Alright, i have a hw assignment to check if an inserted string is a palindrome. The string must first be inserted into a stack, a queue, and then compared. I have the program up and running, for me that is. My teacher, when trying to grade it experience(d) a run time error. Also, getline portable is a requirement of the assignment and came with the file and instructions.
This is the note from the teacher:
Check if a line is a palindrome. Ignore spaces? y/n y (her running the code)
Input line to check
(where she gets the runtime error)
175 [main] csc240Summer2014PE8Student 10060 open_stackdumpfile: Dumping stack trace to csc240Summer2014PE8Student.exe.stackdump
#include <iostream>
#include <stack>
#include <queue>
#include <string>
using namespace std;
istream& getline_portable( istream& is, string& str ) {
istream& ris = std::getline(is,str);
if ( str.size() && str[str.size()-1] == '\r' )
str.resize(str.size()-1);
return ris;
}
int main()
{
stack<char> s;
queue<char> q;
char c, choice, b;
string str;
int i = 0;
int count = 0;
do
{
cout<<"Check if a line is a palindrome. Ignore spaces? y/n ";
cin >> b;
cin.ignore();
tolower(b);
cout<<"Input line to check\n";
getline_portable(cin,str);
for(int j = 0; j < str.size(); j++)
str[j] = tolower(str[j]);
if(b == 'n')
{
for(int j = 0; j < str.size(); j++)
{
c = str[j];
q.push(c);
s.push(c);
}
}
else if (b == 'y')
{
for(int j = 0; j < str.size() - count; j++)
{
c = str[j];
if(isspace(c))
{
}
else if(!isspace(c))
{
q.push(c);
s.push(c);
}
}
}
do
{
if(q.front() != s.top())
{
i = false;
break;
}
else
{
i = true;
s.pop();
q.pop();
}
}while(!q.empty() && !s.empty());
if (i == true)
cout << str << " is a pallindrom.\n";
else if (i == false)
cout << "Your input of " << str << " is not a pallindrome.\n";
cout << "Would you like to test another string? y/n ";
cin >> choice;
tolower(choice);
cin.ignore();
}while (choice == 'y');
cout << "Press enter to continue...";
cin.get();
return 0;
}
Related
I'm trying to create a char matrix using dynamic allocation (char**). It represents a board where the margins are '#' character and in the middle is the ASCII 32 (blank space). When I run the code this massage appear: "Exception thrown at 0x00007FFD9ABF024E (ucrtbased.dll) in myapp.exe: 0xC0000005: Access violation reading location " in some cpp file.
Here's my code:
#include <iostream>
using namespace std;
char** allocateBoard(int n)
{
char** Board = 0;
Board = new char* [n+2];
int i;
for (i = 0; i < n + 2; i++)
{
Board[i] = new char[n * 2 + 2];
}
return Board;
}
void initBoard(char**& Board, int n)
{
int i, j;
for (i = 0; i < n; i++)
{
for (j = 0; j < n * 2; j++)
{
if (i == 0 || i == n - 1) Board[i][j] = '#';
else if (j == 0 || j == n * 2 - 1) Board[i][j] = '#';
else Board[i][j] = 32;
}
}
}
void showBoard(char** Board, int n)
{
int i, j;
for (i = 0; i < n; i++)
{
for (j = 0; j < n * 2; j++)
{
cout << Board[i][j];
}
cout << endl;
}
}
int main()
{
int n = 4;
char** Board = 0;
Board = allocateBoard(n);
initBoard(Board, n);
showBoard(Board, n);
cout << endl;
showBoard(Board, n);
for (int i = 0; i < n * 2 + 4; i++)
{
delete[] Board[i];
}
delete[] Board;
return 0;
}
Does anyone know where is the problem? As a very beginner I can't see where is the mistake. I've allocated more space in the matrix than I'm actually using so I can't figure why this message appears. Is the deallocation the problem?
Thanks!
Use a circular singly linked list to implement Round Robin process scheduling algorithm in which
each process is provided a fixed time (quantum) to execute and is pre-empted after that time period
to allow the other process to execute. Assume a set of ‘n’ processes are ready for execution.
Read the time quantum and for each of the processes, read the total execution time.
Name the processes as ‘A’, ‘B’ and so on in sequence. Each node should contain the name
of the process, its total execution time and the remaining execution time. If a process
completes its execution, remove it from the list after displaying its name and the
completion time.
Input format:
First line contains the value of ‘n’, the number of processes
Second line contains the time quantum
The remaining lines contain the total execution time of the processes in order.
