I have string as follows in objective c
NSString *str = #"access_token=E2JmCPLtVySGn-cGGJGGnQ&email=abc#gmail.com";
How can i get only E2JmCPLtVySGn-cGGJGGnQ ?
You can use a Regular Expression (RegEx) to find character patterns.
The pattern matching syntax can be found in the ICU User Guide Regular Expressions
In the example the pattern is: find the first "=" and all characters up to but not including the character "&". In the pattern '(?<=access_token=)" is a look-behind assertion meaning that the "access_token=" must precede the matched text, "[^&]+" the brackets the "[]" mean a character class, the "^" al but the following character, the "+" means one or more.
NSString *str = #"access_token=E2JmCPLtVySGn-cGGJGGnQ&email=abc#gmail.com";
NSString *regexPattern = #"(?<=access_token=)[^&]+";
NSString *found = nil;
NSRange range = [str rangeOfString:regexPattern options:NSRegularExpressionSearch];
if (range.location != NSNotFound) {
found = [str substringWithRange:range];
}
NSLog(#"Range: %#", NSStringFromRange(range));
NSLog(#"found: %#", found);
NSLog output if found:
Range: {13, 22}
found: E2JmCPLtVySGn-cGGJGGnQ
There is a method of the NSString class called rangeOfString: that returns an NSRange struct. If you know that your returned value always has the text access_token= and also includes &email and the format is always the same, you can use this rangeOfString: method to sniff out the token.
NSRange accessTokenRange = [str rangeOfString:#"access_token="];
//this would return (0,13) for index:0, length: 13
NSRange emailRange = [str rangeOfString:#"&email="];
//this would return (34,7)
NSInteger tokenLength = ( emailRange.location + 1 ) - accessTokenRange.length;
//the point where &email begins is at index 34, but it starts at 0
//so it's actually the 35th character
//the access_token= string is 13 characters long, so 35-13 = 22
//so you know that the actual token value is 22 characters long
NSRange trueTokenRange = NSMakeRange(accessTokenRange.length,tokenLength);
NSString *tokenSubstring = [str substringWithRange:trueTokenRange];
I don't think my math is off, zero indexing can introduce off by 1 errors if you're not careful, I usually have NSLog going on each range so I can double check where I need to add or subtract 1. But essentially you'll be starting at the 14th character, which is index 13 of the string, and reading the next 22 characters.
Related
I need to count characters in string before some string and after some string. For example, I have string "This is example string" and I need to know howmany characters are before word "example" (it is 8 chars in this case) and how many characters are after word "example" (7 in that case...). My idea was to loop that string and count every character, but how to stop it before that requied word? Thanks for every idea!
check this out
NSString *sample = #"This is example string";
NSRange b = [sample rangeOfString:#"example"];
if (b.location != NSNotFound) {
NSLog(#"%d characters before", b.location);
NSLog(#"%d characters after", [sample length] - b.location - b.length);
}
I'm wondering, is there a way to detect a character that takes up more than 1 index spot in an NSString? (like an emoji). I'm trying to implement a custom text view and when the user pushes delete, I need to know if I should delete only the previous one index spot or more.
Actually NSString use UTF-16.So it is quite difficult to work with characters which takes two UTF-16 charater(unichar) or more.But you can do with rangeOfComposedCharacterSequenceAtIndexto get range and than delete.
First find the last character index from string
NSUInteger lastCharIndex = [str length] - 1;
Than get the range of last character
NSRange lastCharRange = [str rangeOfComposedCharacterSequenceAtIndex: lastCharIndex];
Than delete with range from character (If it is of two UTF-16 than it deletes UTF-16)
deletedLastCharString = [str substringToIndex: lastCharRange.location];
You can use this method with any type of characters which takes any number of unichar
For one you could transform the string to a sequence of characters using [myString UTF8String] and you can then check if the character has its first bit set to one or zero. If its one then this is a UTF8 character and you can then check how many bytes are there to this character. Details about UTF8 can be found on Wikipedia - UTF8. Here is a simple example:
NSString *string = #"ČTest";
const char *str = [string UTF8String];
NSMutableString *ASCIIStr = [NSMutableString string];
for (int i = 0; i < strlen(str); ++i)
if (!(str[i] & 128))
[ASCIIStr appendFormat:#"%c", str[i]];
NSLog(#"%#", ASCIIStr); //Should contain only ASCII characters
For an app I'm working on, I need to check if a text field contains only the letters A, T, C, or G. Furthermore, I would like to make specialized error messages for any other inputed characters. ex) "Don't put in spaces." or "The letter b isn't an accepted value." I have read a couple other posts like this, but they are alphanumeric, I only want specified characters.
One approach for you, far from unique:
NString has methods to find substrings, represented as an NSRange of location & offset, made up from characters in a given NSCharacterSet.
