I want to remove static text from string - iOS - ios

Hi I have a News Reader and I keep getting a string like this -
two New York police officers shot dead in 'ambush'
I want the string two New York police officers shot dead in ambush
How can I scan from & to ; and then delete occurrences of the scan.
I created a scanner like so -
NSString *webString222222 = filteredTitle2;
NSScanner *stringScanner222222 = [NSScanner scannerWithString:webString222222];
NSString *content222222 = [[NSString alloc] init];
[stringScanner222222 scanUpToString:#"&" intoString:Nil];
[stringScanner222222 scanUpToString:#";" intoString:&content222222];
NSString *filteredTitle222 = [content222222 stringByReplacingOccurrencesOfString:content222222 withString:#""];
NSString *filteredTitle22 = [filteredTitle222 stringByReplacingOccurrencesOfString:#"&" withString:#""];
But when I do this code the whole text disappears! Every single word.
When I check the title in my NSLog that is the only & sign in there and the only ; sign in there!
Im not sure where I went wrong here.

If the special characters you are encountering are all relatively consistent you can merely replace each of those substrings with the empty string, like so:
NSString *cleansedString = [filteredTitle2 stringByReplacingOccurrencesOfString:#"'"
withString:#""];

You can use NSRegularExpression to build proper matching pattern:
NSString *pattern = #"\\&#[0-9]+;";
NSString *str = #"two New York police officers shot dead in 'ambush'";
NSLog(#"Original test: %#",str);
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression
regularExpressionWithPattern:pattern
options:NSRegularExpressionCaseInsensitive error:&error];
if (error != nil)
{
NSLog(#"ERror: %#",error);
}
else
{
NSString *replaced = [regex stringByReplacingMatchesInString:str
options:0
range:NSMakeRange(0, [str length])
withTemplate:#""];
NSLog(#"Replaced test: %#",replaced);
}
See https://developer.apple.com/library/ios/documentation/Foundation/Reference/NSRegularExpression_Class/index.html

Related

Regex for a string combination

NSString *fmtpAudio = #"a=fmtp:111 ";
NSString *stereoString = #";stereo=1;sprop-stereo=1";
NSArray *componentArray = [localSdpMutableStr componentsSeparatedByString:fmtpAudio];
if (componentArray.count >= 2) {
NSString *component = [componentArray objectAtIndex: 1];
NSArray *fmtpArray = [component componentsSeparatedByString:#"\r\n"];
if (fmtpArray.count > 1) {
NSString *fmtp = [fmtpArray firstObject];
NSString *fmtpAudioOld = [NSString stringWithFormat:#"%#%#", fmtpAudio, fmtp];
fmtpAudio = [NSString stringWithFormat:#"%#%#%#", fmtpAudio, fmtp, stereoString];
NSString *stereoEnabledSDP = [NSString stringWithString: localSdpMutableStr];
stereoEnabledSDP = [stereoEnabledSDP stringByReplacingOccurrencesOfString: fmtpAudioOld withString: fmtpAudio];
localSdpMutableStr.string = stereoEnabledSDP;
}
}
Consider below example String:
a=fmtp:93 av=2\r\n
a=fmtp:111 av=1\r\n
a=fmtp:92 av=2\r\n
In the above example string, a=fmtp:111 can appear anywhere in the string.
We have to get the string between a=fmtp:111 and the next first appearance of \r\n which is av=1 in our case
Now we have to append ;stereo=1;sprop-stereo=1 to av=1 and append back to the original string.
The final output should be
a=fmtp:93 av=2\r\n
a=fmtp:111 av=1;stereo=1;sprop-stereo=1\r\n
a=fmtp:92 av=2\r\n
Is it possible to achieve the above chunk of logic with Replace with Regex pattern?
You can use
NSError *error = nil;
NSString *fmtpAudio = #"^a=fmtp:111 .*";
NSString *stereoString = #"$0;stereo=1;sprop-stereo=1";
NSString *myText = #"a=fmtp:93 av=2\r\na=fmtp:111 av=1\r\na=fmtp:92 av=2";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:fmtpAudio options:NSRegularExpressionAnchorsMatchLines error:&error];
NSString *modifiedString = [regex stringByReplacingMatchesInString:myText options:0 range:NSMakeRange(0, [myText length]) withTemplate: stereoString];
NSLog(#"%#", modifiedString);
Output:
a=fmtp:93 av=2
a=fmtp:111 av=1;stereo=1;sprop-stereo=1
a=fmtp:92 av=2
See the regex demo.
Details
^ - start of a line (^ starts matching line start positions due to the options:NSRegularExpressionAnchorsMatchLines option)
a=fmtp:111 - a literal string
.* - any zero or more chars other than line break chars as many as possible.
The $0 in the replacement pattern is the backreference to the whole match value.

