How to link individual cell in uitableview to distinct URL? - ios

Question

I currently have two separate arrays of titles in my uitablview. Each array is grouped in it's own section. Eg. Section 1 (item1, item2, item3) Section 2(item1, item2, etc). I would like to link each cell to a certain wordpress post. How would I do this? I have linked below all of my code below the viewdidload method which contains the arrays.
- (void)didReceiveMemoryWarning
{
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}
#pragma mark - Table view data source
- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
// Return the number of sections.
return numberOfSections;
}
- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
switch (section) {
case manualSection:
return [self.manual count];
case interviewSection:
return [self.interviews count];
default:
return 0;
}
}
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *CellIdentifier = #"Cell";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier forIndexPath:indexPath];
switch (indexPath.section)
{
case manualSection:
cell.textLabel.text = [self.manual objectAtIndex:indexPath.row];
break;
case interviewSection:
cell.textLabel.text = [self.interviews objectAtIndex:indexPath.row];
break;
default:
cell.textLabel.text = #"Not Found";
}
return cell;
}
- (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section {
switch (section) {
case manualSection:
return #"Manual";
break;
case interviewSection:
return #"Interviews";
break;
default:
return 0;
}
}

Answer 1

Create a model with the properties you need (title, link)
Update arrays (manuals, interviews) with models, and not strings
Implement the -tableView:didSelectRowAtIndexPath: function in the class you are presenting to us, to access the list at the index you need; then get the model and access the link
NSURL *url = [NSURL URLWithString:#"http://www.stackoverflow.com/"];
if( ![[NSWorkspace sharedWorkspace] openURL:url] )
NSLog(#"Failed to open url: %#",[url description]);