console.log not showing in Parse Logs page - ios

Question

In the below cloud code i would like to get a feedback of the saveAll function but after calling the code from my client in the parse Logs page i can only see:
I2014-10-08T15:28:32.930Z] v249: Ran cloud function acceptMeetingBis for user dyGu143Xho with:
Input: {"meetingId":"bUSTGNhOer"}
Result: Meeting accepted
Here is my cloud code:
Parse.Cloud.define("acceptMeetingBis", function(request, response) {
var userAcceptingTheMeeting = request.user;
var meetingId = request.params.meetingId;
var changedObjects = [];
var queryForMeeting = new Parse.Query("MeetingObject");
queryForMeeting.equalTo("objectId", meetingId);
queryForMeeting.first({
success: function(meeting) {
var userCreatorOfMeeting = meeting.get("user");
userAcceptingTheMeeting.increment("acceptedMeetings", +1);
changedObjects.push(userAcceptingTheMeeting);
meeting.add("participantsObjectId", userAcceptingTheMeeting.id);
if (meeting.get("participantsObjectId").length === meeting.get("meetingNumberOfPersons")) {
meeting.set("isAvailable", false);
}
changedObjects.push(meeting);
Parse.Object.saveAll(changedObjects, {
success: function(objects) {
console.log("Successfully saved objects"); //this line doesn't show up
response.success("objects saved");
},
error: function(error) {
// An error occurred while saving one of the objects.
response.error(error);
}
});
//future query and push notifications will go here
response.success("Meeting accepted");
},
error: function() {
response.error("Failed to accept the meeting");
}
});
});
I will also need to add some push and another nested query after the saveAll() but before doing/trying that i would like to know if this is the right method to use or if i have to build the code in a different way. I'm new to javascript and honestly i'm struggling to understand some concepts, like promises. Any help would be much appreciated.

Answer 1

Your call to
Parse.Object.saveAll
is asynchronous, and you call
response.success("Meeting accepted")
immediately after making the asynchronous call, which ends the cloud code running of the method. If you simply replace the
response.success("objects saved")
with
response.success("Meeting accepted")
you should get what you want.
I didn't see the rest of your question about promises. You should check out Parse's documentation on chaining promises, which is what you want here.
Essentially, here's what you'll want to do:
Parse.Cloud.define("acceptMeetingBis", function(request, response) {
var userAcceptingTheMeeting = request.user;
var meetingId = request.params.meetingId;
var changedObjects = [];
var meetingToAccept;
var queryForMeeting = new Parse.Query("MeetingObject");
queryForMeeting.get(meetingId).then(function(meeting) {
meetingToAccept = meeting;
var userCreatorOfMeeting = meeting.get("user");
userAcceptingTheMeeting.increment("acceptedMeetings", +1);
return userAcceptingTheMeeting.save();
}).then(function(userWhoAcceptedMeetingNowSaved) {
meetingToAccept.add("participantsObjectId", userWhoAcceptedMeetingNowSaved.id);
if (meetingToAccept.get("participantsObjectId").length === meetingToAccept.get("meetingNumberOfPersons")) {
meetingToAccept.set("isAvailable", false);
}
return meetingToAccept.save();
}).then(function(savedMeeting) {
response.success("Meeting accepted");
}, function(error) {
response.error("Failed to accept the meeting");
});
});
For each asynchronous action you want to do, perform it at the end of one of the .then functions and return the result (it returns a promise). Keep adding .then functions until you're done all the work you want to do, at which point call response.success.