Why does 0 = 0.5? - z3

I noticed some strange behavior with Z3 4.3.1 when working with .smt2 files.
If I do (assert (= 0 0.5)) it will be satisfiable. However, if I switch the order and do (assert (= 0.5 0)) it's not satisfiable.
My guess as to what is happening is that if the first parameter is an integer, it casts both of them to integers (rounding 0.5 down to 0), then does the comparison. If I change "0" to "0.0" it works as expected. This is in contrast to most programming languages I've worked with where if either of the parameters is a floating-point number, they are both cast to floating-point numbers and compared. Is this really the expected behavior in Z3?

I think this is a consequence of lack of type-checking; z3 is being too lenient. It should simply reject such queries as they are simply not well formed.
According to the SMT-Lib standard, v2 (http://smtlib.cs.uiowa.edu/papers/smt-lib-reference-v2.0-r10.12.21.pdf); page 30; the core theory is defined thusly:
(theory Core
:sorts ((Bool 0))
:funs ((true Bool) (false Bool) (not Bool Bool)
(=> Bool Bool Bool :right-assoc) (and Bool Bool Bool :left-assoc)
(or Bool Bool Bool :left-assoc) (xor Bool Bool Bool :left-assoc)
(par (A) (= A A Bool :chainable))
(par (A) (distinct A A Bool :pairwise))
(par (A) (ite Bool A A A))
)
:definition
"For every expanded signature Sigma, the instance of Core with that signature
is the theory consisting of all Sigma-models in which:
- the sort Bool denotes the set {true, false} of Boolean values;
- for all sorts s in Sigma,
- (= s s Bool) denotes the function that
returns true iff its two arguments are identical;
- (distinct s s Bool) denotes the function that
returns true iff its two arguments are not identical;
- (ite Bool s s) denotes the function that
returns its second argument or its third depending on whether
its first argument is true or not;
- the other function symbols of Core denote the standard Boolean operators
as expected.
"
:values "The set of values for the sort Bool is {true, false}."
)
So, by definition equality requires the input sorts to be the same; and hence the aforementioned query should be rejected as invalid.
There might be a switch to z3 or some other setting that forces more strict type-checking than it does by default; but I would've expected this case to be caught even with the most relaxed of the implementations.

Do not rely on the implicit type conversion of any solver. Instead,
use to_real and to_int to do explicit type conversions. Only send
well-typed formulas to the solver. Then Mohamed Iguernelala's examples become the following.
(set-logic AUFLIRA)
(declare-fun x () Int)
(assert (= (to_real x) 1.5))
(check-sat)
(exit)
(set-logic AUFLIRA)
(declare-fun x () Int)
(assert (= 1.5 (to_real x)))
(check-sat)
(exit)
Both of these return UNSAT in Z3 and CVC4. If instead, you really
wanted to find the model where x = 1 you should have instead used one
of the following.
(set-option :produce-models true)
(set-logic AUFLIRA)
(declare-fun x () Int)
(assert (= (to_int 1.5) x))
(check-sat)
(get-model)
(exit)
(set-option :produce-models true)
(set-logic AUFLIRA)
(declare-fun x () Int)
(assert (= x (to_int 1.5)))
(check-sat)
(get-model)
(exit)
Both of these return SAT with x = 1 in Z3 and CVC4.
Once you make all the type conversions explicit and deal only in well-typed formulas, the order of arguments to equality no longer matters (for correctness).

One of our interns, who worked on a conservative extension of SMT2 with polymorphism has noticed the same strange behavior, when he tried the understand how formulas mixing integers and reals are type-checked:
z3 (http://rise4fun.com/z3) says that the following example is SAT, and finds a model x = 1
(set-logic AUFLIRA)
(declare-fun x () Int)
(assert (= x 1.5))
(check-sat)
(get-model)
(exit)
But, it says that the following "equivalent" example in UNSAT
(set-logic AUFLIRA)
(declare-fun x () Int)
(assert (= 1.5 x))
(check-sat)
(exit)
So, this does not comply with the symmetric property of equality predicate. So, I think it's a bug.

