xh/
If you try and edit the first row of that table, the values are not masked. Any ideas?
This "unmasking" of the field is what the PasswordRenderer is essentially all about. If you want to not be able to see the original values at all you have at least two options:
1.Convert the header row's values beforehand:
function renderAsPassword(password) {
return new Array(password.length + 1).join('*');
}
alert(['', 'Kia', 'Nissan', 'Toyota', 'Honda'].map(renderAsPassword));
2.Create a custom editor, extending the built-in PasswordEditor:
var PasswordEditor = Handsontable.editors.PasswordEditor.prototype.extend();
PasswordEditor.prototype.getValue = function() {
return renderAsPassword(this.TEXTAREA.value);
};
PasswordEditor.prototype.setValue = function(newValue){
this.TEXTAREA.value = renderAsPassword(newValue);
};
I'm using the angularjs ui-grid and I have a "total" row that I want to pin to the top of the grid no matter what is the current sorting.
How can I accomplish that?
I think this is what you are looking for : Row Pinning
Essentially add another hidden column, something like this:
{
field: 'pinned',
visible: false,
sort: {direction: uiGridConstants.ASC, priority: 0}, //use uiGridConstants.DESC for pinning to the bottom
suppressRemoveSort: true,
sortDirectionCycle: [uiGridConstants.ASC] //use uiGridConstants.DESC for pinning to the bottom
}
Row entities which have pinned = true rise to the top, even when other sorting are applied.
DISCLAIMER: I know it's not exactly answers the question, but this is how I solved it for now until I'll have a better solution:
Create an other grid above the main grid :
<div style="height:30px" ui-grid="totalGridOptions"></div>
<div ui-grid="gridOptions" class="grid"></div>
with definitions:
$scope.totalGridOptions = {showHeader:false,enableHorizontalScrollbar:false};
and then bind the columns of the main grid to the total grid (for width and other adjustments):
$scope.$watch('gridOptions', function (newVal) {
$scope.totalGridOptions.columnDefs = newVal.columnDefs;
}, true);
I think you should use something like this
$scope.gridOptions.data.unshift({label:value});
unshift adds it to the top
Edit 2 / Actual Solution: The way I finally settled this issue was by using custom header cell templates. I essentially create a second header row by adding a div at the bottom of what was previously my header. Here's a simple version:
<div class="super-special-header>
<div class="header-display-name">{{col.displayName}}</div>
<div class="totals-row">{{grid.appScope.totals[col.field]}}</div>
</div>
I store my totals on the controller's $scope and can access them in that div with grid.appScope.totals[whateverThisColumnIs]. This way I can still update them dynamically, but they don't get mixed into a sort function like my previous 'solution' was aiming for.
Edit 1 / Dead-end 'solution': Just ran into a problem with my solution, if your table is long (you have to scroll to get to bottom rows), the totals row will scroll out of view. Going to leave this 'solution' here so no one else makes the same mistake!
I had this same issue but with a twist. Since I was going to need to change the default sorting algorithms for many of the columns anyway, I set my algorithm up to skip the first element in the sort. You can use the sortingAlgorithm property on any columndef that would be part of a sortable column. This is really only a solution if you have only a few sortable columns though. It becomes unmaintainable for huge tables.
I couldn't find any built-in feature for ui-grid to keep a specific row at the top of the grid when sorting is applied. But this could be done using sortingAlgorithm parameter in the columnDefs( please refer to http://ui-grid.info/docs/#!/tutorial/Tutorial:%20102%20Sorting).
I have written an algorithm which keeps the row('total' is the particular cell value in the row) at the top of the grid without applying a sorting.
var sortingAlgorithm = function (a, b, rowA, rowB, direction) {
if (direction == 'total') {
if (a == 'total') {
return 0;
}
return (a < b) ? -1 : 1;
} else {
if (a == 'total') {
return 0;
}
if (b == 'total') {
return 1;
}
}
}
How to add more textfields in a view on clicking a button in the same view in sproutcore?
I have a sliding pane with particular number of textfields. On clicking a button, I need to add more number of text field in the same view.
Or,
I should be able to select the number from a select button view and show those many number of textfield in the same view.
I would recommend using a SC.ListView for this purpose.
You should have a SC.ArrayController whose content is an array containing objects that represent each text field. This may be as simple as something like this:
MyApp.myController = SC.ArrayController.create({
content: [
SC.Object.create({ someProperty: "Text field value 1" }),
SC.Object.create({ someProperty: "Text field value 2" }),
SC.Object.create({ someProperty: "Text field value 3" })
]
});
Next, you'll create your SC.ListView and bind it's content to the controller, and create the exampleView whose content is bound to the someProperty property of the objects:
MyApp.MyView = SC.View.extend({
childViews: 'scrollView addButtonView'.w(),
scrollView: SC.ScrollView.extend({
layout: { top: 0, left: 0, right: 0, bottom: 50 },
contentView: SC.ListView.extend({
contentBinding: 'MyApp.myController.arrangedObjects',
rowHeight: 40,
exampleView: SC.View.extend({
childViews: 'textFieldView'.w(),
textFieldView: SC.TextFieldView.extend({
// Add a little margin so it looks nice
layout: { left: 5, top: 5, right: 5, bottom: 5 },
valueBinding: 'parentView.content.someProperty'
})
})
})
}),
addButtonView: SC.ButtonView.extend({
layout: { centerX: 0, bottom: 10, width: 125, height: 24 },
title: "Add Text Field",
// NOTE: The following really should be handled by a statechart
// action; I have done it inline for simplicity.
action: function() {
MyApp.myController.pushObject(SC.Object.create({ value: "New Field" }));
}
})
});
Now, when you click the "Add Text Field" button, it will add a new object to the controller array which will automatically re-render the list view with the new object and hence, the new text field.
