Cannot load JSON from php/mysql in Swift - ios

Question

I'm trying to build an IOS App for my php/mysql website. The problem is I can't get the following code working with my created JSON output. But the same code works with other APIs like :
http://www.telize.com/geoip
Here is my code:
import UIKit
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
// Playground - noun: a place where people can play
let urlPath = "https://www.example.com/API_OUT.php?API_KEY=785d...e5f5"
let url: NSURL = NSURL(string: urlPath)!
let session = NSURLSession.sharedSession()
let task = session.dataTaskWithURL(url, completionHandler: {data, response, error -> Void in
println("Task completed")
if((error) != nil) {
// If there is an error in the web request, print it to the console
println(error.localizedDescription)
}
var err: NSError?
var jsonResult = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: &err) as NSDictionary
if(err != nil) {
// If there is an error parsing JSON, print it to the console
println("JSON Error \(err!.localizedDescription)")
} else {
println(jsonResult)
}
})
task.resume()
}
}

Answer 1

This JSON is an array, not a dictionary (unlike your original JSON, which was a dictionary). Thus your assignment of this new JSON to a dictionary will fail.
I would suggest (a) use NSArray rather than NSDictionary; and (b) use if let ... syntax rather than just let, to gracefully handle these errors in the future.
Thus, that yields:
var parseError: NSError?
if let jsonResult = NSJSONSerialization.JSONObjectWithData(data, options: nil, error: &parseError) as? NSArray {
println(jsonResult)
} else {
// If there is an error parsing JSON, print it to the console
println("JSON Error \(parseError?.localizedDescription)")
}