Strictly speaking, Z3 is not SMT 2.0 compliant by default, and this is one of those cases. We can add
(set-option :smtlib2-compliant true)
and then this query is indeed rejected correctly.

Z3 is not the unique SMT solver that type-checks these examples:
CVC4 accepts them as well (even with option --smtlib-strict), and answers UNSAT in both cases of my formulas above.
Yices accepts them and answers UNSAT (after changing the logic to QF_LIA, because it does not support AUFLIRA).
With (set-logic QF_LIA), Z3 emits an error: (error "line 3 column 17: logic does not support reals").
Alt-Ergo says "typing error: Int and Real cannot be unified" in both cases. But Alt-Ergo's SMT2 parser is very limited and not heavily tested, as we concentrated on its native polymorphic language. So, it should not be taken as a reference.
I think that developers usually assume an "implicit" sub-typing relation between Int and Real. This is why these examples are successfully type-checked by Z3, CVC4 and Yices (and probably others as well).

Jochen Hoenicke gived the answer (on SMT-LIB mailing list) regarding "mixing reals and integers". Here it is:
I just wanted to point out, that the syntax may be officially correct.
There is an extension in AUFLIRA and AUFNIRA.
From http://smtlib.cs.uiowa.edu/logics/AUFLIRA.smt2
"For every operator op with declaration (op Real Real s) for some
sort s, and every term t1, t2 of sort Int and t of sort Real, the
expression
- (op t1 t) is syntactic sugar for (op (to_real t1) t)
- (op t t1) is syntactic sugar for (op t (to_real t1))
- (/ t1 t2) is syntactic sugar for (/ (to_real t1) (to_real t2)) "

One possible solution is
(declare-fun x () Real)
(declare-fun y () Real)
(assert (= x 0))
(assert (= y 0.5))
(check-sat)
(push)
(assert (= x y) )
(check-sat)
(pop)
and the output is
sat
unsat

Related

Why does Z3 return Unknown for these horn clauses

I am using Z3 to solve my horn clauses. In the body of Horn clauses uninterpreted predicates should be positive. However, I need negation of some of uninterpreted predicates.
I have seen some examples in which negation works fine. For instance Z3 would return sat for the following example:
(set-logic HORN)
(declare-fun inv (Int) Bool)
(assert (inv 0))
(assert (forall ((k Int)) (or (> k 10) (not (inv k)) (inv (+ k 1)))))
(check-sat)
But my example looks like the following for which Z3 returns unknown.
(set-logic HORN)
(declare-fun inv (Int ) Bool)
(declare-fun s ( Int ) Bool)
(assert (forall ((k Int) (pc Int))(=>(and (= pc 1)(= k 0)) (inv k ))))
(assert (forall ((k Int)(k_p Int)(pc Int)(pc_p Int))
(=>(and (inv k )(= pc 1)(= pc_p 2)(= k_p (+ k 1))(not (s pc ))(s pc_p ))
(inv k_p ))))
(check-sat)
I wonder if there is a way to rewrite my clauses to Horn clause fragment of Z3.
Your clauses are not in the Horn fragment because the predicate s is used with both polarities in the last assertion. So there are two occurrences of a predicate with positive polarity (both (s pc) and (inv k_p) are positive polarity).
A basic method to avoid polarity issues is to introduce an extra argument to s of type Bool. Consequently, you would also have to say what is the specification of s using Horn clauses so it all makes sense. The typical scenario is that s encodes the behavior of a recursive procedure and the extra Boolean argument to s would be the return value of the procedure s. Of course this encoding doesn't ensure that s is total or functional.
There is a second approach, which is to add an extra argument to "inv", where you let 's' be an array. Then the occurrences (not (s pc)) becomes (not (select s pc)), etc.
It all depends on the intent of your encoding for what makes sense.

