Parsing a value in powershell - parsing

Question

So I run this command
$driverRAIDv = $data|where-object{$_.Name -eq "$serverName" -and ($_.Description1 -match "hpsa")} | select -ExpandProperty version
And it returns this value:
HP HPSA Driver (v 5.0.0-28OEM)
I want to take this value/variable and parse it so that I only have 5.0.0-28OEM

Answer 1

Try this, matches anything between ( and ) brackets:
EDIT: ..and removes the v followed by a space:
$driverRAIDv = $data|where-object{$_.Name -eq "$serverName" -and ($_.Description1 -match "hpsa")} | select -ExpandProperty version
$regex = "(?<=\().*(?=\))"
[regex]::matches($driverRAIDv,$regex).Value -replace "v "
which returns:
5.0.0-28OEM
or you could use following regex which will match anything between (v and )
$regex="(?<=\(v\s).*(?=\))"

Answer 2

Give this a try. Basically, we're creating a "calculated property" that contains an expression to parse out the portion of the value that you want.
$driverRAIDv = $data|where-object{$_.Name -eq "$serverName" -and ($_.Description1 -match "hpsa")} | select -Property #{ Label = 'Version'; Expression = { [void]($_ -match ('v\s(.*?)\)')); $matches[1]; }; };
I tested this out using the following code:
#{ Version = 'HP HPSA Driver (v 5.0.0-28OEM)'} | select -Property #{ Label = 'Version'; Expression = { [void]($_ -match ('v\s(.*?)\)')); $matches[1]; }; };
If you check out the help for the Select-Object command, you will see that you can create calculated properties, which basically modify the value of a property, through a PowerShell expression. To do this, create a Hashtable that contains two items: Label and Expression. The Label can simply be set to the same property value that you're modifying. The Expression is a PowerShell ScriptBlock that performs some type of operation, and returns a result. In the example I gave above, we are running a regular expression against the Version property, and returning it as the result.

Answer 3

You have many ways to do it depending on your needs and variance of what you will get.
One way could be to use replace operator. Say, you got
$driverRAIDv="HP HPSA Driver (v 5.0.0-28OEM)"
$driverRAIDv -replace 'HP HPSA Driver \(v ','' -replace '\)',''
would get you 5.0.0-28OEM
In the same line:
$driverRAIDv = ($data|where-object{$_.Name -eq "$serverName" -and ($_.Description1 -match "hpsa")} | select -ExpandProperty version) -replace 'HP HPSA Driver \(v ','' -replace '\)',''

Answer 4

A non-regex option would be to split on (, ) and (space), and select the last non-empty string.
$driverRAIDv = $data|
where {$_.Name -eq $serverName -and $_.Description1 -match "hpsa"} |
foreach {$_.version.split('[() ]')| where {$_}| select -last 1}