We have a large storyboard, and overtime we keep adding to it. I see some items are positioned at a negative x or y position. Does that have any performance issues? Should I move everything down and right or is it safe to ignore?
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In GeoGebra, can you plot the abscissa (xAxis) vertically and the ordinate (yAxis) horizontally?
I need this, since I like to visualise an inverse. Since I also like to visualise an Area between different values, I need an IntegralBetween for an interval on y's (so re-interpreting x as y does not work). In addition the function is very tall, so I like to have the layout rotated by 90 degrees.
In GeoGebra's 2D view x always refers to the horizontal and y to the vertical axes. You can however shade the area between two functions in y using inequalities with zero line thickness
I am having issues with my implementation of CorePlot. I have a subview in my UIViewController than contains the chart. Most of the data shows up fine but no increments / values are showing up on the y axis.
This is what I am seeing now:
If I shift the x axis start point by subtracting 10 (to better see the left half of the chart) I see this:
For the record, I do not have any values outside of the (positive x, positive y) quadrant on the chart and have logged out my data to verify this. Any input / advice would be appreciated, thank you!
http://www.raywenderlich.com/13271/how-to-draw-graphs-with-core-plot-part-2
This guy does a great job explaining that about halfway down... search for "You're Getting There!" to find exactly where he talks about the weird lines in the Y axis.
Hope this helps!
Set the leftPadding on the graph.plotAreaFrame to leave room for the axis labels at the left side of the graph.
The smeared y-axis is caused by too many tick marks and labels—they overlap and become illegible and negatively impact drawing performance. You need to adjust the labeling parameters to reduce the number of ticks and labels. By default, the axis draws major tick marks and labels one unit apart. The properties that need to be changed depend on the labeling policy you want to use.
Depending on where the anchorPoint is with UIAttachmentBehavior, the view can be quite rotated, so it's in more of a diamond shape than a square. In these situations, where it's rotated say 90°, how do I find what the lowest or highest point of this UIView is (in relation to the window)?
It's easy enough when the UIView is a (non-rotated) square, as I can just use CGRectGetMaxY (or min) and the x value doesn't matter, and then use convertPoint, but with the rotation the x value seems to have a real importance, as if I choose maxX, it will tell me the bottom right's point, while minX will give me the bottom left's.
I just want the lowest point that exists in the UIView. How do I get this?
EDIT: Here's some code showing how I'm attempting it currently:
CGPoint lowestPoint = CGPointMake(CGRectGetMinX(weakSelf.imageView.bounds), CGRectGetMaxY(weakSelf.imageView.bounds));
CGPoint convertedPoint = [weakSelf.imageView convertPoint:lowestPoint toView:nil];
The tracking of convertedPoint's y value completely changes depending on what I supply for the x value in lowestPoint's CGPointMake.
The view's frame is its bounding box. Normally you should be careful about using the frame of a transformed view, which is precisely what a rotated-by-UIKit-Dynamics view is. But it does give the info you are after.
I often do a screen capture and paste it into Fireworks.
I always have to change the x and y values to 0 because they're always negative.
I find this happens if the image is larger than my window. If you make sure you're zoomed out until you can see the whole canvas first, the item should paste into the correct position.
In my existing app, I had 5 of my UIView derivatives (labels and buttons) laid up horizontally, i.e. on 0 degrees. They were all aligned on their left edges (so that button1.frame.origin.x = button2.frame.origin.x and so on.)
Now, for update purpose, I need to rotate all 5 of them, by 9 degrees anticlockwise.
I achieve the the rotation easily.
But I can't get how adjust their left edges so that they would all be aligned again after rotation.
The requirement, in summary, is this: The first control need to remain fixed (acting as pivot point) - the 4 others need to move right in order to maintain left alignment after rotation.
I tried putting incremental x value to each of the last 4 controls (keeping the pivot x fixed) but so far don't achieve exact alignment.
After rotation, it looks like all of them are center aligned, instead of left aligned which I really want.
I know what I really want, but just looking for a smarter way so that it won't be ugly like it is now.
Read about layout constraints. That will really help you in many ways. In layout constraints the concept is very simple like
Control1.attribute = Control2.attribute + C
So you can literally program each controls attributes and achieve a fine grain control. You can then code it such that all the controls X is same as other controls X, they are all same distance from another control etc.
You can have multiple layout constraints and the system will try to satisfy as many as possible.
But the only thing is that this is possible in iOS 6.0.