NSPredicate with Multiple Conditions - ios

Question

I am trying to create a NSPredicate with multiple conditions. I've found several solutions, but none of them appear to be working with my method. The best looking one I've found is below.
This is my single predicate method, and it works just fine:
NSPredicate *predicate = [NSPredicate predicateWithFormat:#"name contains[c] %#",
searchText];
filteredBusinesses = [businesses filteredArrayUsingPredicate:predicate];
Here is my edited version with multiple conditions. I'm not sure whats going wrong. Any ideas?
NSPredicate *p1 = [NSPredicate predicateWithFormat:#"name contains[c] %#", searchText];
NSPredicate *p2 = [NSPredicate predicateWithFormat:#"businessArea contains[c] %#",
searchText];
NSPredicate *predicate = [NSCompoundPredicate andPredicateWithSubpredicates:#[p1, p2]];
filteredBusinesses = [businesses filteredArrayUsingPredicate:predicate];

Answer 1

You can try this
NSPredicate *predicate = [NSCompoundPredicate orPredicateWithSubpredicates:#[p1, p2]];

Answer 2

Addition to #Nikunj's answer, you can also use NSCompoundPredicate for your AND operations like this.
Obj-C - AND
NSPredicate *predicate1 = [NSPredicate predicateWithFormat:#"X == 1"];
NSPredicate *predicate2 = [NSPredicate predicateWithFormat:#"X == 2"];
NSPredicate *predicate = [NSCompoundPredicate andPredicateWithSubpredicates:#[predicate1, predicate2]];
Swift - AND
let predicate1:NSPredicate = NSPredicate(format: "X == 1")
let predicate2:NSPredicate = NSPredicate(format: "Y == 2")
let predicate:NSPredicate = NSCompoundPredicate(andPredicateWithSubpredicates: [predicate1,predicate2] )
Swift 3 - AND
let predicate1 = NSPredicate(format: "X == 1")
let predicate2 = NSPredicate(format: "Y == 2")
let predicateCompound = NSCompoundPredicate.init(type: .and, subpredicates: [predicate1,predicate2])

Answer 3

Nothing looks wrong in the code you posted, which means the error is probably coming from when you evaluate the predicate by filtering the array.
Since the first predicate works, the problem lies with the businessArea key path.
Filtering the array would throw an exception if:
There's an object in the array that doesn't have a businessArea value (as in, it's not an object that has a -businessArea method)
The object does have a businessArea value, but the value is neither an NSString nor nil

Answer 4

NSCompoundPredicate received a facelift. Just in case someone's looking for a Swift 5+ version:
AND
let predicatesAND = NSCompoundPredicate(andPredicateWithSubpredicates:[pred1,pred2])
OR
let predicatesOR = NSCompoundPredicate(orPredicateWithSubpredicates:[pred1,pred2])

Answer 5

First off, I suspect you may have a flaw in your two basic predicates. Judging by your object name "businesses", it is a collection i.e NSArray, NSSet or NSDictionay of items. In that case, "name contains[c] 'mmm'" has no meaning when evaluated for the whole collection, and should crash. It is missing a collection operator (ANY, ALL, SOME) , e.g. "ANY name contains[c] 'mmm'".
Ah... now I see... you're using the predicate to filter an NSArray, which means the predicate is executed on each item separately. So your predicates are alright.
Now... the simplest way to combine your predicates is at the very format-string level! what's wrong with
NSPredicate *p1 = [NSPredicate predicateWithFormat:#"name contains[c] %# AND businessArea contains[c] %#", nameToSearch, areaToSearch];
If you insist on doing it the hard way, than building your compound NSPredicate should have worked too - only you employed the same searchText to both conditions, which may caused the predicate to never match.
My advice to you, place a breakpoint on the line evaluating the filtered array and stop just before the filtering, and in the debugger print the predicate description, using the debugger command po p1 you will see there what is the final form of your predicate, and will be able to determine if you built it correctly.