I am new to swift programming and I don't know how to call a method at regular interval of time. I have a demo app for service call but i don't know how can i call it at regular interval of time.
You can create an object of NSTimer() and call a function on definite time interval like this:
var updateTimer = NSTimer.scheduledTimerWithTimeInterval(15.0, target: self, selector: "callFunction", userInfo: nil, repeats: true)
this will call callFunction() every 15 sec.
func callFunction(){
print("function called")
}
Here is a simple example with start and stop functions:
private let kTimeoutInSeconds:NSTimeInterval = 60
private var timer: NSTimer?
func startFetching() {
self.timer = NSTimer.scheduledTimerWithTimeInterval(kTimeoutInSeconds,
target:self,
selector:Selector("fetch"),
userInfo:nil,
repeats:true)
}
func stopFetching() {
self.timer!.invalidate()
}
func fetch() {
println("Fetch called!")
}
If you get an unrecognized selector exception, make sure your class inherits from NSObject or else the timer's selector won't find the function!
Timer variant with a block (iOS 10, Swift 4)
let timer = Timer.scheduledTimer(withTimeInterval: 5, repeats: true) { (timer) in
print("I am called every 5 seconds")
}
Do not forget call invalidate method
timer.invalidate()
GCD approach (will tend to drift a bit late over time)
func repeatMeWithGCD() {
DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + 5) {
print("I am called every 5 seconds")
self.repeatMeWithGCD()//recursive call
}
}
Do not forget to create a return condition to prevent stackoverflow error
Related
How can I run a function every minute?
In JavaScript I can do something like setInterval, does something similar exist in Swift?
Wanted output:
Hello World once a minute...
var helloWorldTimer = NSTimer.scheduledTimerWithTimeInterval(60.0, target: self, selector: Selector("sayHello"), userInfo: nil, repeats: true)
func sayHello()
{
NSLog("hello World")
}
Remember to import Foundation.
Swift 4:
var helloWorldTimer = Timer.scheduledTimer(timeInterval: 60.0, target: self, selector: #selector(ViewController.sayHello), userInfo: nil, repeats: true)
#objc func sayHello()
{
NSLog("hello World")
}
If targeting iOS version 10 and greater, you can use the block-based rendition of Timer, which simplifies the potential strong reference cycles, e.g.:
weak var timer: Timer?
func startTimer() {
timer?.invalidate() // just in case you had existing `Timer`, `invalidate` it before we lose our reference to it
timer = Timer.scheduledTimer(withTimeInterval: 60.0, repeats: true) { [weak self] _ in
// do something here
}
}
func stopTimer() {
timer?.invalidate()
}
// if appropriate, make sure to stop your timer in `deinit`
deinit {
stopTimer()
}
While Timer is generally best, for the sake of completeness, I should note that you can also use dispatch timer, which is useful for scheduling timers on background threads. With dispatch timers, since they're block-based, it avoids some of the strong reference cycle challenges with the old target/selector pattern of Timer, as long as you use weak references.
So:
var timer: DispatchSourceTimer?
func startTimer() {
let queue = DispatchQueue(label: "com.domain.app.timer") // you can also use `DispatchQueue.main`, if you want
timer = DispatchSource.makeTimerSource(queue: queue)
timer!.schedule(deadline: .now(), repeating: .seconds(60))
timer!.setEventHandler { [weak self] in
// do whatever you want here
}
timer!.resume()
}
func stopTimer() {
timer = nil
}
For more information, see the the Creating a Timer section of Dispatch Source Examples in the Dispatch Sources section of the Concurrency Programming Guide.
For Swift 2, see previous revision of this answer.
If you can allow for some time drift here's a simple solution executing some code every minute:
private func executeRepeatedly() {
// put your code here
DispatchQueue.main.asyncAfter(deadline: .now() + 60.0) { [weak self] in
self?.executeRepeatedly()
}
}
Just run executeRepeatedly() once and it'll be executed every minute. The execution stops when the owning object (self) is released. You also can use a flag to indicate that the execution must stop.
