IQueryable to IEnumerable - asp.net-mvc

Question

public IEnumerable<Temp_Order> Get_Temp(string id)
{
//List<Temp_Order> data = new List<Temp_Order>();
IEnumerable<Temp_Order> data = db.Temp_Order
.Join(db.Items,
t_id => t_id.ItemId,
I_id => I_id.ItemId,
(t_id, I_id) => new { t_id.Quantity, I_id.ItemName })
.Where(x => x.ItemName == id);
return data;
}
In this method I want IEnumerable<Temp_Order>. So I will use this in controller and return to the view.
I'm getting this error:
Cannot implicitly convert type 'System.Linq.IQueryable' to 'System.Collections.Generic.IEnumerable'. An explicit conversion exists (are you missing a cast?) E:\WORK\Projects\RMS_Live\RMS_Live\Models\Order.cs

Answer 1

The Join is converting your query to an IEnumerable of an anonymous type. Add a Select on the end to cast is back to Temp_Order:
public IEnumerable<Temp_Order> Get_Temp(string id)
{
//List<Temp_Order> data = new List<Temp_Order>();
IEnumerable<Temp_Order> data = db.Temp_Order
.Join(db.Items, t_id => t_id.ItemId, I_id => I_id.ItemId, (t_id, I_id) => new { t_id.Quantity, I_id.ItemName })
.Where(x => x.ItemName == id)
.Select(a => new Temp_Order
{
ItemName = a.ItemName,
Property2 = a.Property2,
//snip
});
return data;
}
EDIT:
You indicate in the comments that you want all properties from both Temp_Order and Item which means you need another class. You can get away without creating another class, but it's much simpler in the long run. So first make your class, 2 ways spring to mind, you either replicate all the properties you need or just return the 2 objects, I'll use the latter:
public class OrderItem
{
public Temp_Order Temp_Order { get; set; }
public Item Item { get; set; }
}
Now your function becomes this:
public IEnumerable<OrderItem> Get_Temp(string id)
{
IEnumerable<OrderItem> data = db.Temp_Order
.Join(db.Items,
t_id => t_id.ItemId,
I_id => I_id.ItemId,
(t_id, I_id) => new OrderItem
{
Temp_Order = t_id,
Item = I_id
})
.Where(x => x.ItemName == id);
return data;
}
And in your view, make sure you set the model type to IEnumerable<OrderItem> and you can access all the properties like this:
#Model.Temp_Order.ItemName