How to find embedded documents with nil field values in Mongoid? - ruby-on-rails

Is there a way to find nil values inside the embedded documents in Mongoid?
Given I have these models:
class Record
include Mongoid::Document
embeds_many :locations
end
class Location
include Mongoid::Document
embedded_in :record
field :special_id, type: String
end
I can find records given a specific special_id of location model
Record.where('locations.special_id' => '123')
But, if I wanted to get all records with nil special_id in locations, this works but returns all of the records.
Record.where('locations.special_id.eq' => nil)
This one returns 0 results:
Record.where('locations.special_id.exists' => false)
Thanks

embeds_many just sets up an array of hashes inside MongoDB so the usual dot-notation should work:
Record.where('locations.special_id' => nil)
# ------------^^^^^^^^^^^^^^^^^^^^ just the usual JavaScript-style path
The .eq and .exists notations are generally used as methods on symbols as short forms. For example:
where(:'locations.special_id'.ne => nil)
would be a shorthand for:
where('locations.special_id' => { :$ne => nil })
If you try to embed the operator in the field name string then MongoDB will just think you're trying to use another component in the path.

Related

Mongoid greater than date or not nil

I have two models
class Conversation
include Mongoid::Document
field :last_moderated_at, type: DateTime
has_many :messages
end
class Message
include Mongoid::Document
include Mongoid::Timestamps
end
I want to get the list of all messages that were created after the moderation date, or all of them if the moderation date is nil
I had expected the following to work
conversation.messages.where(
:created_at.gte => conversation.last_moderated_at
)
But apparently the comparison with nil fails (when last_moderated_at == nil)
Do I have no choice but to use an if/else or is there a mongoDB operator of type greater than that also works when compared to nil dates ?
EDIT : A simpler example : Conversation.where(:created_at.gte => nil).count will always return 0
The syntax is correct. It does work on Mongoid version 6, at least.

MongoDB conditional aggregate query on a HABTM relationship (Mongoid, RoR)?