Here's an update to the NSTimer answer, for Swift 3 (in which NSTimer was renamed to Timer) using a closure rather than a named function:
var timer = Timer.scheduledTimer(withTimeInterval: 60, repeats: true) {
(_) in
print("Hello world")
}
You can use Timer (swift 3)
var timer = Timer.scheduledTimerWithTimeInterval(60, target: self, selector: Selector("function"), userInfo: nil, repeats: true)
In selector() you put in your function name
In swift 3.0 the GCD got refactored:
let timer : DispatchSourceTimer = DispatchSource.makeTimerSource(flags: [], queue: DispatchQueue.main)
timer.scheduleRepeating(deadline: .now(), interval: .seconds(60))
timer.setEventHandler
{
NSLog("Hello World")
}
timer.resume()
This is specially useful for when you need to dispatch on a particular Queue. Also, if you're planning on using this for user interface updating, I suggest looking into CADisplayLink as it's synchronized with the GPU refresh rate.
Here is another version algrid's answer with an easy way to stop it
#objc func executeRepeatedly() {
print("--Do something on repeat--")
perform(#selector(executeRepeatedly), with: nil, afterDelay: 60.0)
}
Here's an example of how to start it and stop it:
override func viewWillAppear(_ animated: Bool) {
super.viewWillAppear(animated)
executeRepeatedly() // start it
}
override func viewWillDisappear(_ animated: Bool) {
super.viewWillDisappear(animated)
NSObject.cancelPreviousPerformRequests(withTarget: self) // stop it
}
timer = Timer.scheduledTimer(withTimeInterval: 60, repeats: true, block: myMethod)
func myMethod(_:Timer) {
...
}
or
timer = Timer.scheduledTimer(withTimeInterval: 60, repeats: true) { _ in
...
}
make sure to invalid the timer at some point like your time is no longer visible, or you object is deist
How to call function on time? Also How to Call only once time in swift 3?
i need to call one function one time only, so how can possible to call function only one time like after 3 seconds?
You can do something like,
DispatchQueue.main.asyncAfter(deadline: .now() + 3) {
yourFunction() // call your functin here
}
You can also use DispatchQueue.global().asyncAfter if you don't want to perform your task on main thread!
And refer this post to manage it one time only!
private let _onceToken = NSUUID().uuidString
DispatchQueue.once(token: _onceToken) {
print( "Do This Once!" )
DispatchQueue.main.asyncAfter(deadline: .now() + 3) {
yourFunction() // call your functin here
}
}
It will execute your method only once and delay your method for 3 seconds.
For start timer:
var timerUpdateArray:Timer!
func callTimer(){
self.timerUpdateArray = Timer.scheduledTimer(timeInterval: 1,
target: self, selector: #selector(yourFunc),
userInfo: nil, repeats: true)
}
For stop timer:
self.timerUpdateArray.invalidate()
This question already has answers here:
Why would a `scheduledTimer` fire properly when setup outside a block, but not within a block?
(3 answers)
Closed 6 years ago.
I've been trying to utilize Timer in Swift and I've simplified it town to the following:
func startTimer () {
timer = Timer.scheduledTimer(timeInterval: 0.1, target: self, selector: #selector(ViewController.test), userInfo: nil, repeats: true)
}
func test () {
print("FIRED")
}
I would like to call this from another function and have verified the startTimer function works, but the timer doesn't fire. Does this have something to do with the RunLoop? I'm fairly new to coding so any explanation would be appreciated.
Good Practice: In startTimer() check that the timer has not already been created and make the assignment. In stopTimer() check that the timer exists before calling invalidate, and set the timer back to nil.