SubString from existing string iOS

I have two strings as followed:
NSString *newStr = #"143.2a";
NSString *expression = #"^([0-9]*)(\\.([0-9]{0,10})?)?$";
I want to substring "newStr" such as all my characters in "expression" should be present after subString. Like
NSString * extractedString = #"143.2";
(except all alphabets and symbols other than single'.')
How shall I do this?
First of all, your regex pattern won't extract that string.
If you want to check for one or more digits followed be a dot followed be one or more digits the pattern is supposed to be
NSString *expression = #"\\d+\\.\\d+";
To extract the string use the NSRegularExpression class as suggested by Larme.
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:expression options:0 error:nil];
NSTextCheckingResult *firstMatch = [regex firstMatchInString:newStr options:0 range:NSMakeRange(0, newStr.length)];
if (firstMatch) {
NSString *extractedString = [newStr substringWithRange:firstMatch.range];
NSLog(#"%#", extractedString);
} else {
NSLog(#"Not Found");
}

Objective C - NSRegularExpression with specific substring

I have an NSString which I am checking if there is an NSLog and then I comment it out.
I am using NSRegularExpression and then looping through result.
The code:
-(NSString*)commentNSLogFromLine:(NSString*)lineStr {
NSString *regexStr =#"NSLog\\(.*\\)[\\s]*\\;";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:regexStr options:NSRegularExpressionCaseInsensitive error:nil];
NSArray *arrayOfAllMatches = [regex matchesInString:lineStr options:0 range:NSMakeRange(0, [lineStr length])];
NSMutableString *mutStr = [[NSMutableString alloc]initWithString:lineStr];
for (NSTextCheckingResult *textCheck in arrayOfAllMatches) {
if (textCheck) {
NSRange matchRange = [textCheck range];
NSString *strToReplace = [lineStr substringWithRange:matchRange];
NSString *commentedStr = [NSString stringWithFormat:#"/*%#*/",[lineStr substringWithRange:matchRange]];
[mutStr replaceOccurrencesOfString:strToReplace withString:commentedStr options:NSCaseInsensitiveSearch range:matchRange];
NSRange rOriginal = [mutStr rangeOfString:#"NSLog("];
if (NSNotFound != rOriginal.location) {
[mutStr replaceOccurrencesOfString:#"NSLog(" withString:#"DSLog(" options:NSCaseInsensitiveSearch range:rOriginal];
}
}
}
return [NSString stringWithString:mutStr];
}
The problem is with the test case:
NSString *str = #"NSLog(#"A string"); NSLog(#"A string2")"
Instead of returning "/*DSLog(#"A string");*/ /*DSLog(#"A string2")*/" it returns: "/*DSLog(#"A string"); NSLog(#"A string2")*/".
The issue is how the Objective-C handles the regular expression. I would expected 2 results in arrayOfAllMatches but instead that I am getting only one. Is there any way to ask Objective-C to stop on the first occurrence of ); ?
The problem is with the regular expression. You are searching for .* inside the parentheses, which causes it to include the first close parenthesis, continue through the second NSLog statement, and go all the way to the final close parentheses.
So what you want to do is something like this:
NSString *regexStr =#"NSLog\\([^\\)]*\\)[\\s]*\\;";
That tells it to include everything inside the parenthesis except for the ) character. Using that regex, I get two matches. (note that you omitted the final ; in your string sample).

