I am playing around with action extensions and looked at Apple's documents and found this code.
NSExtensionContext *myExtensionContext = self.extensionContext;
NSArray *inputItems = myExtensionContext.inputItems;
Then I change the array to a string.
NSString * resultString = [inputItems componentsJoinedByString:#""];
Then, I set the text view to the resultString string.
textView.text = resultString;
What I have been getting is
<NSExtensionItem: 0x174002840> - userInfo: {NSExtensionItemAttachmentsKey = ("<NSItemProvider: 0x17424c900> {types = (\n \"public.plain-text\"\n)}");}
that appears in my text view.
Code snippet from viewDidLoad:
[super viewDidLoad];
NSExtensionContext *myExtensionContext = self.extensionContext;
NSArray *inputItems = myExtensionContext.inputItems;
NSString * resultString = [inputItems componentsJoinedByString:#""];
textView.text = resultString;
Actually following code will return array of NSExtensionItem not a NSString type so you can not parse directly using
NSString * resultString = [inputItems componentsJoinedByString:#""];
To Parse NSArray of NSExtensionItems, You need to do following things. Here I assume that 'NSDictionary' as input type.
for (NSExtensionItem *item in self.extensionContext.inputItems) {
for (NSItemProvider *itemProvider in item.attachments) {
if ([itemProvider hasItemConformingToTypeIdentifier:#"typeIdentifier"]) {
// This is an image. We'll load it, then place it in our image view.
[itemProvider loadItemForTypeIdentifier:#"typeIdentifier" options:nil completionHandler:^(id<NSSecureCoding> item, NSError *error) {
NSDictionary* tempDict = (NSDictionary*)item;
NSLog(#"Dectionary : %#",item);
}];
}
}
}
For More details Action Extension tutorial may help you.
With all the URL-handling objects lying around in the standard Cocoa libraries (NSURL, NSMutableURL, NSMutableURLRequest, etc), I know I must be overlooking an easy way to programmatically compose a GET request.
Currently I'm manually appending "?" followed by name value pairs joined by "&", but all of my name and value pairs need to be manually encoded so NSMutableURLRequest doesn't fail entirely when it tries to connect to the URL.
This feels like something I should be able to use a pre-baked API for.... is there anything out of the box to append an NSDictionary of query parameters to an NSURL? Is there another way I should approach this?
Introduced in iOS8 and OS X 10.10 is NSURLQueryItem, which can be used to build queries. From the docs on NSURLQueryItem:
An NSURLQueryItem object represents a single name/value pair for an item in the query portion of a URL. You use query items with the queryItems property of an NSURLComponents object.
To create one use the designated initializer queryItemWithName:value: and then add them to NSURLComponents to generate an NSURL. For example:
NSURLComponents *components = [NSURLComponents componentsWithString:#"http://stackoverflow.com"];
NSURLQueryItem *search = [NSURLQueryItem queryItemWithName:#"q" value:#"ios"];
NSURLQueryItem *count = [NSURLQueryItem queryItemWithName:#"count" value:#"10"];
components.queryItems = #[ search, count ];
NSURL *url = components.URL; // http://stackoverflow.com?q=ios&count=10
Notice that the question mark and ampersand are automatically handled. Creating an NSURL from a dictionary of parameters is as simple as:
NSDictionary *queryDictionary = #{ #"q": #"ios", #"count": #"10" };
NSMutableArray *queryItems = [NSMutableArray array];
for (NSString *key in queryDictionary) {
[queryItems addObject:[NSURLQueryItem queryItemWithName:key value:queryDictionary[key]]];
}
components.queryItems = queryItems;
I've also written a blog post on how to build URLs with NSURLComponents and NSURLQueryItems.
You can create a category for NSDictionary to do this -- there isn't a standard way in the Cocoa library that I could find either. The code that I use looks like this:
// file "NSDictionary+UrlEncoding.h"
#import <cocoa/cocoa.h>
#interface NSDictionary (UrlEncoding)
-(NSString*) urlEncodedString;
#end
with this implementation:
// file "NSDictionary+UrlEncoding.m"
#import "NSDictionary+UrlEncoding.h"
// helper function: get the string form of any object
static NSString *toString(id object) {
return [NSString stringWithFormat: #"%#", object];
}
// helper function: get the url encoded string form of any object
static NSString *urlEncode(id object) {
NSString *string = toString(object);
return [string stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];
}
#implementation NSDictionary (UrlEncoding)
-(NSString*) urlEncodedString {
NSMutableArray *parts = [NSMutableArray array];
for (id key in self) {
id value = [self objectForKey: key];
NSString *part = [NSString stringWithFormat: #"%#=%#", urlEncode(key), urlEncode(value)];
[parts addObject: part];
}
return [parts componentsJoinedByString: #"&"];
}
#end
I think the code's pretty straightforward, but I discuss it in some more detail at http://blog.ablepear.com/2008/12/urlencoding-category-for-nsdictionary.html.
