How can I create a "hyperlink" with Swift? - ios

Question

I'm trying to make separate pieces of text UILabels clickable. What I'm looking for is commonly known as a hyperlink in web development.
Link 1
Link 2
Link 3
Each a tag is its own UILabel, and it would ideally open Safari to the specified href when the text between the tags is clicked.
I've found a bevy of resources on how to do this sort of thing in Objective-C, but they all seem unnecessarily complicated and don't translate well to Swift (they fit an Objective-C organizational structure that doesn't work well in Swift and goes against the recommended way of using the language).
Here are a few:
How to add hyperlink in iPhone app?
How to make a clickable link inside a NSTextField and Cocoa
Text as Hyperlink in Objective-C
If I had a 3 UILabels,
Item 1
Item 2
Item 3
then what would be the best "Swift-y" way to make each item open to a different URL in Safari?
I could create separate buttons for each, but the UILabels are programmatically populated, so I was thinking that making the text respond to taps might be a better option.

Answer 1

Swift 3
I created a LinkUILabel class in github:
https://github.com/jorgecsan/LinkUILabel
With this you only need add the url inspectable as the shows the image:
or assign the url variable programmatically:
linkUILabel.url = "www.example.com"
If you want to implement by your self also I found that solution!:)
using:
// This is the label
#IBOutlet weak var label: UILabel!
override func loadView() {
super.loadView()
// This is the key
let tap = UITapGestureRecognizer(target: self, action: #selector(self.onClicLabel(sender:)))
label.isUserInteractionEnabled = true
label.addGestureRecognizer(tap)
}
// And that's the function :)
func onClicLabel(sender:UITapGestureRecognizer) {
openUrl("http://www.google.com")
}
func openUrl(urlString:String!) {
let url = URL(string: urlString)!
if #available(iOS 10.0, *) {
UIApplication.shared.open(url, options: [:], completionHandler: nil)
} else {
UIApplication.shared.openURL(url)
}
}
Hope it helps!:)

Answer 2

The One approach would be something like the following.
The assumptions are:
self.urls is a string array containing the urls associated with each UILabel.
Each UILabel tag has been set to the corresponding index in the array
labelTapped: is set as the touchUpInside handler for the labels.
import Foundation
import UIKit
class urltest {
var urls:[String]
init() {
self.urls=[String]() // Load URLs into here
}
#IBAction func labelTapped(sender:UILabel!) {
let urlIndex=sender.tag;
if (urlIndex >= 0 && urlIndex < self.urls.count) {
self.openUrl(self.urls[urlIndex]);
}
}
func openUrl(url:String!) {
let targetURL=NSURL.URLWithString(url)
let application=UIApplication.sharedApplication()
application.openURL(targetURL);
}
}

Answer 3

Hyperlink via UITextView
var termsConditionsTextView: UITextView = {
let view = UITextView()
view.backgroundColor = .clear
view.textAlignment = .left
let firstTitleString = "By registering for THIS_APP I agree with the "
let secondTitleString = "Terms & Conditions"
let finishTitleString = firstTitleString + secondTitleString
let attributedString = NSMutableAttributedString(string: finishTitleString)
attributedString.addAttribute(.link, value: "https://stackoverflow.com", range: NSRange(location: firstTitleString.count, length: secondTitleString.count))
view.attributedText = attributedString
view.textContainerInset = .zero
view.linkTextAttributes = [
.foregroundColor: UIColor.blue,
.underlineStyle: NSUnderlineStyle.single.isEmpty
]
view.font = view.font = UIFont(name: "YOUR_FONT_NAME", size: 16)
view.textColor = UIColor.black
return view }()