Are equations with products of uninterpreted functions unsolvable in Z3

The following code
(declare-fun f (Int) Real)
(declare-fun g (Int) Real)
(declare-const x Int)
(declare-const y Int)
(assert (= (* (f x) (g y)) 1.0))
(check-sat)
(get-model)
returns "unknown", even though there is an obvious solution. Eliminating arguments to f and g (effectively making them constants?) results in "sat" with expected assignments. I guess, my question is: what is special about arithmetic with uninterpreted functions?
BTW, replacing * with + also results in "sat", so the issue is not about uninterpreted functions, per se, but about how they are combined.
Additional thoughts
Making the domain (very) finite does not help, e.g.,
(declare-fun f (Bool) Real)
(declare-fun g (Bool) Real)
(declare-const x Bool)
(declare-const y Bool)
(assert (= (* (f x) (g y)) 1.0))
(check-sat)
(get-model)
returns "unknown". This is odd given that f:Bool->Real is essentially just two variables f(False) and f(True) (of course, the solver has to recognize this).
Inability to handle non-linear arithmetic over real-valued uninterpreted functions is a very severe limitation because arrays are implemented as uninterpreted functions. So, for example,
(declare-const a (Array Int Real))
(assert (= (* (select a 1) (select a 1)) 1))
(check-sat)
(get-model)
returns "unknown". In other words, any non-linear algebraic expression on real array elements involving multiplication is unsolvable:'(
It's the non-liearity introduced by the multiplication that makes the problem hard to solve, not the uninterpreted functions. In fact, you can ask the solvers why by using the get-info command:
(set-logic QF_UFNIRA)
(declare-fun f (Int) Real)
(declare-fun g (Int) Real)
(declare-const x Int)
(declare-const y Int)
(assert (= (* (f x) (g y)) 1.0))
(check-sat)
(get-info :reason-unknown)
Here're some responses I got from various solvers:
Z3:
(:reason-unknown smt tactic failed to show goal to be sat/unsat (incomplete (theory arithmetic)))
CVC4:
(:reason-unknown incomplete)
MathSAT:
(error "sat, but with non-linear terms")
So, as the solvers themselves improve and start handling more nonliear arithmetic, you might get models eventually. But, in general, nonlinear problems will always be problematic as they are undecidable when integers are involved. (Since you can code Diophantine equations using non-linear terms.)
See also How does Z3 handle non-linear integer arithmetic? for a relevant discussion from 2012.
Removing uninterpreted functions
Even if you get rid of the uninterpreted functions, you'd still be in the unknown land, so long as you mix Int and Real types and non-linear terms:
(set-logic QF_NIRA)
(declare-const f Real)
(declare-const g Real)
(declare-const x Int)
(declare-const y Int)
(assert (= (+ (* f g) (to_real (+ x y))) 1.0))
(check-sat)
(get-info :reason-unknown)
Z3 says:
(:reason-unknown "smt tactic failed to show goal to be sat/unsat (incomplete (theory arithmetic))")
So, the issue would arise with mixed types and non-linear terms.

