I have NSString with input Value from keyboard.
Eg.
NSString *myText = #"Apple";
In my case , i want to get a word before last letter.
For above eg , i want to get only l letter before e letter.
How can i get it?
NSString *text = #"Apple";
unichar c = [text characterAtIndex:text.length - 2];
If you need a NSString
NSString *character = [NSString stringWithCharacters:&c length:1];
that may be a useful implenentaion as well:
NSString *_string = #"string";
NSString *_letter = nil;
if (_string.length > 1) {
[_string substringWithRange:NSMakeRange(_string.length - 2, 1)];
}
it does not crash either, when the string is not long enough.
Related
I have a requirement where in first letter of all words in a sentence need to be capitalised. I achieved this through the below code
myString = [myString capitalizedString];
But there is an issue with this.. if the word starts with a numeric for eg "32abc", after capitalisation it changes to "32Abc". I need it to be "32abc".
Help would be appreciated.
Method 1
NSString *input = #"32abc";
/* get first char */
NSString *firstChar = [input substringToIndex:1];
/* remove any diacritic mark */
NSString *folded = [firstChar stringByFoldingWithOptions:NSDiacriticInsensitiveSearch locale:[NSLocale currentLocale]];
/* create the new string */
NSString *capitalisedSentence = [[folded uppercaseString] stringByAppendingString:[input substringFromIndex:1]];
Method 2 (Optimized)
NSString *input = #"32abc";
NSString *capitalisedSentence = [input stringByReplacingCharactersInRange:NSMakeRange(0,1)
withString:[[input substringToIndex:1] capitalizedString]];
Try this:
myString = [myString stringByReplacingCharactersInRange:NSMakeRange(0,1) withString:[[myString substringToIndex:1] uppercaseString]];
I have a number which will be represented as string. It is longer than 4 chars. I need to create new string from 5th till the end for that number.
For example if I have 56789623, I need to have 9623 as a result (5678 | 9623).
How to do that?
P.S. I suppose that this is very simple question, but I don't know how properly ask Google about that.
NSString *str = #"56789623";
NSString *first, *second;
if ([str length] > 4) {
first = [str substringWithRange:NSMakeRange(0, 4)];
second = [str substringWithRange:NSMakeRange(4, [str length] - 4)];
} else {
first = str;
second = nil;
}
Use this Simple functions
- (NSString *)substringFromIndex:(NSUInteger)from;
- (NSString *)substringToIndex:(NSUInteger)to;
- (NSString *)substringWithRange:(NSRange)range;
You can use:
- (NSString *)substringFromIndex:(NSUInteger)anIndex
NSString *number = #"56789623";
NSString *result = [number substringFromIndex:4];
NSLog(#"%#", result);
result contains the string: #"9623"
The keywords you were looking for are: substring and range. There are several ways to use them. Example code split string into 2 equal (if number of characters is even almost equal) substrings:
NSString *str = #"56789623";
NSInteger middleIndex = (NSInteger)(str.length/2);
NSString *strFirstPart = [str substringToIndex:middleIndex];
NSString *strSecondPart = [str substringFromIndex:middleIndex];
NSString *strFirstPart2 = [str substringWithRange:NSMakeRange(0, middleIndex)];
NSString *strSecondPart2 = [str substringWithRange:NSMakeRange(middleIndex, [str length]-middleIndex)];
for example i have string like this:
NSString *one = B3#This is the first string
NSString *two = 1#This is the second string
How can i get the "B3" and "1" Character only (using objective C)
Thanks..
Turns out this is one way to do it:
NSRange range = [one rangeOfString:#"#" options:NSBackwardsSearch];
NSString *newString = [one substringToIndex:range.location];
Thanks for all the answers.
NSString* one = #"B3#";
NSString* two = #"1#";
NSString* result = [one stringByReplacingOccurrencesOfString:#"#" withString:#""];
NSString* result_2 = [two stringByReplacingOccurrencesOfString:#"#" withString:#""];
//if you need to marge
NSString* tot = [NSString stringWithFormat:#"%#%#",result,result_2];
I've got a string that shows the stock amount using "-" as separators.
It's built up like this: localStock-wareHouseStock-supplierStock
Now I want to update the supplierStock at the end of the string, but as you can see in the code below it goes wrong when the original string returns more than a single-space value (such as 20).
Is there a way to remove all characters until the last "-" (or remove characters after the second "-")?