Rails 4.2.5, Mongoid 5.1.0
I have three models - Mailbox, Communication, and Message.
mailbox.rb
class Mailbox
include Mongoid::Document
belongs_to :user
has_many :communications
end
communication.rb
class Communication
include Mongoid::Document
include Mongoid::Timestamps
include AASM
belongs_to :mailbox
has_and_belongs_to_many :messages, autosave: true
field :read_at, type: DateTime
field :box, type: String
field :touched_at, type: DateTime
field :import_thread_id, type: Integer
scope :inbox, -> { where(:box => 'inbox') }
end
message.rb
class Message
include Mongoid::Document
include Mongoid::Timestamps
attr_accessor :communication_id
has_and_belongs_to_many :communications, autosave: true
belongs_to :from_user, class_name: 'User'
belongs_to :to_user, class_name: 'User'
field :subject, type: String
field :body, type: String
field :sent_at, type: DateTime
end
I'm using the authentication gem devise, which gives access to the current_user helper, which points at the current user logged in.
I have built a query for a controller that satisfied the following conditions:
Get the current_user's mailbox, whose communication's are filtered by the box field, where box == 'inbox'.
It was constructed like this (and is working):
current_user.mailbox.communications.where(:box => 'inbox')
My issue arrises when I try to build upon this query. I wish to chain queries so that I only obtain messages whose last message is not from the current_user. I am aware of the .last method, which returns the most recent record. I have come up with the following query but cannot understand what would need to be adjusted in order to make it work:
current_user.mailbox.communications.where(:box => 'inbox').where(:messages.last.from_user => {'$ne' => current_user})
This query produces the following result:
undefined method 'from_user' for #<Origin::Key:0x007fd2295ff6d8>
I am currently able to accomplish this by doing the following, which I know is very inefficient and want to change immediately:
mb = current_user.mailbox.communications.inbox
comms = mb.reject {|c| c.messages.last.from_user == current_user}
I wish to move this logic from ruby to the actual database query. Thank you in advance to anyone who assists me with this, and please let me know if anymore information is helpful here.
Ok, so what's happening here is kind of messy, and has to do with how smart Mongoid is actually able to be when doing associations.
Specifically how queries are constructed when 'crossing' between two associations.
In the case of your first query:
current_user.mailbox.communications.where(:box => 'inbox')
That's cool with mongoid, because that actually just desugars into really 2 db calls:
Get the current mailbox for the user
Mongoid builds a criteria directly against the communication collection, with a where statement saying: use the mailbox id from item 1, and filter to box = inbox.
Now when we get to your next query,
current_user.mailbox.communications.where(:box => 'inbox').where(:messages.last.from_user => {'$ne' => current_user})
Is when Mongoid starts to be confused.
Here's the main issue: When you use 'where' you are querying the collection you are on. You won't cross associations.
What the where(:messages.last.from_user => {'$ne' => current_user}) is actually doing is not checking the messages association. What Mongoid is actually doing is searching the communication document for a property that would have a JSON path similar to: communication['messages']['last']['from_user'].
Now that you know why, you can get at what you want, but it's going to require a little more sweat than the equivalent ActiveRecord work.
Here's more of the way you can get at what you want:
user_id = current_user.id
communication_ids = current_user.mailbox.communications.where(:box => 'inbox').pluck(:_id)
# We're going to need to work around the fact there is no 'group by' in
# Mongoid, so there's really no way to get the 'last' entry in a set
messages_for_communications = Messages.where(:communications_ids => {"$in" => communications_ids}).pluck(
[:_id, :communications_ids, :from_user_id, :sent_at]
)
# Now that we've got a hash, we need to expand it per-communication,
# And we will throw out communications that don't involve the user
messages_with_communication_ids = messages_for_communications.flat_map do |mesg|
message_set = []
mesg["communications_ids"].each do |c_id|
if communication_ids.include?(c_id)
message_set << ({:id => mesg["_id"],
:communication_id => c_id,
:from_user => mesg["from_user_id"],
:sent_at => mesg["sent_at"]})
end
message_set
end
# Group by communication_id
grouped_messages = messages_with_communication_ids.group_by { |msg| mesg[:communication_id] }
communications_and_message_ids = {}
grouped_messages.each_pair do |k,v|
sorted_messages = v.sort_by { |msg| msg[:sent_at] }
if sorted_messages.last[:from_user] != user_id
communications_and_message_ids[k] = sorted_messages.last[:id]
end
end
# This is now a hash of {:communication_id => :last_message_id}
communications_and_message_ids
I'm not sure my code is 100% (you probably need to check the field names in the documents to make sure I'm searching through the right ones), but I think you get the general pattern.

Extract Mongoid documents based on the DateTime of their last has_many relations?

I have a bunch of orders, and some of them have order_confirmations.
1: I wish to extract a list of orders based on the DateTime of its last order_confirmation. This is my failed attempt (returns 0 records):
Order.where(:order_confirmations.exists => true).desc("order_confirmations.last.datetime")
2: I wish to extract a list of orders where the last order_confirmation is between 5 and 10 days old. This is my failed attempt (returns 0 results):
Order.lte("order_confirmations.last.datetime" => 5.days.ago).gte("order_confirmations.last.datetime" => 10.days.ago)
My relations:
class Order
include Mongoid::Document
has_many :order_confirmations
end
class OrderConfirmation
include Mongoid::Document
field :datetime, type: DateTime
belongs_to :order
end
With referenced relationships, you cannot directly query referenced documents.
That said, you would probably want to query order confirmations first, and then select the orders like this:
OrderConfirmation.between(datetime: 10.days.ago..5.days.ago)
.distinct(:order_id).map { |id| Order.find(id) }
If you had confirmations embedded into the order, like this
class Order
include Mongoid::Document
embeds_many :order_confirmations
end
class OrderConfirmation
include Mongoid::Document
field :datetime, type: DateTime
embedded_in :order
end
Then you could query order confirmation inside order query with $elemMatch:
Order.elem_match(order_confirmations:
{ :datetime.gte => 10.days.ago, :datetime.lte => 5.days.ago })
Regarding your first question, I don't think it's possible to do that with just MongoDB queries, so you could do something like
# if you go embedded rels
Order.all.map { |o| o.order_confirmations.desc(:datetime).first }
.sort_by(&:datetime).map(&:order)
# if you stay on referenced rels
OrderConfirmation.desc(:datetime).group_by(&:order)
.map { |k, v| v.first }.map(&:order)
Check out the elemMatch function.
where('$elemMatch' => [{...}]
I do believe there is a bug in mongoid though related to elemMatch and comparing dates, not sure if its been fixed.