Using Z3 QFNRA tactic with datatypes: interaction or inlining

In Non-linear arithmetic and uninterpreted functions, Leonardo de Moura states that the qfnra-nlsat tactic hasn't been fully integrated with the rest of Z3 yet. I thought that the situation has changed in two years, but apparently the integration is still not very complete.
In the example below, I use datatypes purely for "software engineering" purposes: to organize my data into records. Even though there are no uninterpreted functions, Z3 still fails to give me a solution:
(declare-datatypes () (
(Point (point (point-x Real) (point-y Real)))
(Line (line (line-a Real) (line-b Real) (line-c Real)))))
(define-fun point-line-subst ((p Point) (l Line)) Real
(+ (* (line-a l) (point-x p)) (* (line-b l) (point-y p)) (line-c l)))
(declare-const p Point)
(declare-const l Line)
(assert (> (point-y p) 20.0))
(assert (= 0.0 (point-line-subst p l)))
(check-sat-using qfnra-nlsat)
(get-model)
> unknown
(model
)
However, if I manually inline all the functions, Z3 finds a model instantly:
(declare-const x Real)
(declare-const y Real)
(declare-const a Real)
(declare-const b Real)
(declare-const c Real)
(assert (> y 20.0))
(assert (= 0.0 (+ (* a x) (* b y) c)))
(check-sat-using qfnra-nlsat)
(get-model)
> sat
(model
(define-fun y () Real
21.0)
(define-fun a () Real
0.0)
(define-fun x () Real
0.0)
(define-fun b () Real
0.0)
(define-fun c () Real
0.0)
)
My question is, is there a way to perform such an inlining automatically? I'm fine with either one of these workflows:
Launch Z3 with a tactic that says "Inline first, then apply qfnra-nlsat. I haven't found a way to do so, but maybe I wasn't looking well enough.
Launch Z3 using some version of simplify to do the inlining. Launch Z3 the second time on the result of the first invocation (the inlined version).
In other words, how to make qfnra-nlsat work with tuples?
Thank you!
That's correct, the NLSAT solver is still not integrated with the other theories. At the moment, we can only use it if we eliminate all datatypes (or elements of other theories) before running it. I believe there is no useful existing tactic inside of Z3 at the moment though, so this would have to be done beforehand. In general it's not hard to compose tactics, e.g., like this:
(check-sat-using (and-then simplify qfnra-nlsat))
but the simplifier is not strong enough to eliminate the datatype constants in this problem. (The respective implementation files are datatype_rewriter.cpp and datatype_simplifier_plugin.cpp.)

Why operators '/' and 'div' in Z3 give different results?

I was trying to represent a real number with two integer numbers as using them as the numerator and the denominator of the real number. I wrote the following program:
(declare-const a Int)
(declare-const b Int)
(declare-const f Real)
(assert (= f (/ a b)))
(assert (= f 0.5))
(assert (> b 2))
(assert (> b a))
(check-sat)
(get-model)
The program returned SAT result as follows:
sat
(model
(define-fun f () Real
(/ 1.0 2.0))
(define-fun b () Int
4)
(define-fun a () Int
2)
)
However, if I write '(assert (= f (div a b)))' instead of '(assert (= f (/ a b)))', then the result is UNSAT. Why does not div return the same result?
Moreover, and the main concern for me, I did not find a way to use operator '/' in z3 .Net API. I can see only function MkDiv, which actually for operator 'div'. Is there a way so that I can apply operator '/' in the case of z3 .Net API? Thank you in advance.
Strictly speaking neither of these formulas is SMT-LIB2 compliant, because / is a function that takes two Real inputs and produces a Real output, whereas div is a function that takes two Int inputs and produces an Int (see SMT-LIB Theories). Z3 is more relaxed and automatically converts those objects. If we enable the option smtlib2_compliant=true then it will indeed report an error in both cases.
The reason for the div version being unsatisfiable is that there is indeed no solution where f is an integer according to (= f (/ a b)), but there is indeed no integer that satisfies (= f 0.5)

Sort Mismatch in Model

I have analyzed a formula in QF_AUFLIA with z3. The result was sat. The model returned by (get-model) contained the following lines:
(define-fun PCsc5_ () Int
(ite (= 2 false) 23 33)
According to my understanding of the SMTLIBv2 language, this statement is malformed. = should only be applied to arguments of the same sort. However, 2 has sort Int and false has sort Bool.
When I feed back just these two lines to z3, it agrees with me by saying:
invalid function application, sort mismatch on argument at position 2
Is this a bug?
If not, how am I supposed to interpret (= 2 false)?
The problem was due to a type error in the input. Z3 3.2 misses some type errors in macro applications. This problem was fixed. The next release will correctly report the type error (aka sort mismatch). Here is a minimal example that exposes the problem:
(set-option :produce-models true)
(declare-fun q (Int) Bool)
;; p1 is a macro
(define-fun p1 ((z Int) (y Int)) Bool
(ite (q y) (= z 0) (= z 1)))
(declare-const a Int)
(declare-const b Bool)
(assert (p1 a b)) ;; << TYPE ERROR: b must be an Int
(check-sat)
(get-model)

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