File.rename(blog_path + '/' + project_path, File.expand_path(topic_name, blog_path))
I use these code to rename ruby file name, but I think there is a better way to write this functionality with less code since it includes blog_path two times.
The code is OK, but I think there is no need to expand_path here - this method creates an absolute path from the the relative one.
Also, it is good to use File.join to create a path instead just concatenate it with slash - it will be completely OS independent. So I would write your code like this:
File.rename(File.join(blog_path, project_path), File.join(blog_path, topic_name))
Or if you want to get rid of doubled blog_path, change working directory before doing a rename:
Dir.chdir(blog_path)
File.rename(project_path, topic_name)
More info on working with files and directories in Ruby you can find in the article: Ruby for Admins: Files and Directories.
Related
I think (correct me if I am wrong) that it is better to put a / at the end of most of url. Like this: http://www.myweb/file/
And not put / at the end of filenames: http://www.myweb/name.html
I have to correct that in a website with a lot of links. Is there a way I can do that in a fast way. For instance in some programs like Dreamweaver I can use find and replace.
The second case is quite easy with Dreamweaver:
- Find: .html/"
- Replace: .html"
But how can I say something like:
- Find: all the links that end with a directory. Like http://www.myweb/file
- Replace: the same link but with a / at the end. Like http://www.myweb/file/
Your approach may work but it is based on the assumption that all files have a file extension.
There is a distinct difference between the urls http://www.myweb/file and http://www.myweb/file/ because the latter could resolve to http://www.myweb/file/index.php, or any other in the default set configured in your web server. That URL could also reference a perfectly valid file which doesn't contain a file extension, such as if it were a REST endpoint.
So you are correct insofar as you should explicitly add a "/" if you are referring to a directory, for example if you are expecting the web server to look up the correct index page to respond, or doing a directory listing.
To replace the incorrect URLS, regular expressions are your friend.
To find all files which have an erroneous "/" you could use /\.(html|php|jpg|png)\//, adding as many different file extensions into that pipe-separated list as you like. You can then replace that with .$1 or .\1 depending on your tool.
An example of doing this with Perl would be:
perl -pi -e 's/\.(html|php|jpg|png)\//.\1/g' theFileYouWantToCheck.html
Of (if you're using a Linux-based system) you can automate that nicely with find:
find path/to/html/root -type f -name "*.html* | xargs perl -pi -e 's/\.(html|php|jpg|png)\//.\1/g'
which will find all html files in the directory and do an inline find and replace. Assuming you're using version control, it's then easy to see the changes it's applied :)
Update
Solving the problem for adding a slash to directories isn't trivial. The approach I'd take:
Write a script to recurse through your website structure locally, making a list of all files
Parse the HTML files to extract all href=".*" and replace them with href=".*/" only if the end of the URL isn't present in the list extracted by the first script.
Any text-based find and replace is not going to be aware of whether the link is actually to a file or not.
I have a series of folders that all have files I need linked to the database (via there file path). One option I could do is manually insert all the file paths into my database, however, this can be painful as the number of folders will keep increasing and manual uploading will take too much time.
Is there a way to write a ruby helper function that will search these folders and automatically add the path to the files into a column in my database?
All the file paths have a recognizable pattern, for example:
Tel/a_1/poi1/names.csv
Tel/a_2/poi1/names.csv
Tel/a_3/poi1/names.csv
I need a function that will occupy a field in my database with the path of each of these names.csv files. Very new to ruby and rails, so any help is greatly appreciated. Also, please let me know if anything is unclear.
Something like this should give u all the filenames in the folder, for you to manipulate:
Dir["Tel/**/**/*.csv].each do |file|
* update attribute of your model with the path of the file
end
Read about the Dir object too.
Thats a example to get all files.
Dir["Tel/a_*/poi1/names.csv"] return a Array with path about all files.
I wanted to make a generator that created files (and directories, etc...) based on already existing files in the app (for instance, the views or controllers). So if we had views set up like this
-app
-views
- layouts
- application.html.erb
- users
- index.html.erb
- show.html.erb
- etc ...
and I wanted to create files based on them I can do (with just ruby)
directories = Dir.entries("#{Rails.root}/app/views")
directories.each do |directory|
unless directory == "." or directory == ".."
files = Dir.entries("#{Rails.root}/app/views/#{directory}")
files.each do |file|
unless file == "." or file == ".."
text = File.read("#{Rails.root}/app/views/#{directory}/#{file}")
something #=> whatever else needs to go here to edit the file
something else #=> output_file.puts whatever
end
end
end
end
so this is basically what I would like to do with a generator so I can roll my code into a plugin and use it for other apps.
First question, how can I generate arbitrary files (with filenames based on existing filenames using the generator. Is it appropriate to cycle through the directories like I did above, grab the directory/file and generate files? Is there a way to do what I did using a simpler method (mine seems easily breakable).
Also, should I put all that read/format/write code inside the generator itself and just pass a string into the "initialize content" section of create_file or should I put it somewhere else. Or should I use the generator to create the bare files and populate it with an init script?
Is there a more rails type of way of populating generated files, or should I just shove all my formatting code inside the generator. If so, what is the appropriate way to approach this.
I am not sure if you want to know how generators are built in rails3 or not. The code you are showing is not very generator-like. In generators you can use all commands from Thor, which offers you a very powerful toolset of manipulating files, and injecting code (strings) into classes or files.
So I would most definitely fill your files inside a generator, because then it happens on user request, and the user can choose whether or not certain files need or can be overwritten or not.
Inside your gem, you will have a lib/generators folder, containing a templates folder, containing all files you might want to place inside the rails application.
From the Thor documentation, here is a nice example to construct files in a generator.
Hope this helps.
there's a simple API to use generators in Rails. here you can find a good guide:
http://guides.rubyonrails.org/generators.html
if you want to check some code:
https://github.com/coderloop/tamed_beast (I'm the author of its generators)
https://github.com/pilu/web-app-theme (another clean example)
If i want to move /lib/foo_bar.rb to /lib/tidy/foo_bar.rb or even /lib/tidy/somestuff/foo_bar.rb
must i declare FooBar to be module Tidy or module Tidy::Somestuff
in other words must the modules match the directory structure?
Yes, if you don't want to specify the load path. You can add lib/tidy to the LOAD_PATH and then Rails will find it, but it's easier to just stick with the conventions
Does Rails have an equivalent of the Server.MapPath method from ASP.NET? I've tried looking for one, but couldn't find anything.
Edit: I need this to generate a PDF with some images stored on the server. I know the relative path (URL) of the images, but I need an absolute path on disk to load them. I use FPDF for this and even though it says it accepts an URL, it doesn't seem to be the case (or I couldn't make it work).
It checked that it works with a hardcoded physical disk path and now I need to make it flexible.
Ruby has one: File.expand_path.
You can also use Rails.root to get the current path to rails project, then compose the path from there.
File.join(Rails.root, "public", "404.html")
File.expand_path("public/404.html", Rails.root)