Load URL within JSON in UIWebView? - ios

Question

My JSON reads like this:
{
"sites": [
{
"name": "lovely.com",
"url": "http:\/\/www.trial.com\/lovely\/",
"price": "1795",
},
{
"name": "great.com",
"url": "http:\/\/www.trial.com\/great\/",
"price": "1730",
},
{
"name": "food.com",
"url": "http:\/\/www.trial.com\/food\/",
"price": "1195",
},
I need the url of the specified site to open in a separate UIWebView when the user clicks on the "buy" button. Here is a snippet of my current code:
ViewController.m
-(void)buyBttnPressed:(id)sender{
UIWebView *buyView = [[UIWebView alloc] initWithFrame:CGRectMake(20,132,280,368)];
buyView.backgroundColor = [UIColor whiteColor];
buyView.scalesPageToFit = YES;
buyView.delegate = self;
[self.view addSubview:buyView];
// [buyView loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:_url]]];
}
I have already parsed the JSON file. I'm just trying to figure out how to open the url(s) in the WebView using the url object key . . .

Answer 1

You can modify code as below
NSString *urlString=[NSString stringWithFormat:#"%#",url];
[buyView loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:urlstring]]];
////(OR) If are using NSObject say Location to store the details you can refer below code
UIButton *btn=(UIButton *)sender;
Location *locObj=[self.dataArray objectAtIndex:btn.tag];
NSString *urlString=[NSString stringWithFormat:#"%#",locObj.url];
[buyView loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:urlstring]]];
int i=-1;
for(NSDictionary *dict in dataarray)
{
i++;
btn.tag=i;
}
Hope it helps you...!

Answer 2

Use the Json element where you saved all the links,let's say that your JsonElement is called
Location
the code should be something like this:
NSURL *nsurl=[NSURL URLWithString:Location.url];
NSURLRequest *nsrequest=[NSURLRequest requestWithURL:nsurl];
[webview loadRequest:nsrequest];

Answer 3

do this
NSError *error;
NSJSONSerialization *jsonData = [NSJSONSerialization JSONObjectWithData:parseData options:NSJSONReadingMutableContainers error:&error];
NSString *strURL = [[[jsonData valueForKey:#"sites"]objectAtIndex:selectedIndex]valueForKey:#"url"];
[buyView loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:strURL]]];

Answer 4

you can try this
create a custom method to get json data as an array..
-(NSArray *)getDataDictionaryFromJsonFile:(NSString *)jsonFileName
{
NSData *fileContents = [NSData dataWithContentsOfFile:[[NSBundle mainBundle] pathForResource:jsonFileName ofType:#"json"]];
NSError *error;
NSDictionary *dict = [NSJSONSerialization JSONObjectWithData:fileContents options:kNilOptions error:&error];
NSArray * array = [dict objectForKey:#"sites"];
return array;
}
now call this method where ever you want,
like
NSArray * sitesArray = [self getDataDictionaryFromJsonFile:#"Sites"];
NSURL * url = [NSURL urlFromString:[[sitesArray objectAtIndex:0] objectForKey:#"url"]];
NSLog(#"lovely URL:%#",[[sitesArray objectAtIndex:0] objectForKey:#"url"]);

Answer 5

The easiest way to do that is by using AFNetworking library here
Add AFNetworking to your project and import AFNetworking.h and create a property to store the url from the JSON
//in .h file
#property (strong, nonatomic) NSString *urlFromJSON;
.
//in .m file
NSURL *url = [[NSURL alloc] initWithString:#"YOUR_JSON_URL_HERE"];
NSURLRequest *request = [[NSURLRequest alloc] initWithURL:url];
AFJSONRequestOperation *operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON) {
//You can reach the the url using:
self.urlFromJSON = JSON["url"]; //the key of the url in the JSON
} failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id JSON) {
NSLog(#"Request Failed with Error: %#, %#", error, error.userInfo);
}];
[operation start];
Good Luck ;)