What I want to do is,
We have having one product info on Website.
That product is available on store.
what we have on website is that, Product info and one button for that product.
I want to take two actions on that button.
When User opens website on iPad or iPhone on Safari (browser) and click on GetProduct button, then following two actions must be taken place.
1. If user is already having product installed on device then directly open the app in device.
2. If user is not having the app on device then link user to the app on store, so he can download from there.
I already handled second condition,
but how to handle the first condition.
If I am already having the app then how to open it on action of button click in browser.
You can achieve what you're asking for by using a URL scheme. This will enable you to call the openUrl: method with your application's url scheme which will then launch your app.
Here's how you setup a custom url scheme:
Open your app's Info.plist and add a row with a key called URL Types.
Expand the URL Types item, and Item 0 under it and you'll see URL Identifier
Enter your app's bundle identifier (e.g. com.myCompany.myApp) as the URL Identifier value.
Add another row to Item 0 and enter URL Schemes.
Expand the URL Schemes and under Item 0 type in the name for your custom scheme (e.g. myScheme).
You should now be able to open your app from Safari by typing myScheme:// in the address bar.
Alternatively, from your app, you can launch the other app like this:
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"myScheme://"]];
Note that you can also send parameters to the app you're launching with the url scheme (more on that here).
With iOS9 Apple introduced a way to open installed app from Links. Here is the official link for this : Apple universal links
Related
I installed Meeseva app on my device. When I try to open it programmatically it's not opening.
if ([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:#"Meeseva App://location?id=1"]]) {
NSString *mystr=[[NSString alloc] initWithFormat:#"Meeseva App://location?id=1"];
NSURL *myurl=[[NSURL alloc] initWithString:mystr];
[[UIApplication sharedApplication] openURL:myurl];
}
When I opened fb, twitter, google+ and etc... all are opening successfully.
Can any solve this this issue?
App link is
https://itunes.apple.com/in/app/meeseva-app/id1121539928?mt=8
Is there any another way to open installed app programatically?
If your app can receive specially formatted URLs, you should register the corresponding URL schemes with the system. Apps often use custom URL schemes to vend services to other apps.
Hence "Meeseva" app might not have created a custom url for their app. So you can't do anything for it.
As mentioned above the apps which want to provide support for url schema then they have to create a custom URL schemes.
You need to find out what the correct URL scheme of the Meeseva App is. Meeseva App:// does not seem to be a valid URL scheme as it has a space in the middle.
For example the Google Maps URL scheme is comgooglemaps://, not Google Maps://
Usually developers make their URL scheme public in their documentation. However this is a feature that needs to be implemented and apps don't support this "out of the box". If the developer did not implement this, the app can't be opened via link.
Alternatively it is possible that the app reacts on "universal links". That means if there is a website for the app, iOS might ask you whether to open that website in the app or in Safari. In that case you could simply link to the website and let the user decide how the link should be opened. However, again, this needs to be implemented by the developer. If the app does not support universal links either, there's no way for you to open the app at all.
I have two applications and i want to open them from each other (like facebook opens messenger).
After a little search i found that i have to know the url scheme of my app, but i don't know how can i declare it. In my urlSchemes are only facebook's schemes.
var url = NSURL(string: "")
UIApplication.sharedApplication().canOpenURL(url!)
I found that code and as i understand i have to put in the url my urlScheme.
Any help?
Here is a good tutorial on setting up URL Schemes within you app: https://dev.twitter.com/cards/mobile/url-schemes
Incase this tutorial disappears, heres the info:
Configure our Xcode project
Go to Your Target > Info > URL Types
You need to define your custom URL type. Remember, you want to open the app via birdland://, so that will be your URL scheme. We also need to assign an unique identifier to the scheme. Apple recommends that you use reverse DNS notation to ensure that there are no name collisions on the platform, e.g com.mycompany.ios.
That’s it! You’ve configured the app with simple support for the URL scheme birdland://. There is, of course, much more that you can do with Custom URL Schemes. To find out more, check out Apple’s documentation.
Now, to check that our registered URL scheme works, we’ll head out to Safari. Press the “Home” button in the Simulator (or press command-shift-H) to reach the Home Screen. Open Safari.
Next, type birdland:// in the address bar of Safari. Just as you can with http:// URLs, you’re asking Safari to open the “birdland” scheme. Press Go.
NSString *openAppURL = #"yourappname://";
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:openAppURL]];
//check if app is installed or not
BOOL canOpenURL = [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:openAppURL]];
First of all, I know how to make custom schemes in iOS and I know how to open my app from a website using a javascript setTimeout method.