NSMutableString *string1 = [NSMutableString stringWithString: p1.colorStock];
NSLog(#"string1: %#",string1);
NSString *newString = [string1 substringToIndex:[string1 length]-2];
NSLog(#"newString: %#",newString);
NSString *colorStock = [NSString stringWithFormat:#"%#-%#",newString,p2.supplierStock];
NSLog(#"colorstock: %#",colorStock);
p1.colorStock = colorStock;
NSLog1
string1: 0-0-0
newString: 0-0
colorstock: 0-0-20
NSLog2
string1: 0-0-20
newString: 0-0-
colorstock: 0-0--20
EDIT: Got it working thanks to Srikar!
NSString *string1 = [NSString stringWithString: p1.colorStock];
NSLog(#"string1: %#",string1);
NSString *finalString = [string1 stringByReplacingOccurrencesOfString:[[string1 componentsSeparatedByString:#"-"] lastObject] withString:p2.supplierStock.stringValue];
NSLog(#"finalString: %#",finalString);
p1.colorStock = finalString;
Why not use componentsSeparatedByString followed by lastObject ?
NSString *supplierStock = [[string1 componentsSeparatedByString:#"-"] lastObject];
The above works if the "stock amount" is always in sets of 3's separated by a "-". Also since you always want supplierStock, lastObject is perfect for your needs.
Of course after splitting string1 with - you get a NSArray instance and you can access the individual components using objectAtIndex:index. So if you want localStock you can get by
NSString *localStock = [[string1 componentsSeparatedByString:#"-"] objectAtIndex:0];
I would suggest splitting the string into the 3 parts using [NSString componentsSeparatedByString:#"-"] and then building it back up again:
NSArray *components = [p1.colorStock componentsSeparatedByString:#"-"];
p1.colorStock = [NSString stringWithFormat:#"%#-%#-%#",
[components objectAtIndex:0],
[components objectAtIndex:1],
p2.supplierStock];
With a string that looks like
NSString *myString = #"Hello-World";
you can separate it with the componentsSeparatedByString: method of the NSString object as
NSArray *myWords = [myString componentsSeparatedByString:#"-"];
The myWords - array will then contain the two NSString objects Hello and World.
To access the strings:
NSString *theHelloString = [myWords objectAtIndex:0];
NSString *theWorldString = [myWords objectAtIndex:1];
Hope it helps!
None of these examples show how to do this if you are unaware of how many of these separator occurrences you're going to have in the original string.
Here's what I believe the correct the correct code should be for dismantling the original string and rebuilding it until you reach the final separator, regardless of how many separators it contains.
NSString *seperator = #" ";
NSString *everythingBeforeLastSeperator;
NSArray *stringComponents = [originalString componentsSeparatedByString:seperator];
if (stringComponents.count!=0) {
everythingBeforeLastSeperator = [stringComponents objectAtIndex:0];
for (int a = 1 ; a < (stringComponents.count - 1) ; a++) {
everythingBeforeLastSeperator = [NSString stringWithFormat:#"%#%#%#", everythingBeforeLastSeperator, seperator, [stringComponents objectAtIndex:a]];
}
}
return everythingBeforeLastSeperator;
I would like to be able to right align a string using spaces. I have to be able to use the stringWithFormat: method.
So far I have tried the recommended format and it does not seem to work: [NSString stringWithFormat:#"%10#",#"test"].
I would expect this to return a string that has six spaces followed by "test" but all I am getting is "test" with no spaces.
It appears that stringWithFormat ignores the sizing requests of the %# format specifier. However, %s specifier works correctly:
NSString *test = #"test";
NSString *str = [NSString stringWithFormat:#"%10s", [test cStringUsingEncoding:NSASCIIStringEncoding]];
NSLog(#"'%#'", str);
This prints ' test'.
It's C style formatting. %nd means the width is n.
check following code.
NSLog(#"%10#",[NSString stringWithFormat:#"%10#",#"test"]);
NSLog(#"%#",[NSString stringWithFormat:#" %#",#"test"]);
NSLog(#"%10#", #"test");
NSLog(#"%10s", [#"test" cStringUsingEncoding:[NSString defaultCStringEncoding]]);
NSLog(#"%10d", 1);
NSString *str = #"test";
int padding = 10-[str length]; //6
if (padding > 0)
{
NSString *pad = [[NSString string] stringByPaddingToLength:padding withString:#" " startingAtIndex:0];
str = [pad stringByAppendingString:str];
}
NSLog(#"%#", str);