5
2
6
3
7
5
1
Output:
E 9
B 12
A 18
D 21
C 22
#include <iostream>
using namespace std;
class node
{
public:
char name;
int tm;
int rt;
node *next;
};
class rr
{
public:
node * Head = NULL;
int j = 65;
void insert (int n)
{
node *nn = new node;
nn->name = j++;
nn->tm = n;
nn->rt = nn->tm;
if (Head == NULL)
{
Head = nn;
Head->next = Head;
}
else
{
node *temp = Head;
while (temp->next != Head)
temp = temp->next;
nn->next = temp->next;
temp->next = nn;
}
}
void quantum (int t)
{
node *temp = Head;
int c = 0, i = 0;
while (Head != NULL)
{
{
temp->rt = temp->rt - t;
c = c + t;
if (temp->rt <= 0)
{
c = c + temp->rt;
cout << temp->name;
cout << c << endl;
del (temp->name);
if (temp->next == temp)
{
break;
}
}
temp = temp->next;
}
}
}
void del (char x)
{
node *p = NULL;
node *temp = Head;
if (Head->name == x)
{
while (temp->next != Head)
temp = temp->next;
p = Head;
temp->next = Head->next;
Head = Head->next;
delete p;
}
else
{
while (temp->name != x)
{
p = temp;
temp = temp->next;
}
p->next = temp->next;
delete temp;
}
}
};
int
main ()
{
rr robin;
int i, n, x, y, t;
cin >> y;
cin >> t;
for (i = 0; i < y; i++)
{
cin >> n;
robin.insert (n);
}
robin.quantum (t);
return 0;
}
I need to make a c program that will make a histogram of all the letters present in a phrase the user gives. When I run it, I does it but gives a "* stack smashing detected *: terminated". Where would this error be coming from? (for ease right now I set max to 3). In the future i'll have it find the max
Thank you
Andrew
#include <stdio.h>
#include <ctype.h>
#include <string.h>
static void ReadText(int histo[26],int max) {
char phrase[100];
int i;
char Letter;
char toArray;
// read in phrase
printf("Enter Phrase: "); // reads in phrase with spaces between words
scanf("%[^\n]",phrase);
// count the number of certain letters that occur
for(i = 0; i <= strlen(phrase);++i) {
Letter = phrase[i];
if(isalpha(Letter) != 0){
Letter = tolower(Letter);
toArray = Letter - 97;
histo[(int)toArray] = histo[(int)toArray] + 1;
}
}
}
static void DrawHist(int histo[26], int max){
int i;
int j;
int histo2[50];
for(i = 0; i <= 26; i++) {
histo2[i+i] = histo[i];
if(i < 25) {
histo2[i+i+1] = 0;
}
}
// (i = 1; i <= 50; i++) {
// printf("%d",histo2[i]);
//}
//printf("\n");
for(i=max;i>0;--i) {
for(j=0;j<=51;++j) {
if((j < 51) && (histo2[j] >= i)) {
printf("|");
}
else if((j < 51) && (histo2[j] < i)){
printf(" ");
}
else if(j == 51){
printf("\n");
}
}
}
printf("+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-\n");
printf("A B C D E F G H I J K L M N O P Q R S T U V W X Y Z\n");
}
int main() {
int histo[26] = {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
int max = 3;
//int i;
ReadText(histo,max);
//for(i = 0; i<26;++i) {
// printf("%d",histo[i]);
//}
DrawHist(histo,max);
return 0;
}
I have a trivial problem but I don't know how to solve it. I just wanna do a simple "foreach" of a Mat to view rgb values. I have next code:
for(int i=0; i<mat.rows; i++)
{
for(int j=0; j<mat.cols; j++)
{
int value_rgb = mat.at<uchar>(i,j);
cout << "(" << i << "," << j << ") : " << value_rgb <<endl;
}
}
The mat is 200 rows x 200 cols. When I print on console the results, just in the final the programs fails with next error:
**OpenCV Error: Assertion failed (dims <= 2 && data && (unsigned)i0 <(unsigned)size.p[0] && (unsigned)(i1*DataType<_Tp>::channels) < (unsigned)(size.p[1]*channels()) && ((((sizeof(size_t)<<28)|0x8442211) >> ((DataType<_Tp>::depth) & ((1 << 3) - 1))*4) & 1 5) == elemSize1()) in unknown function, file c:\opencv\build\include\opencv2\core\mat.hpp, line 537**
Anyone can help me?
Thanks.