I wanted to use Chris's answer, but it wasn't written for Automatic Reference Counting (ARC) so I updated it. I thought I'd paste my solution in case anyone else has this same issue. Note: replace self with the instance or class name where appropriate.
+(NSString*)urlEscapeString:(NSString *)unencodedString
{
CFStringRef originalStringRef = (__bridge_retained CFStringRef)unencodedString;
NSString *s = (__bridge_transfer NSString *)CFURLCreateStringByAddingPercentEscapes(NULL,originalStringRef, NULL, (CFStringRef)#"!*'\"();:#&=+$,/?%#[]% ", kCFStringEncodingUTF8);
CFRelease(originalStringRef);
return s;
}
+(NSString*)addQueryStringToUrlString:(NSString *)urlString withDictionary:(NSDictionary *)dictionary
{
NSMutableString *urlWithQuerystring = [[NSMutableString alloc] initWithString:urlString];
for (id key in dictionary) {
NSString *keyString = [key description];
NSString *valueString = [[dictionary objectForKey:key] description];
if ([urlWithQuerystring rangeOfString:#"?"].location == NSNotFound) {
[urlWithQuerystring appendFormat:#"?%#=%#", [self urlEscapeString:keyString], [self urlEscapeString:valueString]];
} else {
[urlWithQuerystring appendFormat:#"&%#=%#", [self urlEscapeString:keyString], [self urlEscapeString:valueString]];
}
}
return urlWithQuerystring;
}
The other answers work great if the values are strings, however if the values are dictionaries or arrays then this code will handle that.
Its important to note that there is no standard way of passing an array/dictionary via the query string but PHP handles this output just fine
-(NSString *)serializeParams:(NSDictionary *)params {
/*
Convert an NSDictionary to a query string
*/
NSMutableArray* pairs = [NSMutableArray array];
for (NSString* key in [params keyEnumerator]) {
id value = [params objectForKey:key];
if ([value isKindOfClass:[NSDictionary class]]) {
for (NSString *subKey in value) {
NSString* escaped_value = (NSString *)CFURLCreateStringByAddingPercentEscapes(NULL,
(CFStringRef)[value objectForKey:subKey],
NULL,
(CFStringRef)#"!*'();:#&=+$,/?%#[]",
kCFStringEncodingUTF8);
[pairs addObject:[NSString stringWithFormat:#"%#[%#]=%#", key, subKey, escaped_value]];
}
} else if ([value isKindOfClass:[NSArray class]]) {
for (NSString *subValue in value) {
NSString* escaped_value = (NSString *)CFURLCreateStringByAddingPercentEscapes(NULL,
(CFStringRef)subValue,
NULL,
(CFStringRef)#"!*'();:#&=+$,/?%#[]",
kCFStringEncodingUTF8);
[pairs addObject:[NSString stringWithFormat:#"%#[]=%#", key, escaped_value]];
}
} else {
NSString* escaped_value = (NSString *)CFURLCreateStringByAddingPercentEscapes(NULL,
(CFStringRef)[params objectForKey:key],
NULL,
(CFStringRef)#"!*'();:#&=+$,/?%#[]",
kCFStringEncodingUTF8);
[pairs addObject:[NSString stringWithFormat:#"%#=%#", key, escaped_value]];
[escaped_value release];
}
}
return [pairs componentsJoinedByString:#"&"];
}
Examples
[foo] => bar
[translations] =>
{
[one] => uno
[two] => dos
[three] => tres
}
foo=bar&translations[one]=uno&translations[two]=dos&translations[three]=tres
[foo] => bar
[translations] =>
{
uno
dos
tres
}
foo=bar&translations[]=uno&translations[]=dos&translations[]=tres
I refactored and converted to ARC answer by AlBeebe
- (NSString *)serializeParams:(NSDictionary *)params {
NSMutableArray *pairs = NSMutableArray.array;
for (NSString *key in params.keyEnumerator) {
id value = params[key];
if ([value isKindOfClass:[NSDictionary class]])
for (NSString *subKey in value)
[pairs addObject:[NSString stringWithFormat:#"%#[%#]=%#", key, subKey, [self escapeValueForURLParameter:[value objectForKey:subKey]]]];
else if ([value isKindOfClass:[NSArray class]])
for (NSString *subValue in value)
[pairs addObject:[NSString stringWithFormat:#"%#[]=%#", key, [self escapeValueForURLParameter:subValue]]];
else
[pairs addObject:[NSString stringWithFormat:#"%#=%#", key, [self escapeValueForURLParameter:value]]];
}
return [pairs componentsJoinedByString:#"&"];
}
- (NSString *)escapeValueForURLParameter:(NSString *)valueToEscape {
return (__bridge_transfer NSString *) CFURLCreateStringByAddingPercentEscapes(NULL, (__bridge CFStringRef) valueToEscape,
NULL, (CFStringRef) #"!*'();:#&=+$,/?%#[]", kCFStringEncodingUTF8);
}
If you are already using AFNetworking (as was the case with me), you can use it's class AFHTTPRequestSerializer to create the required NSURLRequest.
