Tweetbot URL Scheme not opening user - ios

Question

I've been trying to get Tweetbot to open a user account when a table row is tapped by the user. However, although Tweetbot opens, it doesn't show the user account. I've been using the Tweetbot URL Scheme page as a reference.
Below is my code:
if (indexPath.row == 1) {
// Removed the actual username
self.destViewURL = #"http://twitter.com/dummyusername";
self.destViewTitle = #"Twitter";
// URLs to try
NSURL *twitterURL = [NSURL URLWithString:#"twitter://user?screen_name= dummyusername"];
NSURL *tweetbotURL = [NSURL URLWithString:#"tweetbot://dummyusername/timeline"];
// Check if Tweetbot is available to open it
if ([[UIApplication sharedApplication] canOpenURL:tweetbotURL]) {
[[UIApplication sharedApplication] openURL:tweetbotURL];
}
else {
// Check if Twitter is available to open it
if ([[UIApplication sharedApplication] canOpenURL:twitterURL]) {
[[UIApplication sharedApplication] openURL:twitterURL];
}
// Otherwise open it in the web view
else {
[self performSegueWithIdentifier:#"showWebView" sender:nil];
}

Answer 1

The URL schemes page for Tweetbot 3 is here
All of the supported URLs begin with tweetbot://<screenname>, which suggests that you need to know the user's existing twitter screen name to link to a profile.
However, my testing has shown that you could link directly to a profile by using the same value for tweetbot://<screenname>/user_profile/<profile_screenname>
Swift e.g.
/* Tweetbot app precedence */
if let tweetbotURL = NSURL(string: "tweetbot://dummyusername/user_profile/dummyusername") {
if UIApplication.sharedApplication().canOpenURL(tweetbotURL) {
UIApplication.sharedApplication().openURL(tweetbotURL)
return
}
}
/* Twitter app fallback */
if let twitterURL = NSURL(string: "twitter:///user?screen_name= dummyusername") {
if UIApplication.sharedApplication().canOpenURL(twitterURL) {
UIApplication.sharedApplication().openURL(twitterURL)
return
}
}
/* Safari fallback */
if let webURL = NSURL(string: "http://www.twitter.com/dummyusername") {
if UIApplication.sharedApplication().canOpenURL(webURL) {
UIApplication.sharedApplication().openURL(webURL)
}
}