i m using jsoup Application and trying to get url of web pages. i got urls of web page. i m trying to get only image urls via url parsing
but when sending request to url i got this error
" The constructor URL(Elements) is undefined "
my question is how can i pass urls that i got from jsoup library
here is my code
' public static void main(String[] args) throws IOException {
Validate.isTrue(args.length == 1, "usage: supply url to fetch");
String url = args[0];
print("Fetching %s...", url);
Document doc = Jsoup.connect(url).get();
Elements links = doc.select("a[href]");
Elements media = doc.select("[src]");
Elements imports = doc.select("link[href]");
'
and using
'Elements imagepath = doc.select("[src]");'
and passing this Lement into url parsing function
URL url = new URL(imagepath);
can anyone help me to figure it out how to get url parsing function works
thanks in advance
The reason you get that exception is because you pass Elements to the URL constructor - the Elements is just the specialization of List<Element>. This means you probably have more than one image assigned to imagepath variable. If you would like to construct the URL objects from the scraped images, consider this code sample:
Elements images = document.select("img");
for (Element element : images) {
System.out.println(element.attr("abs:src"));
}
This should help you making progress with your application. I would love to answer any further question you might have.
Related
I want to access and return a resource image from a DLL /connected project.
(Its a file, with build action of Resource). It is not listed in properties/resource as there are hundreds of them in the folder.
The idea is that I can call an image controller.
public ImageResult Display(string resourcePath){
Uri uri = new Uri("pack://application:,,,/ProjectName;component/Images/Vectors/" + resourcePath, UriKind.Absolute);
// What goes here??
}
The problem is i dont know how to turn the URI into an image, in MVC5.
I want to be able to call it from the view. using the url property of the <img> tag
I think you could try WebClient.DownloadData() method to download the image as byte array from specified URI, then convert it to Base64 format with Convert.ToBase64String() and display it on <img> tag using a string property in the viewmodel as src attribute value, below is an example to display the image:
Viewmodel Example
public class ViewModel
{
// other properties
// used to pass image into src attribute of img tag
public string ImageData { get; set; }
}
Controller Action
public ActionResult Display(string resourcePath)
{
Uri uri = new Uri("pack://application:,,,/ProjectName;component/Images/Vectors/" + resourcePath, UriKind.Absolute);
using (var wc = new System.Net.WebClient())
{
// download URI resource as byte array
byte[] image = wc.DownloadData(uri);
// get image extension
string path = string.Format("{0}{1}{2}{3}", uri.Scheme, Uri.SchemeDelimiter, uri.Authority, uri.AbsolutePath);
string extension = System.IO.Path.GetExtension(path).Replace(".", "");
// assign image to viewmodel property as Base64 string format
var model = new ViewModel();
model.ImageData = string.Format("data:image/{0};base64,{1}", extension, Convert.ToBase64String(image));
return View(model);
}
}
View
#model ViewModel
<img src="#Model.ImageData" ... />
Additional note:
If you already know the extension from the resource URI, you could use it directly instead of using Path.GetExtension, here is an example for JPG format:
model.ImageData = string.Format("data:image/jpg;base64,{0}", Convert.ToBase64String(image));
Related issues:
Image to byte array from a url
MVC How to display a byte array image from model
Be sure to register the pack:// scheme as this won't automatically be registered in an MVC app as it is in a WPF app.
In this example code, Blarn0 is a public property in my model class to ensure that the access to the PackUriHelper.UriSchemePack property isn't optimized away when the code is published in Release configuration. I'm sure one can use discards for this very purpose in later versions of C#.
const string scheme = "pack";
if (!UriParser.IsKnownScheme(scheme))
Blarn0 = PackUriHelper.UriSchemePack;
I'm trying to opening the URL that has the pdf document in the new tab. If I click on 1000 anchor tags then it will display the url in new tab like http://sivls100.eskom.co.za:8080/finalnewnrs/Document.do?method=dt&fn=1000.pdf. But if any person has this URL in the network can see the pdf file. I would like to show the pdf file to authenticated users.I did some investigation and found that we can achieve this by setting authenticated user in attribute like setAttribute and get Attribute. I did some code and it works as long as session valid. My session timeout is 30 min.It will not work after 30 min.
Code:
public ActionForward dt(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws Exception {
Object obj = request.getSession().getAttribute("userDetail");
String target = new String(SUCCESS);
if (obj == null) {
target = new String(FAILURE);
} else {
String filename = request.getParameter("fn");
request.setAttribute("filename", "upload/dt/" + filename);
}
return mapping.findForward(target);
}
Thank you for any help or atleast for the better design.
Is there a function to do urlencoding in Dart? I am doing a AJAX call using XMLHttpRequest object and I need the url to be url encoded.