[[AFHTTPRequestSerializer serializer] requestWithMethod:#"GET" URLString:#"YOUR_URL" parameters:#{PARAMS} error:nil];
In case you only require the URL for your work, use NSURLRequest.URL.
Here is a simple example in Swift (iOS8+):
private let kSNStockInfoFetchRequestPath: String = "http://dev.markitondemand.com/Api/v2/Quote/json"
private func SNStockInfoFetchRequestURL(symbol:String) -> NSURL? {
if let components = NSURLComponents(string:kSNStockInfoFetchRequestPath) {
components.queryItems = [NSURLQueryItem(name:"symbol", value:symbol)]
return components.URL
}
return nil
}
I took Joel's recommendation of using URLQueryItems and turned into a Swift Extension (Swift 3)
extension URL
{
/// Creates an NSURL with url-encoded parameters.
init?(string : String, parameters : [String : String])
{
guard var components = URLComponents(string: string) else { return nil }
components.queryItems = parameters.map { return URLQueryItem(name: $0, value: $1) }
guard let url = components.url else { return nil }
// Kinda redundant, but we need to call init.
self.init(string: url.absoluteString)
}
}
(The self.init method is kinda cheesy, but there was no NSURL init with components)
Can be used as
URL(string: "http://www.google.com/", parameters: ["q" : "search me"])
I've got another solution:
http://splinter.com.au/build-a-url-query-string-in-obj-c-from-a-dict
+(NSString*)urlEscape:(NSString *)unencodedString {
NSString *s = (NSString *)CFURLCreateStringByAddingPercentEscapes(NULL,
(CFStringRef)unencodedString,
NULL,
(CFStringRef)#"!*'\"();:#&=+$,/?%#[]% ",
kCFStringEncodingUTF8);
return [s autorelease]; // Due to the 'create rule' we own the above and must autorelease it
}
// Put a query string onto the end of a url
+(NSString*)addQueryStringToUrl:(NSString *)url params:(NSDictionary *)params {
NSMutableString *urlWithQuerystring = [[[NSMutableString alloc] initWithString:url] autorelease];
// Convert the params into a query string
if (params) {
for(id key in params) {
NSString *sKey = [key description];
NSString *sVal = [[params objectForKey:key] description];
// Do we need to add ?k=v or &k=v ?
if ([urlWithQuerystring rangeOfString:#"?"].location==NSNotFound) {
[urlWithQuerystring appendFormat:#"?%#=%#", [Http urlEscape:sKey], [Http urlEscape:sVal]];
} else {
[urlWithQuerystring appendFormat:#"&%#=%#", [Http urlEscape:sKey], [Http urlEscape:sVal]];
}
}
}
return urlWithQuerystring;
}
You can then use it like so:
NSDictionary *params = #{#"username":#"jim", #"password":#"abc123"};
NSString *urlWithQuerystring = [self addQueryStringToUrl:#"https://myapp.com/login" params:params];
-(NSString*)encodeDictionary:(NSDictionary*)dictionary{
NSMutableString *bodyData = [[NSMutableString alloc]init];
int i = 0;
for (NSString *key in dictionary.allKeys) {
i++;
[bodyData appendFormat:#"%#=",key];
NSString *value = [dictionary valueForKey:key];
NSString *newString = [value stringByReplacingOccurrencesOfString:#" " withString:#"+"];
[bodyData appendString:newString];
if (i < dictionary.allKeys.count) {
[bodyData appendString:#"&"];
}
}
return bodyData;
}
Yet another solution, if you use RestKit there's a function in RKURLEncodedSerialization called RKURLEncodedStringFromDictionaryWithEncoding that does exactly what you want.