I have an app that uses custom URL scheme and it is working great. What it does is, it sends a http://testsite.com/QueryStrings message to other users in the contact list (predefined) and on clicking those web links in the sms, these things happen:
Open the link in Safari
Open the app if installed with custom url using setTimeout
If not installed, move to the normal website page
What I wanted actually is to open my app directly from SMS if installed but for that I have to send my custom url scheme in the SMS, that is not an option because if app is not installed then this SMS wont work so a weblink is the only option for now.
Today, I installed SoundCloud and accidentally noticed this thing is that when http:// m. soundcloud .com /... url is sent in an SMS and on clicking the link it opens the app (if installed) directly not the Safari (Strange for me).
So I was wondering how come their app open from a web link without opening the Safari. I googled it around but I couldn't find a solution to my problem. I am attaching a screenshot too from my mobile where press and hold on the link in the messages app give Open in "SoundCloud" option as well. So how SoundCloud registered a http link to be handled automatically in the app. Please help guys
Screenshot of SoundCloud Open
The answer to this problem is using Associated Domains (But after 9.2 we have to use Universal Links to achieve this).
Before Universal Links, the primary mechanism to open up an app when it was installed was by trying to redirect to an app’s URI scheme (registered in the app’s PLIST like so) in Safari. This put the routing logic in Safari, but there was no way to check if the app was installed or not.
iOS 9 Universal Links were intended to fix this. Instead of opening up Safari first when a link is clicked, iOS will check if a Universal Link has been registered for the domain associated with the link, then check if the corresponding app is installed. If the app is currently installed, it will be opened. If it’s not, Safari will open and the http(s) link will load.
Functionally, it allows you have a single link that will either open your app or open your mobile site.
Configure your app to register approved domains
Registered your app at developers.apple.com
Enable ‘Associated Domains’ on your app identifier
Enable ‘Associated Domain’ on in your Xcode project
Add the proper domain entitlement
Make sure the entitlements file is included at build
Configure your website to host the ‘apple-app-site-association’ file
Buy a domain name or pick from your existing
Acquire SSL certification for the domain name
Create structured ‘apple-app-site-association’ JSON file
Sign the JSON file with the SSL certification
Configure the file server
Apple launched Universal Links in iOS 9.0, which moves the app routing into the OS so that developers don’t need to worry about doing the routing in Javascript.
Receiving Universal Link URL in the App
URI schemes received the deep link URL through openUrl in the App Delegate. Universal Links receive their data via a different code path: continueUserActivity. This new delegate method is used for a number of app transitions, ranging from Spotlight to Universal Links, and will likely see a couple more use cases introduced in future OS versions.
Below is a snippet of code that you can use to retrieve the full Universal Link URL that opened the app.
- (BOOL)application:(UIApplication *)application continueUserActivity:(NSUserActivity *)userActivity restorationHandler:(void (^)(NSArray *))restorationHandler {
if ([userActivity.activityType isEqualToString:NSUserActivityTypeBrowsingWeb]) {
NSString *myUrl = [userActivity.webpageURL absoluteString];
// parse URL string or access query params
}
return YES;
}
Source: https://blog.branch.io/how-to-setup-universal-links-to-deep-link-on-apple-ios-9
I want to open sayduck application from my iOS application. I know I need to use URL Scheme register by this application. My problem is that I cant fint this URL. Do you know how I can check if this URL is definded?
There is a URL scheme - but unless you're sure the user has the Sayduck application installed the best approach is to go via safari. openURL:
http://in.sayduck.com/
This will either launch the app, go to the appropriate app store download page for the device or show a web page depending on the device type (desktop/ios/android etc.)
Disclosure: I work for sayduck
The situation is like this:
User opens app from a website using a custom urlscheme
User does stuff in the app
User clicks button in the app to return to the website in Safari.
I have tried opening a new tab containing a javascript:window.close() but this does not work on iOS 6.1.
So my question is: Is there a way to open Safari to view the website the user left from? Either with a working new tab that closes itself or a different route?
When you open the app with your custom url scheme, pass the actual page url as an argument.
mycustomUrlScheme://mydomain.com?objectid=1234&callback_url=encoded_url
In your app, handle the url for the content info and keep the page url to open it afterwards. It will make safari open a new tab. But that should be a good start.
As far as i understand you can do it.
user opens mobile safari for example http://www.example.com
user clicks a link that is appscheme://open and the application become active
user taps a button to open safari for example http://www.example.com?q=test
for the third step you can use [[UIApplication sharedApplication]openURL:url]