File Upload in asp.net mvc3 - asp.net-mvc

Question

I'm currently using Entity Framework Code First approach for my asp.net MVC3(aspx syntax) project.
I have a model in my project called EmployeeModel
public class EmployeeModel
{
public string imageinfo;
public string fileinfo;
}
My DbContext is
public class ContextDB:DbContext
{
public DbSet<EmployeeModel> Employee { get; set; }
}
I would like to have a file browser for both fileinfo and imageinfo in my view to upload the files and images and the path of the files and images need to be stored in the database.
Can anyone please help?

Answer 1

Try using
.chtml
#using (Html.BeginForm("Index", "Home", FormMethod.Post, new { enctype = "multipart/form-data" }))
{
<input type="file" name="file" />
<input type="submit" value="OK" />
}
Controller
public class HomeController : Controller
{
// This action renders the form
public ActionResult Index()
{
return View();
}
// This action handles the form POST and the upload
[HttpPost]
public ActionResult Index(HttpPostedFileBase file)
{
// Verify that the user selected a file
if (file != null && file.ContentLength > 0)
{
// extract only the fielname
var fileName = Path.GetFileName(file.FileName);
// store the file inside ~/App_Data/uploads folder
var path = Path.Combine(Server.MapPath("~/App_Data/uploads"), fileName);
file.SaveAs(path);
}
// redirect back to the index action to show the form once again
return RedirectToAction("Index");
}
}

Answer 2

In Asp.Net MVC we have to use HttpPostedFileBase for Uploaded files as shown below :-
Controller :
[HttpPost]
public ActionResult Upload(HttpPostedFileBase file)
{
if (file != null) // file here will have your posted file which you post from view
{
int byteCount = file.ContentLength; <---Your file Size or Length
byte[] yourfile = new byte[file.ContentLength];
file.InputStream.Read(yourfile , 0, file.ContentLength);
var doc1 = System.Text.UnicodeEncoding.Default.GetString(empfile);
// now doc1 will have your image in string format and you can save it to database.
}
}
View :
#using (Html.BeginForm("Upload", "Home", FormMethod.Post, new { enctype = "multipart/form-data" }))
{
<input type="file" name="file" />
<input type="submit" value="OK" />
}