Simple way of converting NSDictionary to url query string in Objective-c
Ex: first_name=Steve&middle_name=Gates&last_name=Jobs&address=Palo Alto, California
NSDictionary *sampleDictionary = #{#"first_name" : #"Steve",
#"middle_name" : #"Gates",
#"last_name" : #"Jobs",
#"address" : #"Palo Alto, California"};
NSMutableString *resultString = [NSMutableString string];
for (NSString* key in [sampleDictionary allKeys]){
if ([resultString length]>0)
[resultString appendString:#"&"];
[resultString appendFormat:#"%#=%#", key, [sampleDictionary objectForKey:key]];
}
NSLog(#"QueryString: %#", resultString);
Hope will help :)
If you are already using AFNetwork, you can use their built in serializer to to produce an encoded URL;
NSString *baseURL = #"https://api.app.com/parse";
NSDictionary *mutableParameters = [[NSMutableDictionary alloc] initWithObjectsAndKeys:#"true",#"option1", data, #"option2", token, #"token", #"3.0", #"app", nil];
NSURLRequest *request = [[AFHTTPRequestSerializer serializer] requestWithMethod:#"GET" URLString:baseURL parameters:mutableParameters error:nil];
NSString *urlPath = request.URL.absoluteString;
NSLog(#"%#", urlPath); // https://api.app.com/parse?option1=true&option2=datavalue&token=200%3ATEST%3AENCODE ....
Note; this is an extension to an above answer. The edit queue is full so cannot be added to the existing answer.
I am trying to parse the file location from the following so that image can be displayed. How do I do it?
[
{
"title":"testing barcode display",
"body":"lets see if it renders \r\n\r\n",
"author":"1",
"created":"1373490143",
"nid":"5",
"Barcode":"<img class=\"barcode\" typeof=\"foaf:Image\" src=\"http://mysite.com/sites/default/files/barcodes/95b2d526b0a8f3860e7309ba59b7ca11QRCODE.png\" alt=\"blahimage\" title=\"blahimage\" />"
}
]
I have a table view which displays the title tag. I need to display the entire content in the detail view. I can do everything except the Barcode tag. Please advise.
If it should be done, parse the xml
NSString *xmlString = #"<img class=\"barcode\" typeof=\"foaf:Image\" src=\"http://mysite.com/sites/default/files/barcodes/95b2d526b0a8f3860e7309ba59b7ca11QRCODE.png\" alt=\"blahimage\" title=\"blahimage\" />";
GDataXMLElement *xmlElement = [[GDataXMLElement alloc]initWithXMLString:xmlString error:nil];
NSArray *attributes = [xmlElement attributes];
[attributes enumerateObjectsUsingBlock:^(GDataXMLNode * node, NSUInteger idx, BOOL *stop) {
NSLog(#"%# : %#",node.name,node.stringValue);
}];
OR
NSString *class = [[xmlElement attributeForName:#"class"] stringValue];
NSString *typeOf = [[xmlElement attributeForName:#"typeof"] stringValue];
NSString *src = [[xmlElement attributeForName:#"src"] stringValue];
NSString *alt = [[xmlElement attributeForName:#"alt"] stringValue];
NSString *title = [[xmlElement attributeForName:#"title"] stringValue];
Use json-framework or something similar.
If you do decide to use json-framework, here's how you would parse a JSON string into an NSDictionary:
SBJsonParser* parser = [[[SBJsonParser alloc] init] autorelease];
// assuming jsonString is your JSON string...
NSDictionary* myDict = [parser objectWithString:jsonString];
// now you can grab data out of the dictionary using objectForKey or another dictionary method
You have to convert json string in nsdictionary, so try this
SBJSON *json = [[SBJSON new] autorelease];
NSError *error;
NSDictionary *dict = [json objectWithString:YOUR_JSON_STRING error:&error];
add user this dictionary to display details in tableView
I have a button that shows some part of the URL on a text view, but I would like for this information to be shown in a specific format.