Mongoid and querying for embedded locations?

I have a model along the lines of:
class City
include Mongoid::Document
field :name
embeds_many :stores
index [["stores.location", Mongoid::GEO2D]]
end
class Store
include Mongoid::Document
field :name
field :location, :type => Array
embedded_in :cities, :inverse_of => :stores
end
Then I tried calling something like City.stores.near(#location).
I want to query the City collection to return all cities that have at least 1 Store in a nearby location. How should I set up the index? What would be the fastest call?
I read the Mongoid documentation with using index [[:location, Mongo::GEO2D]] but I am not sure how this applies to an embedded document, or how to only fetch the City and not all the Stop documents.
Mike,
The feature you are requesting is called multi-location documents. It is not supported in the current stable release 1.8.2. This is available only from version 1.9.1.
And Querying is straightforward when use mongoid, its like this
City.near("stores.location" => #location)
And be careful when using near queries in multi-location documents, because the same document may be returned multiple times, since $near queries return ordered results by distance. You can read more about this here.
Use $within query instead to get the correct results
Same query written using $within and $centerSphere
EARTH_RADIUS = 6371
distance = 5
City.where("stores.location" => {"$within" => {"$centerSphere" => [#location, (distance.fdiv EARTH_RADIUS)]}})

Querying embedded objects in Mongoid/rails 3 ("Lower than", Min operators and sorting)

I am using rails 3 with mongoid.
I have a collection of Stocks with an embedded collection of Prices :
class Stock
include Mongoid::Document
field :name, :type => String
field :code, :type => Integer
embeds_many :prices
class Price
include Mongoid::Document
field :date, :type => DateTime
field :value, :type => Float
embedded_in :stock, :inverse_of => :prices
I would like to get the stocks whose the minimum price since a given date is lower than a given price p, and then be able to sort the prices for each stock.
But it looks like Mongodb does not allow to do it.
Because this will not work:
#stocks = Stock.Where(:prices.value.lt => p)
Also, it seems that mongoDB can not sort embedded objects.
So, is there an alternative in order to accomplish this task ?
Maybe i should put everything in one collection so that i could easily run the following query:
#stocks = Stock.Where(:prices.lt => p)
But i really want to get results grouped by stock names after my query (distinct stocks with an array of ordered prices for example). I have heard about map/reduce with the group function but i am not sure how to use it correctly with Mongoid.
http://www.mongodb.org/display/DOCS/Aggregation
The equivalent in SQL would be something like this:
SELECT name, code, min(price) from Stock WHERE price<p GROUP BY name, code
Thanks for your help.
MongoDB / Mongoid do allow you to do this. Your example will work, the syntax is just incorrect.
#stocks = Stock.Where(:prices.value.lt => p) #does not work
#stocks = Stock.where('prices.value' => {'$lt' => p}) #this should work
And, it's still chainable so you can order by name as well:
#stocks = Stock.where('prices.value' => {'$lt' => p}).asc(:name)
Hope this helps.
I've had a similar problem... here's what I suggest:
scope :price_min, lambda { |price_min| price_min.nil? ? {} : where("price.value" => { '$lte' => price_min.to_f }) }
Place this scope in the parent model. This will enable you to make queries like:
Stock.price_min(1000).count
Note that my scope only works when you actually insert some data there. This is very handy if you're building complex queries with Mongoid.
Good luck!
Very best,
Ruy
MongoDB does allow querying of embedded documents, http://www.mongodb.org/display/DOCS/Advanced+Queries#AdvancedQueries-ValueinanEmbeddedObject
What you're missing is a scope on the Price model, something like this:
scope :greater_than, lambda {|value| { :where => {:value.gt => value} } }
This will let you pass in any value you want and return a Mongoid collection of prices with the value greater than what you passed in. It'll be an unsorted collection, so you'll have to sort it in Ruby.
prices.sort {|a,b| a.value <=> b.value}.each {|price| puts price.value}
Mongoid does have a map_reduce method to which you pass two string variables containing the Javascript functions to execute map/reduce, and this would probably be the best way of doing what you need, but the code above will work for now.

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