UIImage on swift can't check for nil - ios

Question

I have the following code on Swift
var image = UIImage(contentsOfFile: filePath)
if image != nil {
return image
}
It used to work great, but now on Xcode Beta 6, this returns a warning
'UIImage' is not a subtype of 'NSString'
I don't know what to do, I tried different things like
if let image = UIImage(contentsOfFile: filePath) {
return image
}
But the error changes to:
Bound value in a conditional binding must be of Optional type
Is this a bug on Xcode6 beta 6 or am I doing something wrong?

Answer 1

Update
Swift now added the concept of failable initializers and UIImage is now one of them. The initializer returns an Optional so if the image cannot be created it will return nil.
Variables by default cannot be nil. That is why you are getting an error when trying to compare image to nil. You need to explicitly define your variable as optional:
let image: UIImage? = UIImage(contentsOfFile: filePath)
if image != nil {
return image!
}

Answer 2

The simplest way to check if an image has content (> nil) is:
if image.size.width != 0 { do someting}

Answer 3

func imageIsNullOrNot(imageName : UIImage)-> Bool
{
let size = CGSize(width: 0, height: 0)
if (imageName.size.width == size.width)
{
return false
}
else
{
return true
}
}
the Above method call Like as :
if (imageIsNullOrNot(selectedImage))
{
//image is not null
}
else
{
//image is null
}
here, i check image size.

Answer 4

Init, that you are call init?(contentsOfFile path: String) the ? means that it returns optional value.
You should check optional vars for nil before use it.
Shorter, than accepted answer and Swift-style way, than named Optional Chaining to do that:
if let image = UIImage(contentsOfFile: filePath) {
return image
}

Answer 5

You can check it's imageAsset like this:
if image.imageAsset != nil
{
// image is not null
}
else
{
//image is null
}

Answer 6

You can check for it's width, which would be 0 if no image is uploaded.
if(image.size.width != 0){
print("image found")
} else {
print("image is null")
}