How to add a character at start and end of every word in NSString

Suppose i have this:
NSString *temp=#"its me";
Now suppose i want ' " ' in start and end of every word, how can i achieve it to get the result like this:
"its" "me"
Do i have to use regular expressions?
If you have punctuation inside the string, splitting with a space might not be enough.
Use the word boundary \b: it matches both the leading and trailing word boundaries (that is, it will match an empty space right between word and non-word characters and also at the start/end of the string if followed/preceded with a word character.
NSError *error = nil;
NSString *myText = #"its me";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"\\b" options:NSRegularExpressionCaseInsensitive|NSRegularExpressionAnchorsMatchLines error:&error];
NSString *modifiedString = [regex stringByReplacingMatchesInString:myText options:0 range:NSMakeRange(0, [myText length]) withTemplate:#"\""];
NSLog(#"%#", modifiedString); // => "its" "me"
See the IDEONE demo
See more details on the regex syntax in Objective C here.
You can do something like,
NSString *str = #"its me";
NSMutableString *resultStr = [[NSMutableString alloc]init];
NSArray *arr = [str componentsSeparatedByString:#" "];
for (int i = 0; i < arr.count; i++) {
NSString *tempStr = [NSString stringWithFormat:#"\"%#\"",arr[i]];
resultStr = [resultStr stringByAppendingString:[NSString stringWithFormat:#"%# ",tempStr]];
}
NSLog(#"result string is : %#",resultStr);
Hope this will help :)

Filter new line from array of email strings

I'm trying to send emails to a list that I get from a server which is an array of emails whose output is in this format
(
"john#gmail.com\n",
"katebell#gmail.com\n"
"\nakhil#gmail.com",
"mary#gmail.com",
"timcorb\n#gmail.com
)
Now as you can see some emails have newline characters in between and those emails doesnt get sent. I'm trying to find an efficient way to filter out those newlines, my current approach is to loop through all emails and check for newline in each email and if newline exist replace it with a null string. Is there a better way to do this or should I just stick with that? Also Will my current approach cause any issues in any other scenarios?
One way you can try using NSRegularExpression like this below :-
NSArray *array=#[#"john#gmail.com\n",#"katebell#gmail.com\n",#"\nakhil#gmail.com",#"mary#gmail.com",#"timcorb\n#gmail.com"];
NSString *string =[array componentsJoinedByString: #","];
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"\n" options:NSRegularExpressionCaseInsensitive error:nil];
NSString *modifiedString = [regex stringByReplacingMatchesInString:string options:0 range:NSMakeRange(0, [string length]) withTemplate:#""];
NSLog(#"%#",modifiedString);
Output:-
john#gmail.com,katebell#gmail.com,akhil#gmail.com,mary#gmail.com,timcorb#gmail.com
try something like this
NSString *fileName = #"\ntest\n";
fileName = [fileName stringByReplacingOccurrencesOfString:#"\n" withString:#""];
eg.
NSString * str = #"timcorb\n#gmail.com";
str = [str stringByReplacingOccurrencesOfString:#"\n" withString:#""];
NSLog(#"%#",str);
it will Log 2014-01-10 01:01:00.256 demo[26220] timcorb#gmail.com
You can use the below code for replacing characters in a string.
NSString *email = #"\nakhi\nl#gmail.com";
NSString *actualEmail = [email stringByReplacingOccurrencesOfString:#"\n" withString:#""];
NSMutableArray* emailArray = [[NSMutableArray alloc] init];
for (int _index = 0; _index < [yourArray count]; _index++) {
[emailArray addobject:[[yourArray objectAtIndex:_index] stringByReplacingOccurrencesOfString:#"\n" withString:#""]];
}
This will give you your email array

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