Erlang pattern not matching, but correct, what to do? - erlang

i have an crazy problem with pattern matching in erlang:
My receive block:
...
receive
{set_val,Val} ->
log("got: ~p",[Val]);
Any ->
log("~p is an unknown command",[Any])
end.
What I send:
...
{myreceive,myreceive#workstation} ! {set_val,100}
What in my Log appears:
{set_val,100} is an unknown command
how come, that the first pattern does not match? (and how to make it matching :/ )

The only possibility I see is that Val is already bound in your function to a value different from 100.

It seems to work as expected.
1> spawn(fun() -> receive {set_val, Val} -> io:format("got: ~p~n", [Val]); Any -> io:format("~p is an unknown command",[Any]) end end) ! {set_val,100}.
got: 100
{set_val,100}
As Pascal mentioned there have to be variable Val already bound to something different from 100.

Related

Difference ok and end [Erlang]

What is the difference in ending a function with end and ok in Erlang? I've been trying to grasp the meaning in the following code:
-module(esOne).
-export([start/1, func/1]).
start(Par) ->
io:format("Client: I am ~p, spawned by the server: ~p~n",[self(),Par]),
spawn(esOne, func, [self()]),
Par ! {onPid, self()},
serverEsOne ! {onName, self()},
receiveMessage(),
ok.
receiveMessage() ->
receive
{reply, N} ->
io:format("Client: I received a message: ~p~n",[N])
after
5000->
io:format("Client: I received no message, i quit~n",[])
end.
func(Parent)->
io:format("Child: I am ~p, spawned from ~p~n",[self(),Parent]).
This code works in conjunction with another .erl file that acts as server. I managed to write this only through analyzing the given server file and copying it's behavior. First I thought ok was used to end every function, but that is not the case as I can't end receiveMessage() with ok. Then I thought I could maybe end every function with end, but start(Par) will give an error if I replace ok by end. Not only that, but in the server file I see that ok and end are used within functions to end loops. The way they're used look the same to me, yet they clearly fulfill a separate function as one cannot be replaced by another. Some clarification would be much appreciated.
Two points to understand:
Some code block types in Erlang are closed with an "end". So if ... end, case ... end, receive ... [after N] ... end and so on. It is certainly possible to use "end" as its own atom in place of OK, but that is not what is happening above.
Every function in Erlang returns some value. If you aren't explicit about it, it returns the value of the last expression. The "=" operator isn't assignment to a variable like in other languages, it is assignment to a symbol as in math, meaning that reassigning is effectively a logical assertion. If the assertion fails, the process throws an exception (meaning it crashes, usually).
When you end something with "ok" or any other atom you are providing a known final value that will be returned. You don't have to do anything with it, but if you want the calling process to assert that the function completed or crash if anything unusual happened then you can:
do_stuff() ->
ok = some_func().
instead of
do_stuff() ->
some_func().
If some_func() may have had a side effect that can fail, it will usually return either ok or {error, Reason} (or something similar). By checking that the return was ok we prevent the calling process from continuing execution if something bad happened. That is central to the Erlang concept of "let it crash". The basic idea is that if you call a function that has a side-effect and it does anything unexpected at all, you should crash immediately, because proceeding with bad data is worse than not proceeding at all. The crash will be cleaned up by the supervisor, and the system will be restored to a known state instead of being in whatever random condition was left after the failure of the side-effect.
A variation on the bit above is to have the "ok" part appear in a tuple if the purpose of a function is to return a value. You can see this in any dict-type handling library, for example. The reason some data returning functions have a return type of {ok, Value} | {error, Reason} instead of just Value | {error, Reason} is to make pattern matching more natural.
Consider the following case clauses:
case dict:find(Key, Dict) of
{ok, Value} ->
Value;
{error, Reason} ->
log(error, Reason),
error
end.
And:
case finder(Key, Struct) of
Value ->
Value;
{error, Reason}
log(error, Reason),
error
end.
In the first example we match the success condition first. In the second version, though, this is impossible because the error clause could never match; any return at all would always be represented by Value. Oops.
Most of the time (but not quite always) functions that return a value or crash will return just the value. This is especially true of pure functions that carry no state but what you pass in and have no side effects (for example, dict:fetch/2 gives the value directly, or crashes the calling process, giving you an easy choice which way you want to do things). Functions that return a value or signal an error usually wrap a valid response in {ok, Value} so it is easy to match.

