How to get the values from json service [duplicate] - ios

This question already has an answer here:
Parsing JSON response .
(1 answer)
Closed 8 years ago.
Hai I need to get the id & status from the service for login my code is below. please guide me to get the values.. Thanks in advance..
NSString *Username= txtUsername.text;
NSString *Password=txtPassword.text;
NSString *link = [NSString stringWithFormat:#"http://www.xxx/login.php?user=%#&pass=%#&format=json",Username,Password];
NSURL *url=[NSURL URLWithString:link];
NSData *data=[NSData dataWithContentsOfURL:url];

1st Do the jSon parsing and then get the particular value from the
key .
Before getting any value , we have to understand the tree of jSon.
Here "posts" is an NSArray ,within that one DIctionary "post" is
there ,which again contains another dictionary.
Below is the complete code.
(void)viewDidLoad
{
[super viewDidLoad];
 NSString *Username= txtUsername.text;
NSString *Password=txtPassword.text;
NSString *link =
[NSString stringWithFormat:#"http://www.some.com/webservice/login.php?user=%#&pass=%#&format=json",Username,Password];
dispatch_async(kBgQueue, ^{
NSData* data = [NSData dataWithContentsOfURL:
kLatestKivaLoansURL];
[self performSelectorOnMainThread:#selector(fetchedData:)
withObject:data waitUntilDone:YES];
}); }
Then call that selector fetchedData
(void)fetchedData:(NSData *)responseData {
//parse out the json data
NSError* error;
NSDictionary* json = [NSJSONSerialization JSONObjectWithData:responseData
options:kNilOptions
error:&error];
 
if(!error){
NSArray* postArray = [json objectForKey:#“posts”]; //This is an array
if (postArray.count>0) {
NSDictionary *dict = [[postArray objectAtIndex:0] objectForKey:#"post" ];
NSString *id_ = [dict objectForKey:#"id"];
NSString *status_ = [dict objectForKey:#"status"];
}
}
}

Can you post your json string. You can use NSJSONSERIALISATION to convert data (json string ) into NSDictionary. Then use the keys to extract the values. I'm replying through mobile so I can't write the actual code.

Use Below code to parse Json in IOS
NSString *Username= txtUsername.text;
NSString *Password=txtPassword.text;
NSString *link = [NSString stringWithFormat:#"http://www.some.com/_webservice/login.php?user=%#&pass=%#&format=json",Username,Password];
NSURL *url=[NSURL URLWithString:link];
NSMutableURLRequest *req1 = [NSMutableURLRequest requestWithURL:url];
NSURLResponse *response;
NSError *error;
//getting the data
NSData *newData = [NSURLConnection sendSynchronousRequest:req1 returningResponse:&response error:&error];
NSString *responseString = [[NSString alloc] initWithData:newData encoding:NSUTF8StringEncoding];
NSLog(#"basavaraj \n\n\n %# \n\n\n",responseString);
NSData* data = [responseString dataUsingEncoding:NSUTF8StringEncoding];
NSError *myError = nil;
NSDictionary *res = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableLeaves error:&myError];
NSString *id=[res objectForKey:#"ID"];
NSString *status=[res objectForKey:#"Status"];
and if u need extra info please go through below link it may help you
Click here for more details

Related

NSJSONSerialization Returns Error of NULL

I have the following code :
NSData * jsonData = [NSData dataWithContentsOfURL:location];
NSString* newStr = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
NSData *data = [newStr dataUsingEncoding:NSUTF8StringEncoding];
NSError *jsonError;
if (jsonError) {
NSLog(#"JSON Error %#", [jsonError localizedDescription]);
}
NSArray * jsonObject = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&jsonError];
Which is parsing the following JSON String :
{"author":"Oli Riman","content":"The museum shows us a view of pre-WWI society that includes doubts, fears, political protests etc. through newspaper cartoons of the time. Really interesting for adults who enjoy history. I wouldn't suggest this for kids who haven't studied WWI history or who don't read easily.","rating":"5","placeId":"40","date":"29-June-2015","reviewId":"9905A52D-76B2-4D42-8CA8-9158225C0D07"}
However I am getting a strange error code of :
domain: (null) - code: 0
Can anyone advise on what is causing this ?
Just tested the code on my simulator. Its working. You need to check if you are getting data from server or not.
If you want to test the parsing thing, you can do one thing-
Just store the data in json file and save it in the app bundle lets say file is "data.json"
and call below method, you will get data for sure.
- (void)readJsonData {
NSString *path = [[NSBundle mainBundle] pathForResource:#"data" ofType:#"json"];
NSURL *url = [NSURL fileURLWithPath:path];
NSData *data = [NSData dataWithContentsOfURL:url];
NSError *error;
NSDictionary *dict = [NSJSONSerialization JSONObjectWithData: data
options: NSJSONReadingAllowFragments
error: &error];
NSLog(#"Parsed json data- %#", dict);
}

