Removing characters from a string in Swift - ios

Question

I have a function:
func IphoneName() -> String
{
let device = UIDevice.currentDevice().name
return device
}
Which returns the name of the iPhone (simple). I need to remove the "'s Iphone" from the end. I have been reading about changing it to NSString and use ranges, but I am a bit lost!

Answer 1

What about this:
extension String {
func removeCharsFromEnd(count:Int) -> String{
let stringLength = countElements(self)
let substringIndex = (stringLength < count) ? 0 : stringLength - count
return self.substringToIndex(advance(self.startIndex, substringIndex))
}
func length() -> Int {
return countElements(self)
}
}
Test:
var deviceName:String = "Mike's Iphone"
let newName = deviceName.removeCharsFromEnd("'s Iphone".length()) // Mike
But if you want replace method use stringByReplacingOccurrencesOfString as #Kirsteins posted:
let newName2 = deviceName.stringByReplacingOccurrencesOfString(
"'s Iphone",
withString: "",
options: .allZeros, // or just nil
range: nil)

Answer 2

You don't have to work with ranges in this case. You can use:
var device = UIDevice.currentDevice().name
device = device.stringByReplacingOccurrencesOfString("s Iphone", withString: "", options: .allZeros, range: nil)

Answer 3

In Swift3:
var device = UIDevice.currentDevice().name
device = device.replacingOccurrencesOfString("s Iphone", withString: "")

Answer 4

Swift 4 Code
//Add String extension
extension String {
func removeCharsFromEnd(count:Int) -> String{
let stringLength = self.count
let substringIndex = (stringLength < count) ? 0 : stringLength - count
let index: String.Index = self.index(self.startIndex, offsetBy: substringIndex)
return String(self[..<index])
}
func length() -> Int {
return self.count
}
}
//Use string function like
let deviceName:String = "Mike's Iphone"
let newName = deviceName.removeCharsFromEnd(count: "'s Iphone".length())
print(newName)// Mike