Mnesia Query Cursors - Working with them in Practical applications

In most applications, its hard to avoid the need to query large amounts of information which a user wants to browse through. This is what led me to cursors. With mnesia, cursors are implemented using qlc:cursor/1 or qlc:cursor/2. After working with them for a while and facing this problem many times,
11> qlc:next_answers(QC,3).
** exception error: {qlc_cursor_pid_no_longer_exists,<0.59.0>}
in function qlc:next_loop/3 (qlc.erl, line 1359)
12>
It has occured to me that the whole cursor thing has to be within one mnesia transaction: executes as a whole once. like this below
E:\>erl
Eshell V5.9 (abort with ^G)
1> mnesia:start().
ok
2> rd(obj,{key,value}).
obj
3> mnesia:create_table(obj,[{attributes,record_info(fields,obj)}]).
{atomic,ok}
4> Write = fun(Obj) -> mnesia:transaction(fun() -> mnesia:write(Obj) end) end.
#Fun<erl_eval.6.111823515>
5> [Write(#obj{key = N,value = N * 2}) || N <- lists:seq(1,100)],ok.
ok
6> mnesia:transaction(fun() ->
QC = cursor_server:cursor(qlc:q([XX || XX <- mnesia:table(obj)])),
Ans = qlc:next_answers(QC,3),
io:format("\n\tAns: ~p~n",[Ans])
end).
Ans: [{obj,20,40},{obj,21,42},{obj,86,172}]
{atomic,ok}
7>
When you attempt to call say: qlc:next_answers/2 outside a mnesia transaction, you will get an exception. Not only just out of the transaction, but even if that method is executed by a DIFFERENT process than the one which created the cursor, problems are bound to happen.
Another intresting finding is that, as soon as you get out of a mnesia transaction, one of the processes which are involved in a mnesia cursor (apparently mnesia spawns a process in the background), exits, causing the cursor to be invalid. Look at this below:
-module(cursor_server).
-compile(export_all).
cursor(Q)->
case mnesia:is_transaction() of
false ->
F = fun(QH)-> qlc:cursor(QH,[]) end,
mnesia:activity(transaction,F,[Q],mnesia_frag);
true -> qlc:cursor(Q,[])
end.
%% --- End of module -------------------------------------------
Then in shell, i use that method:
7> QC = cursor_server:cursor(qlc:q([XX || XX <- mnesia:table(obj)])).
{qlc_cursor,{<0.59.0>,<0.30.0>}}
8> erlang:is_process_alive(list_to_pid("<0.59.0>")).
false
9> erlang:is_process_alive(list_to_pid("<0.30.0>")).
true
10> self().
<0.30.0>
11> qlc:next_answers(QC,3).
** exception error: {qlc_cursor_pid_no_longer_exists,<0.59.0>}
in function qlc:next_loop/3 (qlc.erl, line 1359)
12>
So, this makes it very Extremely hard to build a web application in which a user needs to browse a particular set of results, group by group say: give him/her the first 20, then next 20 e.t.c. This involves, getting the first results, send them to the web page, then wait for the user to click NEXT then ask qlc:cursor/2 for the next 20 and so on. These operations cannot be done, while hanging inside a mnesia transaction !!! The only possible way, is by spawning a process which will hang there, receiving and sending back next answers as messages and receiving the next_answers requests as messages like this:
-define(CURSOR_TIMEOUT,timer:hours(1)).
%% initial request is made here below
request(PageSize)->
Me = self(),
CursorPid = spawn(?MODULE,cursor_pid,[Me,PageSize]),
receive
{initial_answers,Ans} ->
%% find a way of hidding the Cursor Pid
%% in the page so that the subsequent requests
%% come along with it
{Ans,pid_to_list(CursorPid)}
after ?CURSOR_TIMEOUT -> timedout
end.
cursor_pid(ParentPid,PageSize)->
F = fun(Pid,N)->
QC = cursor_server:cursor(qlc:q([XX || XX <- mnesia:table(obj)])),
Ans = qlc:next_answers(QC,N),
Pid ! {initial_answers,Ans},
receive
{From,{next_answers,Num}} ->
From ! {next_answers,qlc:next_answers(QC,Num)},
%% Problem here ! how to loop back
%% check: Erlang Y-Combinator
delete ->
%% it could have died already, so we be careful here !
try qlc:delete_cursor(QC) of
_ -> ok
catch
_:_ -> ok
end,
exit(normal)
after ?CURSOR_TIMEOUT -> exit(normal)
end
end,
mnesia:activity(transaction,F,[ParentPid,PageSize],mnesia_frag).
next_answers(CursorPid,PageSize)->
list_to_pid(CursorPid) ! {self(),{next_answers,PageSize}},
receive
{next_answers,Ans} ->
{Ans,pid_to_list(CursorPid)}
after ?CURSOR_TIMEOUT -> timedout
end.
That would create a more complex problem of managing process exits, tracking / monitoring e.t.c. I wonder why the mnesia implementers didnot see this !
Now, that brings me to my questions. I have been walking around the web for solutions and you could please check out these links from which the questions arise: mnemosyne, Ulf Wiger's Solution to Cursor Problems, AMNESIA - an RDBMS implementation of mnesia.
1. Does anyone have an idea on how to handle mnesia query cursors in a different way from what is documented, and is worth sharing ?
2. What are the reasons why mnesia implemeters decided to force the cursors within a single transaction: even the calls for the next_answers ?
3. Is there anything, from what i have presented, that i do not understand clearly (other than my bad buggy illustration code - please ignore those) ?
4. AMNESIA (on section 4.7 of the link i gave above), has a good implementation of cursors, because the subsequent calls for the next_answers, do not need to be in the same transaction, NOR by the same process. Would you advise anyone to switch from mnesia to amnesia due to this and also, is this library still supported ?
5. Ulf Wiger , (the author of many erlang libraries esp. GPROC), suggests the use of mnesia:select/4. How would i use it to solve cursor problems in a web application ? NOTE: Please do not advise me to leave mnesia and use something else, because i want to use mnesia for this specific problem. I appreciate your time to read through all this question.
The motivation is that transaction grabs (in your case) read locks.
Locks can not be kept outside of transactions.
If you want, you can run it in a dirty_context, but you loose the
transactional properties, i.e. the table may change between invocations.
make_cursor() ->
QD = qlc:sort(mnesia:table(person, [{traverse, select}])),
mnesia:activity(async_dirty, fun() -> qlc:cursor(QD) end, mnesia_frag).
get_next(Cursor) ->
Get = fun() -> qlc:next_answers(Cursor,5) end,
mnesia:activity(async_dirty, Get, mnesia_frag).
del_cursor(Cursor) ->
qlc:delete_cursor(Cursor).
I think this may help you :
use async_dirty instead of transaction
{Record,Cont}=mnesia:activity(async_dirty, fun mnesia:select/4,[md,[{Match_head,[Guard],[Result]}],Limit,read])
then read next Limit number of records:
mnesia:activity(async_dirty, fun mnesia:select/1,[Cont])
full code:
-record(md,{id,name}).
batch_delete(Id,Limit) ->
Match_head = #md{id='$1',name='$2'},
Guard = {'<','$1',Id},
Result = '$_',
{Record,Cont} = mnesia:activity(async_dirty, fun mnesia:select/4,[md,[{Match_head,[Guard],[Result]}],Limit,read]),
delete_next({Record,Cont}).
delete_next('$end_of_table') ->
over;
delete_next({Record,Cont}) ->
delete(Record),
delete_next(mnesia:activity(async_dirty, fun mnesia:select/1,[Cont])).
delete(Records) ->
io:format("delete(~p)~n",[Records]),
F = fun() ->
[ mnesia:delete_object(O) || O <- Records]
end,
mnesia:transaction(F).
remember you can not use cursor out of one transaction