The set of what should be in the string:
NSCharacterSet *ATCG = [NSCharacterSet characterSetWithCharactersInString:#"ATCG"];
And the set of what shouldn't:
NSCharacterSet *invalidChars = [ATCG invertedSet];
You can now search for any range of characters consisting of invalidChars:
NSString *target; // the string you wish to check
NSRange searchRange = NSMakeRange(0, target.length); // search the whole string
NSRange foundRange = [target rangeOfCharacterFromSet:invalidChars
options:0 // look in docs for other possible values
range:searchRange];
If there are no invalid characters then foundRange.location will be equal to NSNotFound, otherwise you change examine the range of characters in foundRange and produce your specialised error messages.
You repeat the process, updating searchRange based on foundRange, to find all the runs of invalid characters.
You could accumulate the found invalid characters into a set (maybe NSMutableSet) and produce the error messages at the end.
You can also use regular expressions, see NSRegularExpressions.
Etc. HTH
Addendum
There is a really simple way to address this, but I did not give it as the letters you give suggest to me you may be dealing with very long strings and using provided methods as above may be a worthwhile win. However on second thoughts after your comment maybe I should include it:
NSString *target; // the string you wish to check
NSUInteger length = target.length; // number of characters
BOOL foundInvalidCharacter = NO; // set in the loop if there is an invalid char
for(NSUInteger ix = 0; ix < length; ix++)
{
unichar nextChar = [target characterAtIndex:ix]; // get the next character
switch (nextChar)
{
case 'A':
case 'C':
case 'G':
case 'T':
// character is valid - skip
break;
default:
// character is invalid
// produce error message, the character 'nextChar' at index 'ix' is invalid
// record you've found an error
foundInvalidCharacter = YES;
}
}
// test foundInvalidCharacter and proceed based on it
HTH
Use NSRegulareExpression like this.
NSString *str = #"your input string";
NSRegularExpression *regEx = [NSRegularExpression regularExpressionWithPattern:#"A|T|C|G" options:0 error:nil];
NSArray *matches = [regEx matchesInString:str options:0 range:NSMakeRange(0, str.length)];
for (NSTextCheckingResult *result in matches) {
NSLog(#"%#", [str substringWithRange:result.range]);
}
Also for the options parameter you have to look in the documentation to pick one that fits.
Look at the NSRegularExpression class reference.
Visit: https://developer.apple.com/library/mac/documentation/Foundation/Reference/NSRegularExpression_Class/Reference/Reference.html
Im initializing a string from an URL as follow:
NSString* text = [NSString stringWithContentsOfURL:TheUrl encoding:NSASCIIStringEncoding error:&error];
The URL contains an s19 file, it seems like follow:
S111C019600FBDC09138BDC0353FBDFFCD16D0
S111C0272B024F3986FF393617BDFFB8323968
S110C035308F83000C8F35CCC350ED0AFD15
S111C0426000ED04ED02EC04ED00CCC08ABDFC
after this line I got the data into my text string. then I want to split the string to get an hex array, how can I do that? I was using the next line to get an array but It gives me the next (and it is right):
NSArray *arr = [text componentsSeparatedByString:#"\r\n"];
arr[0] --> S111C019600FBDC09138BDC0353FBDFFCD16D0
How can I split my text string into bytes/words values? something like this:
arr[0] --> C0
arr[1] --> 19
arr[2] --> 60
You can use a for loop and substringWithRange:, building up the range location as you iterate. The length of the range dictates how much you're taking from the original string on each iteration.
Something along the lines of:
NSRange range = NSMakeRange(0, 2);
while (range.location + range.length < sourceString.length) {
[array addObject:[sourceString substringWithRange:range];
range.location += range.length;
}
I am making an app where there is a requirement to store ASCII art into a database. I store the strings in the below format.
"___________\n |---------|-O\n/___________\\n|______________|\n\____________/"
When I retrieve the data and display it in a label, I want the newline characters and backslashes to be parsed so as to display the real shape of the ASCII art.
How should I parse this kind of strings?
NSString has a method to do what you want, which is to replace a litteral \n, with a newline character (which is symbolized as \n). In a c-format string you can use a double slash to let the library know the second slach is a real one and not an escape symbol. So this should work assuming you have been able to load your data from sqlite into an NSString:
newString = [yourStringFromSQLite stringByReplacingOccurrencesOfString:#"\\n" withString:#"\n"];
If you are using \n just for creating new lines then instead of that just keep space while inserting value in database and set following properties for label ->
1)keep width just to fit first word.
2)linebreakmode to wordwrap (so as width will not be available it will wrap next word to new line)
3)set no. of lines to 0
Hope this will help.
try to use the scanner for remove the html entities
- (NSString *)flattenHTML:(NSString *)html trimWhiteSpace:(BOOL)trim {
NSScanner *theScanner;
NSString *text = nil;
theScanner = [NSScanner scannerWithString:html];
while ([theScanner isAtEnd] == NO) {
[theScanner scanUpToString:#"<" intoString:NULL] ;
[theScanner scanUpToString:#">" intoString:&text] ;
html = [html stringByReplacingOccurrencesOfString:[ NSString stringWithFormat:#"%#>", text] withString:#" "];
}
return trim ? [html stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]] : html;
}
and call this method where your trimmed string need to display