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I have a string which is something like:
ABC:Something|Hello World
I want the data after '|' character so I am using regex for it.
sample_str = "ABC:Something|Hello World"
puts sample_str.match(/[^|]*$/)
This works on rubular and returns me "Hello World" as the output, but doesn't work in my ruby code. What am I missing here? I get #<MatchData ""> in Ruby.
UPDATE: Nevermind. If I use the regex and do match on the string it works now. I was doing it other way round i.e. I did (regex).match(string) instead of (string).match(regex).
Thanks for looking!
Using regex seems excessive:
string.split('|').last
Below regex should help you.
^[\S\s]+?\|([\w\s]+)$
Dont forget to select global and multiline options.
Look at the regex demo here.
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I'm using Ruby 2.4. I have a string with letters and numbers, something like
str = "123abc234abb"
How do I find all the letters occurring after the last number in the string? For example, if I applied the function to the above, it would yield
abb
You could use a positive lookbehind:
"123abc234abb"[/(?<=\d)?[a-zA-Z]+\z/]
#=> "abb"
Try this
str.rpartition(/\d+/).last
How does this work?
rpartition splits the string into three parts, using reverse matching
last picks the post-match part from the three results
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I am new to ruby and would like to create a simple method to convert a series of unix timestamps into datetime format. Currently, what I am doing (in console on my terminal is)
def foo(x)
Time.at(:x)
end
Then I would pass in foo(1315922016). But I get an error
Can't convert Symbol into an exact number
How can I revise my ruby code to allow it to accept an integer which then is put into Time.at method for conversion?
This should be simple call as:
def foo(x)
Time.at(x)
end
Hope that helps!
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This is the best reduced case of I am seeing
NSString * test = #"??( ";
NSLog(#"'%#'", test);
console> '['
I have a work around
NSString * test = #"\x3f\x3f(";
NSLog(#"'%#",test);
console> '??('
It seems like this is likely caused by string interpolation or similar process in the NSString object vivification. I'm posting this question for two reasons.
1) anyone happen to know what is actually causing this?
2) I didn't find anything on this 'feature' of NSString and it took me an hour to track down the bug, so this is just a bread crumb for future programmers. Using the hex code for the character was the work around.
NSlog("'%#'", test); is syntactically incorrect. How are you compiling it with this syntax error?
If I change it to NSLog(#"'%#'", test);, it works correctly (note the string literal denoting # and the uppercase L in NSLog).
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In ruby i have a string like this:
str= 43,69 €
Is possible with a regex obtain 43,69 ?
I have tried with:
/\d+(?:\.\d+)?/
but the output is incorrect: 43.0
This should work
/\d+(?:[.,]\d+)?/
The [.,] part matches decimal separator for a dot or a comma. If you are sure thet decimal separator will be a comma, you can use this:
/\d+(?:,\d+)?/
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Closed 9 years ago.
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There is the following regular expression to describe regular expression:
validates :phone, format: { with: /\A(\+7|8)[0-9]{10}\z/ }
'89277777777' must match this expression, '+79277777777' must too. But I have got 'invalid phone' message always. How can I fix it? Thanks.
If all you want to do is a simple way to validate an international number, which may or may not start with a + followed by either a 7 or an 8, followed by 10 more digits, then this regex should do the trick:
\A\+?[78]\d{10}\z
Debuggex Demo
If my assumptions are incorrect, let me know in the comments and we'll work on a better solution.
Note: don't forget to surround the regex with // -- I didn't do that here due to the use of Debuggex