Also, for your selector make sure you have the #objc prefix. You should be able to get a working timer with the code provided. Happy coding!
class SomeClass {
var timer: Timer?
func startTimer() {
guard timer == nil else { return }
timer = Timer.scheduledTimer(timeInterval: 0.1, target: self, selector: #selector(test), userInfo: nil, repeats: true)
}
func stopTimer() {
guard timer != nil else { return }
timer?.invalidate()
timer = nil
}
#objc func test() {
}
}
I want to call the method func adjustmentBestSongBpmHeartRate() every 1.1 second. I used Timer, but it doesn't work. I have read the document and found a lot of sample code, it still does work! Is there anything I missed?
timer = Timer.scheduledTimer(timeInterval: 1.1, target: self, selector: #selector(self.adjustmentBestSongBpmHeartRate), userInfo: nil, repeats: false)
timer.fire()
func adjustmentBestSongBpmHeartRate() {
print("frr")
}
I found that creating the timer in an OperationQueue Operation did not work. I assume this is because there is no runloop.
Therefore, the following code fixed my problem:
DispatchQueue.main.async {
// timer needs a runloop?
self.timeoutTimer = Timer.scheduledTimer(timeInterval: self.timeout, target: self, selector: #selector(self.onTimeout(_:)), userInfo: nil, repeats: false)
}
Timer methods with a selector are supposed to have one parameter: The timer itself. Thus your code should really look like this: 1
Timer.scheduledTimer(timeInterval: 1.1,
target: self,
selector: #selector(self.adjustmentBestSongBpmHeartRate(_:),
userInfo: nil,
repeats: false)
#objc func adjustmentBestSongBpmHeartRate(_ timer: Timer) {
print("frr")
}
Note that if your app only runs on iOS >= 10, you can use the new method that takes a block to invoke rather than a target/selector. Much cleaner and more type-safe:
class func scheduledTimer(withTimeInterval interval: TimeInterval,
repeats: Bool,
block: #escaping (Timer) -> Void) -> Timer
That code would look like this:
timer = Timer.scheduledTimer(withTimeInterval: 1.1,
repeats: false) {
timer in
//Put the code that be called by the timer here.
print("frr")
}
Note that if your timer block/closure needs access to instance variables from your class you have to take special care with self. Here's a good pattern for that sort of code:
timer = Timer.scheduledTimer(withTimeInterval: 1.1,
repeats: false) {
//"[weak self]" creates a "capture group" for timer
[weak self] timer in
//Add a guard statement to bail out of the timer code
//if the object has been freed.
guard let strongSelf = self else {
return
}
//Put the code that be called by the timer here.
print(strongSelf.someProperty)
strongSelf.someOtherProperty = someValue
}
Edit (updated 15 December)
1: I should add that the method you use in the selector has to use Objective-C dynamic dispatch. In Swift 4 and later, the individual methods you reference must be tagged with the #objc tag. In previous versions of Swift you could also declare the entire class that defines the selector with the #objc qualifier, or you could make the class that defined the selector a subclass of NSObject or any class that inherits from NSOBject. (It's quite common to define the method the timer calls inside a UIViewController, which is a subclass of NSObject, so it used to "just work".
Swift 3
In my case it worked after I added to my method the #obj prefix
Class TestClass {
private var timer: Timer?
func start() {
guard timer == nil else { return }
timer = Timer.scheduledTimer(timeInterval: 60, target: self, selector: #selector(handleMyFunction), userInfo: nil, repeats: false)
}
func stop() {
guard timer != nil else { return }
timer?.invalidate()
timer = nil
}
#objc func handleMyFunction() {
// Code here
}
}
Try this -
if #available(iOS 10.0, *) {
self.timer = Timer.scheduledTimer(withTimeInterval: 0.2, repeats: false, block: { _ in
self.update()
})
} else {
self.timer = Timer.scheduledTimer(timeInterval: 0.2, target: self, selector: #selector(self.update), userInfo: nil, repeats: false)
}
Mostly the problem must have been because of iOS version of mobile.
