Open an URL in UIWebView - ios

Question

I have an important question. I'm creating an iPhone app.
I have an UIWebView (https://www.google.de/) with goBack, goForward and reload.
Now, I want a Button e.g. Bar Button Item named Home or Homepage, to open an URL (https://www.google.de/) in this WebView, to go back to the homepage.
How can I do this? How can I "say" the button to open the link in my WebView? I ask for answer.
// ViewController.h
#import <UIKit/UIKit.h>
#interface ViewController : UIViewController
#property (nonatomic, strong) IBOutlet UIWebView *site ;
#end
// ViewController.m
#import "ViewController.h"
#interface ViewController ()
#end
#implementation ViewController
-(IBAction)refresh:(id)sender; {
NSURL *url=[NSURL URLWithString: #"https://www.google.de/"]; NSURLRequest * requestURL=[NSURLRequest requestWithURL:url]; [_site loadRequest:requestURL];
}
- (void)viewDidLoad {
[self refresh:self];
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
}
- (void)didReceiveMemoryWarning {
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}
#end

Answer 1

UIWebView has methods, goBack and goForward. You can make actions and bind it with your bar buttons to go back and forward whenever you want.
- (IBAction)goBack:(id)sender {
[_site goBack];
}
- (IBAction)goForward:(id)sender {
[_site goForward];
}
- (IBAction)goHomepage:(id)sender {
NSURL *url=[NSURL URLWithString: #"https://www.google.de/"];
NSURLRequest *requestURL=[NSURLRequest requestWithURL:url];
[_site loadRequest:requestURL];
}
To help you more, here's a tutorial on this, and if you don't want to read that tutorial, you can check their source code from here !