Problem with process creation

I am implementing a car park with 2 entry gates and 1 by which you can leave the park. For me, everything looks fine but I am getting errors like
Error in process <0.84.0> with exit value: {badarg,[{parking,car,2},{random,uniform,0}]}
My code is:
-module (parking2).
-export ([start/3]).
-export ([car/2, parkingLoop/1]).
carsInit(0, _Iterations) ->
ok;
carsInit(Number, Iterations) ->
spawn(parking, car, [Number, Iterations]),
carsInit(Number - 1, Iterations).
car(_ID, 0) ->
ok;
car(ID, Iterations) ->
Gate = random:uniform(2),
parking ! {enter, self()},
receive
error ->
io:format("Car ~B ncanot enter - there is no free place.~n", [ID]),
Time = random:uniform(1000),
timer:sleep(Time),
car(ID, Iterations);
ok ->
io:format("Car ~B entered through the ~B gate~n", [ID, Gate])
end,
StopTime = random:uniform(500) + 500,
timer:sleep(StopTime),
parking ! {leave, self(), ID},
FreerideTime = random:uniform(1000) + 500,
timer:sleep(FreerideTime),
car(ID, Iterations - 1).
parkingInit(Slots) ->
spawn(parking, parkingLoop, [Slots]).
parkingLoop(Slots) ->
receive
{enter, Pid} ->
if Slots =:= 0 ->
Pid ! error
end,
Pid ! ok,
parkingLoop(Slots - 1);
{leave, Pid, ID} ->
io:format("Car ~B left the car park.", [ID]),
parkingLoop(Slots + 1);
stop ->
ok
end.
start(Cars, Slots, Iterations) ->
parkingInit(Slots),
carsInit(Cars, Iterations).
May anybody help me ? I learn Erlang for a couple of days and have no idea, what's wrong here.
Thanks in advance,
Radek
The example you posted uses the wrong module in the spawn/3 call:
spawn(parking, parkingLoop, [Slots]).
It should work better (or at least give a more up to date error) if you change this to:
spawn(?MODULE, parkingLoop, [Slots]).
(Always use ?MODULE, which is a macro that evaluates to the current module name, when doing such things since it will avoid a lot of mistakes using the wrong module than intended).
The bug comes from not registering the parkingLoop process. You're trying to send a message to it using parking ! ... but no process is named parking. Change line 33 to:
register(parking, spawn(parking2, parkingLoop, [Slots])).
(Even here you can use the ?MODULE macro to avoid problems in the future: ?MODULE ! ... and register(?MODULE, ...) since you only have one process with this name)
Also, your if statement on line 38 misses a fall-through clause. Make it look like this to handle the case where Slots is not equal to zero:
if
Slots =:= 0 ->Pid ! error;
true -> ok
end,
(The ok expression will have no effect since the return value of the if statement is not used)