- (IBAction)Accesos:(id)sender {
NSData *data = [NSData dataWithContentsOfURL:[NSURL URLWithString:#"URL"]];
NSError* error;
NSDictionary* json = [NSJSONSerialization
JSONObjectWithData:data
options:kNilOptions
error:&error];
NSArray* Response_array = [json objectForKey:#"avenidas"];
for (int i=0; i < Response_array.count; i++){
NSDictionary* item = [Response_array objectAtIndex:i];
NSString* name = [item objectForKey:#"name"];
NSString* state = [item objectForKey:#"state"];
NSString* space = #"\n";
NSString* formattedString = [NSString stringWithFormat:#"%#%#: %#",space, name, state];
txt_webservice_response.text = formattedString; }
}
The information is shown the same as in the URL I would like to display the information like name: state and then the state to be in color depending the type if it is possible.
NSArray* items = [someDictionary objectForKey:#"avenidas"];
NSDictionary* item = [items objectAtIndex:someIndex];
NSString* name = [item objectForKey:#"name"];
NSString* state = [item objectForKey:#"state"];
NSString* formattedString = [NSString stringWithFormat:#"%#:%#", name, state];
(All of this is first-week stuff -- if you don't know it you need to spend more time studying the fundamentals.)
You can create the HTML for the response and show it to webView for coloring
I one of my apps, i parse some data from local host and print it in a table view. To get the data, the user first logs in using an alert view. The user id entered is then used to fetch the data which i parse using JSON.
There is definitely a very simple solution to this question but I can't seem to be able to fix it. The problem is that when I print the data the string comes in this format:
( "string" )
But I want it so that it just says : string
in the table view. Here is my parsing method:
- (void)updateMyBooks
{
dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), ^{
// Fetch data on a background thread:
NSString *authFormatString =
#"http://localhost:8888/Jineel_lib/bookBorrowed.php?uid=%#";
NSString *string = [[NSString alloc]initWithFormat:#"%#",UserID];
NSString *urlString = [NSString stringWithFormat:authFormatString, string];
NSURL *url = [NSURL URLWithString:urlString];
NSLog(#"uel is %#", url);
NSString *contents = [NSString stringWithContentsOfURL:url encoding:NSUTF8StringEncoding error:nil];
response1 = [contents JSONValue];
if (contents) {
// ... Parse JSON response and add objects to newBooksBorrowed ...
BookName = [[NSString alloc]init];
DateBorrowed = [[NSString alloc]init];
BookID = [[NSString alloc]init];
BookExtended = [[NSString alloc]init];
BookReturned = [[NSString alloc]init];
BookName = [response1 valueForKey:#"BookName"];
BookID = [response1 valueForKey:#"BookID"];
DateBorrowed = [response1 valueForKey:#"DateBorrowed"];
BookExtended = [response1 valueForKey:#"Extended"];
BookReturned = [response1 valueForKey:#"Returned"];
dispatch_sync(dispatch_get_main_queue(), ^{
// Update data source array and reload table view.
[BooksBorrowed addObject:BookName];
NSLog(#"bookBorrowed array = %#",BooksBorrowed);
[self.tableView reloadData];
});
}
});
}
This is how I print it in the table view:
NSString *string = [[NSString alloc] initWithFormat:#"%#",[BooksBorrowed objectAtIndex:indexPath.row]];
NSLog(#"string is %#",string);
cell.textLabel.text = string;
When I use log during the parsing process, it comes out as ( "string" ) so the problem is somewhere in the parsing, at least thats what I think.
If
NSString *string = [[NSString alloc] initWithFormat:#"%#",[BooksBorrowed objectAtIndex:indexPath.row]];
returns something like "( string )" then the most probably reason is that
[BooksBorrowed objectAtIndex:indexPath.row]
is not a string, but an array containing a string. In that case,
NSString *string = [[BooksBorrowed objectAtIndex:indexPath.row] objectAtIndex:0];
should be the solution.
NSString *string = [[NSString alloc] initWithFormat:#"%#",[BooksBorrowed objectAtIndex:indexPath.row]];
string = [string stringByReplacingOccurrencesOfString:#"(" withString:#""];
string = [string stringByReplacingOccurrencesOfString:#")" withString:#""];
string = [string stringByReplacingOccurrencesOfString:#"\"" withString:#""];
NSLog(#"string is %#",string);
cell.textLabel.text = string;
EDIT:
Above code is used if it's showing text in that format in your label.
If you see that in NSlog then it's NSString inside NSArray.
You need to fetch that string first from array and then display, use code line suggested by #Martin R for that.
NSString *string = [[BooksBorrowed objectAtIndex:indexPath.row] objectAtIndex:0];