The below piece of code will help you in accessing the rgb pixel values.You have to access three channels to view RGB values.
for(int i = 0; i < i<mat.rows; i++)
{
for(int j = 0; j < mat.cols; j++)
{
int b = mat.at<cv::Vec3b>(i,j)[0];
int g = mat.at<cv::Vec3b>(i,j)[1];
int r = mat.at<cv::Vec3b>(i,j)[2];
cout << r << " " << g << " " << b << value_rgb <<endl ;
}
}
To read pixel value from a grayscale image
#include <opencv\cv.h>
#include <highgui\highgui.hpp>
using namespace std;
using namespace cv;
int main()
{
cv::Mat img = cv::imread("5.jpg",0);
for(int j=0;j<img.rows;j++)
{
for (int i=0;i<img.cols;i++)
{
int a;
a=img.at<uchar>(j,i);
cout<<a<<endl;
}
}
cv::imshow("After",img);
waitKey(0);
}
Updated
This code reads all the grayscale values from an image and results in frequent occurring vales (Number of times the value as occurred). i.e
Number of times pixel value '0' as appeared,
Number of times pixel value '1' as appeared, ... & so on till 256.
#include <opencv\cv.h>
#include <highgui\highgui.hpp>
using namespace std;
using namespace cv;
int main()
{
cv::Mat img = cv::imread("5.jpg",0);
//for(int j=0;j<img.rows;j++)
//{
// for (int i=0;i<img.cols;i++)
// {
// int a;
// a=img.at<uchar>(j,i);
// cout<<a<<endl;
// }
//}
vector<int> values_rgb;
for(int i=0; i<20; i++)
{
for(int j=0; j<20; j++)
{
int value_rgb = img.at<uchar>(i,j);
values_rgb.push_back(value_rgb);
//cout << "(" << i << "," << j << ") : " << value_rgb <<endl;
}
}
// Sorting of values in ascending order
vector<int> counter_rg_values;
for(int l=0; l<256; l++)
{
for(int k=0; k<values_rgb.size(); k++)
{
if(values_rgb.at(k) == l)
{
counter_rg_values.push_back(l);
}
}
}
//for(int m=0;m<counter_rg_values.size();m++)
//cout<<m<<" "<< counter_rg_values[m] <<endl;
int m=0;
for(int n=0;n<256;n++)
{
int c=0;
for(int q=0;q<counter_rg_values.size();q++)
{
if(n==counter_rg_values[q])
{
//int c;
c++;
m++;
}
}
cout<<n<<"= "<< c<<endl;
}
cout<<"Total number of elements "<< m<<endl;
cv::imshow("After",img);
waitKey(0);
}
I wrote a rot13.c program but I can tell something in my loop inside rot13_translate_string is causing the program to just print out blank lines.
Any thoughts?
Thank you!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char rot13_translate_character(char c)
{
if( 'A' <= c && c <= 'M' )
{
return c + 13;
}
else if( 'N' <= c && c <= 'Z' )
{
return c - 13;
}
else if( 'a' <= c && c <= 'm' )
{
return c + 13;
}
else if( 'n' <= c && c <= 'z' )
{
return c - 13;
}
else
{
return c;
}
}
char *rot13_translate_string(const char *str)
{
int len = strlen(str);
char *translation = calloc(len, sizeof(char));
int i;
do //****HERE IN THIS SECTION
{
/* Translate each character, starting from the end of the string. */
translation[len] = rot13_translate_character(str[len]);
len--;
} while( len < 0 ); //<
return translation;
}
And here is the main (part of the same file) - is the condition for my for i = 1 ok?
int main(int argc, char **argv)
{
if( argc < 2)
{
fprintf(stderr, "Usage: %s word [word ...]\n", argv[0]);
return 1;
}
/* Translate each of the arguments */
int i;
for( i = 1; i < argc; i++) //*****IS this right?
{
char *translation = rot13_translate_string( argv[i] );
fprintf(stdout, "%s\n", translation);
}
return 0;
}
As just it was pointed out by Janis is the control on the loop do ... while. It should be
while( len >= 0 );
A "while" loop runs while the control expression is true (and terminates once the expression becomes false). You define the variable len just before the loop and it cannot be <0.
So you never really enter in the loop.
You obtain a line for each input word because of fprintf(stdout, "%s\n", translation); line, where you print for each (empty) word a line (\n).
In other languages, for example in Pascal, there is "repeat until" loop construction, which continues to run until the control expression is true, and only after that it changes it terminates.
In that case you could use a condition with <0.
In C to follow the same logic you can use while loop and negate the condition. In your case
} while (! (len < 0) );