How to get the name of a function?

Is it possible to know the name of a function in itself ?
a_function()->
io:format("I am ~p!", [????]). % What to use here?
Use the macro ?FUNCTION_NAME to get the name of the current function as an atom, and ?FUNCTION_ARITY to get the arity as an integer.
Example:
-module(test).
-export([a_function/2]).
a_function(_Foo, _Bar) ->
io:write("I am ~p/~p!",[?FUNCTION_NAME, ?FUNCTION_ARITY]).
1> c(test).
{ok,test}
2> test:a_function(a, b).
I am a_function/2!
This was implemented in EEP-0045.
For Erlang Versions 18 and Older
In older Erlang versions, there's no simple way to get the current function name at compile time. You can however retrieve it at runtime:
{current_function, {M, F, A}} = process_info(self(), current_function)
Where A is the arity (number of arguments), not the actual arguments. The first argument to process_info/2 is a process ID which can be either the current process (self()) or an other process. For example:
1> process_info(self(), current_function).
{current_function,{erl_eval,do_apply,5}}
Note however, that while this would be functionally equivalent to the ?FUNCTION_NAME macro, it's much slower because it is evaluated in runtime.
at runtime, you could throw an exception and check the top of the stacktrace.
foo() ->
catch throw(away),
[{Module, Fun, Arity} | _] = erlang:get_stacktrace(),
io:format("I am ~p:~p/~p!~n",[Module, Fun, Arity]).

Exception error in Erlang

So I've been using Erlang for the last eight hours, and I've spent two of those banging my head against the keyboard trying to figure out the exception error my console keeps returning.
I'm writing a dice program to learn erlang. I want it to be able to call from the console through the erlang interpreter. The program accepts a number of dice, and is supposed to generate a list of values. Each value is supposed to be between one and six.
I won't bore you with the dozens of individual micro-changes I made to try and fix the problem (random engineering) but I'll post my code and the error.
The Source:
-module(dice2).
-export([d6/1]).
d6(1) ->
random:uniform(6);
d6(Numdice) ->
Result = [],
d6(Numdice, [Result]).
d6(0, [Finalresult]) ->
{ok, [Finalresult]};
d6(Numdice, [Result]) ->
d6(Numdice - 1, [random:uniform(6) | Result]).
When I run the program from my console like so...
dice2:d6(1).
...I get a random number between one and six like expected.
However when I run the same function with any number higher than one as an argument I get the following exception...
**exception error: no function clause matching dice2:d6(1, [4|3])
... I know I I don't have a function with matching arguments but I don't know how to write a function with variable arguments, and a variable number of arguments.
I tried modifying the function in question like so....
d6(Numdice, [Result]) ->
Newresult = [random:uniform(6) | Result],
d6(Numdice - 1, Newresult).
... but I got essentially the same error. Anyone know what is going on here?
This is basically a type error. When Result is a list, [Result] is a list with one element. E.g., if your function worked, it would always return a list with one element: Finalresult.
This is what happens (using ==> for "reduces to"):
d6(2) ==> %% Result == []
d6(2, [[]]) ==> %% Result == [], let's say random:uniform(6) gives us 3
d6(1, [3]) ==> %% Result == 3, let's say random:uniform(6) gives us 4
d6(0, [4|3]) ==> %% fails, since [Result] can only match one-element lists
Presumably, you don't want [[]] in the first call, and you don't want Result to be 3 in the third call. So this should fix it:
d6(Numdice) -> Result = [], d6(Numdice, Result). %% or just d6(Numdice, []).
d6(0, Finalresult) -> {ok, Finalresult};
d6(Numdice, Result) -> d6(Numdice - 1, [random:uniform(6) | Result]).
Lesson: if a language is dynamically typed, this doesn't mean you can avoid getting the types correct. On the contrary, it means that the compiler won't help you in doing this as much as it could.

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