Json to iOS Encoding Error

Problem: I can't parse data from a JSON file to a NSArray appropriately. UTF encoding is not working as expected.
My JSON looks something like:
[
{"Name":"Marcos","Address":"1234 Brasil Av. São Paulo - SP","Latitude":"-23.000","Longitude":"-46.70"},{"Name":"Mario","Address":"1000 Washignton Luiz Av. Itú SP","Latitude":"-20.0000","Longitude":"-46.000"}
]
My Objective-C code is:
NSError *error = nil;
NSURL *jsonUrl = [[NSURL alloc]initWithString:
#"http://marcosdegni.com.br/teste/webservice_teste.php"];
NSString *jsonString = [NSString stringWithContentsOfURL:jsonUrl
encoding:NSUTF8StringEncoding error:&error];
NSLog(#"jsonString: %# , Error:%#:" ,jsonString, error); //(1)
if (!error) {
NSError *error2 = nil;
NSData *jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding];
NSArray * jsonArray = [NSJSONSerialization JSONObjectWithData:jsonData options:kNilOptions error:&error2];
NSLog(#"\n\nArray: %#" \nError:$#, jsonArray, error2); //(2)
//(*1*) This log show the content's as they are expected: note the characters ã and ú on the address fields.
//(*2*) The logs from the array and the dictionary show this charters as it's UNIX codes:\U00e and \U00fa respectively.
You can give this a try. The id json you get will be a NSArray, you can use it from there.
NSData *data = [jsonString dataUsingEncoding:NSUTF8StringEncoding];
id json = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];
NSArray * array = json;
for (NSDictionary *dict in array) {
NSString *string = [dict objectForKey:#"Address"];
NSLog(#"%#",string);
}
From here, and I get the right result if I obtain the value of the key and log it, instead of logging the NSArray directly.

get object from json string in iOS - Xcode

i have "JSON" String like this.
**
{"success":true,"domains":[{"URL":"","name":"Test
Alpha","id":"100"}]}
**
i want to check is success is true and, if it is true, get the URL.
how can i do this in iPhone application - xcode?
NSData* data = [myStr dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary* dictionary = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:&error];
if(YES == dictionary[#"success"])
{
NSString *urlString = dictionary[#"domains"][0][#"URL"];
}
May be hep you.
For example your response is NSData like below :
NSData *data = [NSURLConnection sendSynchronousRequest:request
returningResponse:nil
error:&error];
NSMutableDictionary *_dict = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:&err];
NSString *Success = [_dict valueForKey:#"success"];
You will get your desire output in Success.
Use NSJSONSerialization to get an NSMutableDictionary, check if success is true (YES), and if so, get the URL. E.g., the following should result in URL: www.mydomain.com being output to the debug window:
NSString *jsonString = #"{\"success\":true,\"domains\":[{\"URL\":\"www.mydomain.com\",\"name\":\"Test Alpha\",\"id\":\"100\"}]}";
NSData *jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding];
NSMutableDictionary *dictionary = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingMutableContainers error:nil];
BOOL success = [dictionary objectForKey:#"success"];
if (success) {
NSMutableArray *array = [dictionary objectForKey:#"domains"];
NSMutableDictionary *domainsDictionary = [array firstObject];
NSString *urlString = [domainsDictionary objectForKey:#"URL"];
NSLog(#"URL: %#", urlString);
}

Strange output when importing JSON to Objective-C

As the question says, I get an unexpected output when importing JSON into a TableView class.
JSON:
{"city":"Cambridge"}{"city":"Oxford"}
Objective-C:
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:#"http://www.domain.com/cities.php"]];
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
NSLog(#"%#", response);
Output:
<7b226369 7479223a 2243616d 62726964 6765227d 7b226369 7479223a 224f7866 6f726422 7d>
Fairly sure I'm structuring my JSON wrongly...
Your response is of NSData type and needs to be converted to a string.
NSString *responseString = [[NSString alloc] initWithBytes:[response bytes] length:[response length] encoding:NSUTF8StringEncoding];
NSLog(responseString);
You can also use the initWithData as described elsewhere
NSString *responseString = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];
While this is useful for debugging, to actually extract or work with the data, you will want to convert it to dictionary or array.
NSDictionary *responseDict = [NSJSONSerialization JSONObjectWithData:response options:0 error:NULL];
From here, you can reference items in the dictionary.
NSArray *responseArray = [NSJSONSerialization JSONObjectWithData:response options:kNilOptions error:nil];
NSLog(#"%#",responseArray);
NSMutableArray *cityArray =[[NSMutableArray alloc] init];
for (int i=0; i<[responseArray count]; i++)
{
[cityArray addObject:[NSString stringWithFormat:#"%#",[[responseArray objectAtIndex:i] valueForKey:#"city"];
}
Please note that, I believe you would fix that json and make it to json returning an array.
NSString *jsonStr = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];
NSLog(#"%#",jsonStr);

iOS JSON Parsing error

I am trying to parse a json here but keep on getting errors for some reason. my code is
NSString *string = [NSString stringWithFormat:#"http://api.wunderground.com/api/3c158b3b3cd6ce90/hourly/q/11758.json"];//, query];
NSString *string2 = [string stringByReplacingOccurrencesOfString:#" " withString:#"_"];
NSData* data = [NSData dataWithContentsOfURL:
[NSURL URLWithString:string]];
NSError* error;
NSDictionary *res = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableLeaves error:&error];
NSArray* latestLoans = [res objectForKey:#"forecast"]; //2
NSArray *tmp = [latestLoans valueForKey:#"temp"];
NSLog(#"temp: %#", tmp);
and the error is
temp: (null)
Entity: line 2: parser error : Start tag expected, '<' not found
{
^
I don't get this because the URL is real and gets a response, and I need help with this
What you are looking for, "forecast", does not exist in the response. Perhaps what you are looking for is "hourly_forecast".
NSArray* latestLoans = [res objectForKey:#"hourly_forecast"]; //2
NSArray *tmp = [latestLoans valueForKey:#"temp"];

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