Swift 5, Swift 4 Simple way only call with Dispatch Queue Async
DispatchQueue.main.async
{
self.andicator.stopAnimating()
self.bgv.isHidden = true
Timer.scheduledTimer(withTimeInterval: 1.0, repeats: false, block: { _ in
obj.showAlert(title: "Successfully!", message: "Video save successfully to Library directory.", viewController: self)
})
}
I have solved the question asked by myself.
I'm using apple watch to control my iphone app.
I try to press a button on apple watch to present a new viewcontroller on iphone.
When I write Timer in override func viewDidLoad(), Timer doesn't work. I move Timer to override func viewWillAppear() it works.
I think maybe there's something wrong with controlling by apple watch
I found that if you try to initialize the timer directly at the class-level, it won't work if you're targeting a selector in that same class. When it fires, it can't find the selector.
To get around this, I only initialize the timer after the object containing the selector has been initialized. If it's in the same class, put the initialization code in the ViewDidLoad or similar. Just not in the initializer. Then it will work. No dispatch queue needed.
Also, you do not need to use a selector that accepts the timer as a parameter. You can, but contrary to the answer with a ton of votes, that's not actually true, or more specifically, it works fine for me without it, just as you have it without it.
By the way, I think the reason the dispatch queue worked is because you're forcing the timer to be created after the object was initializing, confirming my above statement.
let timer:Timer?
override func viewDidLoad(){
super.viewDidLoad()
timer = Timer.scheduledTimer(timeInterval: 1.1, target: self, selector: #selector(adjustmentBestSongBpmHeartRate), userInfo: nil, repeats: false)
timer.fire()
}
func adjustmentBestSongBpmHeartRate() {
print("frr")
}
Note: This is code typed from memory, not copied from Xcode so it may not compile, but hopefully you get the idea.
Swift3
var timer = Timer()
timer = Timer.scheduledTimer(timeInterval: 5, target: self, selector: #selector(self.compruebaConexion), userInfo: nil, repeats: true)
my two cents.
I read about "didLoad" and when invoking it.
so we can use a delay:
class ViewController: UIViewController {
var timer: Timer?
override func viewDidLoad() {
super.viewDidLoad()
startTimer()
}
final func killTimer(){
self.timer?.invalidate()
self.timer = nil
}
final private func startTimer() {
// make it re-entrant:
// if timer is running, kill it and start from scratch
self.killTimer()
let fire = Date().addingTimeInterval(1)
let deltaT : TimeInterval = 1.0
self.timer = Timer(fire: fire, interval: deltaT, repeats: true, block: { (t: Timer) in
print("hello")
})
RunLoop.main.add(self.timer!, forMode: RunLoopMode.commonModes)
}
I declared delay and it is giving me an error, I am trying to slow down the timer.
//Updates Timer
func updateTimer() {
var delay: Int
seconds += 1
self.timerLabel.text = String(self.seconds * 0.01)
timer = NSTimer.scheduledTimerWithTimeInterval(-2.0, target: self, selector: #selector(GameScene.delay), userInfo: nil, repeats: false)
The message is telling you that there is no selector for GameScene.delay. You need a func that matches this name. Note that because you have used "GameScene" rather than "gameScene", it may be a class, in which case you would need a "class func" called delay. However, more likely is you would want "self.delay" to be called. ie. one of
func delay(timer: NSTimer) { ... }
class func delay(timer: NSTimer) { ... }
Also, what are you trying to achieve with "-2.0"? You can't run a timer in the past - if will default to 0.1 if <= 0.
the selector portion of a NSTimer is meant to run a function so you declare the function then the timer should be placed outside of the function instead of inside the function
func updateTimer() {
var delay: Int
seconds += 1
self.timerLabel.text = String(self.seconds * 0.01)}
let timer = NSTimer.scheduledTimerWithTimeInterval(2.0, target: self, selector: #selector(self.updateTimer), userInfo: nil, repeats: false)
also could you be more specific when you say you are trying to slow down the timer so