I did a search on dartlang.org, but it didn't turn up any results.
var uri = 'http://example.org/api?foo=some message';
var encoded = Uri.encodeFull(uri);
assert(encoded == 'http://example.org/api?foo=some%20message');
var decoded = Uri.decodeFull(encoded);
assert(uri == decoded);
http://www.dartlang.org/docs/dart-up-and-running/contents/ch03.html#ch03-uri
Update: There is now support for encode/decode URI in the Dart Uri class
Dart's URI code is placed in a separate library called dart:uri (so it can be shared between both dart:html and dart:io). It looks like it currently does not include a urlencode function so your best alternative, for now, is probably to use this Dart implementation of JavaScript's encodeUriComponent.
Uri.encodeComponent(url); // To encode url
Uri.decodeComponent(encodedUrl); // To decode url
I wrote this small function to convert a Map into a URL encoded string, which may be what you're looking for.
String encodeMap(Map data) {
return data.keys.map((key) => "${Uri.encodeComponent(key)}=${Uri.encodeComponent(data[key])}").join("&");
}
I dont' think there is yet. Check out http://unpythonic.blogspot.com/2011/11/oauth20-and-jsonp-with-dartin-web.html and the encodeComponent method.
Note, it's lacking some characters too, it needs to be expanded. Dart really should have this built in and easy to get to. It may have it in fact, but I didn't find it.
Safe Url Encoding in flutter
Ex.
String url = 'http://example.org/';
String postDataKey = "requestParam="
String postData = 'hdfhghdf+fdfbjdfjjndf'
In Case of get request :
Uri.encodeComponent(url+postDataKey+postData);
In Case of Post Data Request use flutter_inappwebview library
var data = postDataKey + Uri.encodeComponent(postData);
webViewController.postUrl(url: Uri.parse(url), postData: utf8.encode(data));
Uri.encodeComponent() is correct, Uri.encodeFull() has a bug, see below example:
void main() {
print('$text\n');
var coded = Uri.encodeFull(text);
print(coded);
print('\n');
coded = Uri.encodeComponent(text);
print(coded);
}
var text = '#2020-02-29T142022Z_1523651918_RC2EAF9OOHDB_RT.jpg';
Can any one please help me how to get the real file name from Struts2 MultiPartRequestWrapper.
MultiPartRequestWrapper multiWrapper =
(MultiPartRequestWrapper) ServletActionContext.getRequest();
Enumeration fileParameterNames = multiWrapper.getFileParameterNames();
if(fileParameterNames.hasMoreElements()){
String inputValue = (String) fileParameterNames.nextElement();
File[] files = multiWrapper.getFiles(inputValue);
for (File cf : files) {
System.out.println(cf.getParentFile().getName());
System.out.println("cf is : " + cf.getName());
System.out.println("cf is : " + cf.toURI().getPath());
File.createTempFile(cf.getName(),"");
}
}
I can see original file name, type, size from "fileParameterNames" but when get file I can only see tempfile with upload_xxxxxxxxx.tmp.
How can I get original file name from the File.
Advance thanks for your help.
Why are you doing all that?
See the file upload FAQ and details pages. All you need to do is provide the appropriate action properties:
public void setUploaded(File myDoc);
public void setUploadedContentType(String contentType);
public void setUploadedFileName(String filename);
and use the file upload interceptor, which is included in the default stack.
Note that different browsers send different information; some only send the original filename, while some send the complete path.
You have to use : multiWrapper.getFileNames("file")[0]
Where "file" is the name of the file control.
var fd = new FormData();
fd.append('file', files[i]);
I want to generate complete Url (with domain name etc) of any file in MVC. Example: A .jpg file or an exe file.
Example: If I give "~/images/abc.jpg" it should return "http://www.mywebsite.com/images/abc.jpg"
I am aware of the Url.Action overload that takes the protocol as a parameter. But Url.Action can be used only for Actions.
I want something like Url.Content function that takes protocol as a parameter.
Do you know if any method to get complete url of any file?
I have tried: VirtualPathUtility.ToAbsolute, ResolveClientUrl, ResolveUrl but all of these don't seem to work.
new Uri(Request.Url, Url.Content("~/images/image1.gif"))
You can use the following code to replace "~/" to absoulute URL.
System.Web.VirtualPathUtility.ToAbsolute("~/")
Edit:
First you need to define a method.
public static string ResolveServerUrl(string serverUrl, bool forceHttps)
{
if (serverUrl.IndexOf("://") > -1)
return serverUrl;
string newUrl = serverUrl;
Uri originalUri = System.Web.HttpContext.Current.Request.Url;
newUrl = (forceHttps ? "https" : originalUri.Scheme) +
"://" + originalUri.Authority + newUrl;
return newUrl;
}
Now call this method will return the complete absolure url.
ResolveServerUrl(VirtualPathUtility.ToAbsolute("~/images/image1.gif"),false))
The output will be http://www.yourdomainname.com/images/image1.gif
Try use this.
Url.Action("~/images/image1.gif", "/", null, Request.Url.Scheme)