How to extract multiple line strings between two keywords using grepwin - grep

Question

Hi I have a directory of files and each file has multiple languages text strings over multiple lines. Using grepwin I would like to extract all the English text strings and save into another text file. Typically in the each file the english text is inside a Switch/Case condition like this:
Default //English
bitmap 8 20 "bmp5/warning.bmp"
Ltext 5 1 11 "USB Device Overload"
LText 85 20 13 "USB"
Ltext 50 33 13 "Device Overload!"
Break
Case _French
bitmap 8 20 "bmp5/warning.bmp"
LTEXT 5 1 11 "Surcharge clé USB!"
LTEXT 45 30 13 "Surcharge clé USB"
Break
Since all the English text is always between 'Default' and 'Break' I want to use those two keywords as the delimeter. Finally all the text between the two keywords needs to be saved out to another text file.
Can anyone help at all.
Thanks guys

Answer 1

Through grep.
$ grep -oPz '(?s)(?<=\n|^)Default\b[^\n]*\n\K.*?(?=\nBreak\b)' file
bitmap 8 20 "bmp5/warning.bmp"
Ltext 5 1 11 "USB Device Overload"
LText 85 20 13 "USB"
Ltext 50 33 13 "Device Overload!"
To save the result to another file, you need to use output redirection operator.
grep -oPz '(?s)(?<=\n|^)Default\b[^\n]*\n\K.*?(?=\nBreak\b)' infile > outfile
From man grep
-P, --perl-regexp PATTERN is a Perl regular expression
-z, --null-data a data line ends in 0 byte, not newline