A couple of notes:
This uses a SC.ScrollView in conjunction with the SC.ListView, you will almost always want to do it this way.
Since we are using standard bindings (not SC.Binding.oneWay()), editing the text fields will automatically update the someProperty property in the objects in MyApp.myController and vice versa: if you update the value via some other means, the text field should automatically update as well.
This should not be used for a large list as using the childViews method of view layout can be slow. If you need performance, you should change the exampleView to a view that overrides the render() method and manually renders a text input and sets up the proper change events and bindings.
Lastly, I can't remember if the proper syntax for the text field's valueBinding is parentView.content.someProperty or .parentView.content.someProperty (notice the period at the beginning). If the first way doesn't work, try adding the . and see if that works.
Like Topher I'm assuming you're using SproutCore not Ember (formerly SC2).
If you need to add an arbitrary child view to an arbitrary location on your view, you want view.appendChild. In the button's action, you would do something like this:
this.get('parentView').appendChild(SC.View.create({ ... }))
If you go this route, you'll have to figure out the layout for the new view yourself. If you don't need to precisely control the layout, then go with Topher's solution - the ListView does the layout piece for you.
I have a splitter. In this splitter, I am implementing drag and drop functionality for the list view. Each list view is loaded in "table" format.
I want to drag my list view from left to right.
For the 1st list view, I have this code :
var listViewOptions = {
template: kendo.template(
$("#Firsttemplate").html()
),
dataSource: listdatSource,
};
var sourceListView = $("#First").kendoListView(listViewOptions).data("kendoListView");
var draggableOptions = {
filter: "table",
hint: function (e) {
return $('<div class="new">' + e.html() + '</div>');
}
}
sourceListView.element.kendoDraggable(draggableOptions);
In the filter, if I give "table" / "tbody" the whole content of list view is dragging in a row format and after dropping it is in the right side of splitter and is displaying in a single row. I want to display in the same format as in the leftside.
Can you tell me how to do this?
Thanks
somejQueryElement.html() gives you the inner HTML code of your element. Thus, if you filter on table elements, your argument e of the hint function is the table and e.html() is the content of the table.
If you want to have your table, you have to add reencapsulate the element in table tags :
var draggableOptions = {
filter: "table",
hint: function (e) {
return $('<div class="new"><table>' + e.html() + '</table></div>');
}
}
I created a multiselectable table in vaadin, but I can't select only a cell in this table when I click it selects all row.
Is there any way of selecting only a cell of a row ?
The title of the question doesn't reflect the actual question inside
Is there any way of selecting only a cell of a row ?
No. The whole point of a Vaadin table is to reflect rows of data in a tabular form. Setting a table to selectable keeps track of the itemIds of the selected rows with the table
You might be able to simulate selecting cells by using a ColumnGenerator in the table, and adding a listener to the generated component. Removing the listener may be tricky, however.
Alternatively, you may wish to simply generate components in a GridLayout and keep track of the selected cells yourself.
Ultimately, the approach here really depends upon exacly what you are trying to achieve.
It depends on what you're trying to accomplish. (Your question title and your question details are addressing two different questions.) If you're wondering whether or not you can target a specific cell and add a click listener to it, then yes, of course you can:
//initial layout setup
final VerticalLayout layout = new VerticalLayout();
layout.setMargin(true);
setContent(layout);
//Create a table and add a style to allow setting the row height in theme.
final Table table = new Table();
table.addStyleName("components-inside");
//Define the names and data types of columns.
//The "default value" parameter is meaningless here.
table.addContainerProperty("Sum", Label.class, null);
table.addContainerProperty("Is Transferred", CheckBox.class, null);
table.addContainerProperty("Comments", TextField.class, null);
table.addContainerProperty("Details", Button.class, null);
//Add a few items in the table.
for (int i=0; i<100; i++) {
// Create the fields for the current table row
Label sumField = new Label(String.format(
"Sum is <b>$%04.2f</b><br/><i>(VAT incl.)</i>",
new Object[] {new Double(Math.random()*1000)}),
Label.CONTENT_XHTML);
CheckBox transferredField = new CheckBox("is transferred");
//Multiline text field. This required modifying the
//height of the table row.
TextField commentsField = new TextField();
//commentsField.setRows(3);
//The Table item identifier for the row.
Integer itemId = new Integer(i);
//Create a button and handle its click. A Button does not
//know the item it is contained in, so we have to store the
//item ID as user-defined data.
Button detailsField = new Button("show details");
detailsField.setData(itemId);
detailsField.addListener(new Button.ClickListener() {
public void buttonClick(ClickEvent event) {
// Get the item identifier from the user-defined data.
Integer iid = (Integer)event.getButton().getData();
Notification.show("Link " +
iid.intValue() + " clicked.");
}
});
detailsField.addStyleName("link");
//Create the table row.
table.addItem(new Object[] {sumField, transferredField,
commentsField, detailsField},
itemId);
}
//Show just three rows because they are so high.
table.setPageLength(3);
layout.addComponent(table);
It might be beneficial to examine the documentation.