Approximate photo of a simple drawing using lines - opencv

Question

As an input I have a photo of a simple symbol, e.g.: https://www.dropbox.com/s/nrmsvfd0le0bkke/symbol.jpg
I would like to detect the straight lines in it, like points of start and ends of the lines. In this case, assuming the top left of the symbol is (0,0), the lines would be defined like this:
start end (coordinates of beginning and end of a line)
1. (0,0); (0,10) (vertical line)
2. (0,10); (15, 15)
3. (15,15); (0, 20)
4. (0,20); (0,30)
How can I do it (pereferably using OpenCV)? I though about Hough lines, but they seem to be good for perfect thin straight lines, which is not the case in a drawing. I'll probably work on binarized image, too.

Answer 1

Give a try on this,
Apply thinning algorithm on threshold image.
Find contours.
approxPolyDP for the found contour.
See some reference:
approxpolydp-for-edge-maps
Creating Bounding boxes and circles for contours

Answer 2

maybe you can work on this one.
assume a perfect binarization:
run HoughLinesP
(not implemented) try to group those detected lines
I used this code:
int main()
{
cv::Mat image = cv::imread("HoughLinesP_perfect.png");
cv::Mat gray;
cv::cvtColor(image,gray,CV_BGR2GRAY);
cv::Mat output; image.copyTo(output);
cv::Mat g_thres = gray == 0;
std::vector<cv::Vec4i> lines;
//cv::HoughLinesP( binary, lines, 1, 2*CV_PI/180, 100, 100, 50 );
// cv::HoughLinesP( h_thres, lines, 1, CV_PI/180, 100, image.cols/2, 10 );
cv::HoughLinesP( g_thres, lines, 1, CV_PI/(4*180.0), 50, image.cols/20, 10 );
for( size_t i = 0; i < lines.size(); i++ )
{
cv::line( output, cv::Point(lines[i][0], lines[i][3]),
cv::Point(lines[i][4], lines[i][3]), cv::Scalar(155,255,155), 1, 8 );
}
cv::imshow("g thres", g_thres);
cv::imwrite("HoughLinesP_out.png", output);
cv::resize(output, output, cv::Size(), 0.5,0.5);
cv::namedWindow("output"); cv::imshow("output", output);
cv::waitKey(-1);
std::cout << "finished" << std::endl;
return 0;
}
EDIT:
updated code with simple line clustering (`minimum_distance function taken from SO):
giving this result:
float minimum_distance(cv::Point2f v, cv::Point2f w, cv::Point2f p) {
// Return minimum distance between line segment vw and point p
const float l2 = cv::norm(w-v) * cv::norm(w-v); // i.e. |w-v|^2 - avoid a sqrt
if (l2 == 0.0) return cv::norm(p-v); // v == w case
// Consider the line extending the segment, parameterized as v + t (w - v).
// We find projection of point p onto the line.
// It falls where t = [(p-v) . (w-v)] / |w-v|^2
//const float t = dot(p - v, w - v) / l2;
float t = ((p-v).x * (w-v).x + (p-v).y * (w-v).y)/l2;
if (t < 0.0) return cv::norm(p-v); // Beyond the 'v' end of the segment
else if (t > 1.0) return cv::norm(p-w); // Beyond the 'w' end of the segment
const cv::Point2f projection = v + t * (w - v); // Projection falls on the segment
return cv::norm(p - projection);
}
int main()
{
cv::Mat image = cv::imread("HoughLinesP_perfect.png");
cv::Mat gray;
cv::cvtColor(image,gray,CV_BGR2GRAY);
cv::Mat output; image.copyTo(output);
cv::Mat g_thres = gray == 0;
std::vector<cv::Vec4i> lines;
cv::HoughLinesP( g_thres, lines, 1, CV_PI/(4*180.0), 50, image.cols/20, 10 );
float minDist = 100;
std::vector<cv::Vec4i> lines_filtered;
for( size_t i = 0; i < lines.size(); i++ )
{
bool keep = true;
int overwrite = -1;
cv::Point2f a(lines[i][0], lines[i][6]);
cv::Point2f b(lines[i][7], lines[i][3]);
float lengthAB = cv::norm(a-b);
for( size_t j = 0; j < lines_filtered.size(); j++ )
{
cv::Point2f c(lines_filtered[j][0], lines_filtered[j][8]);
cv::Point2f d(lines_filtered[j][9], lines_filtered[j][3]);
float distCDA = minimum_distance(c,d,a);
float distCDB = minimum_distance(c,d,b);
float lengthCD = cv::norm(c-d);
if((distCDA < minDist) && (distCDB < minDist))
{
if(lengthCD >= lengthAB)
{
keep = false;
}
else
{
overwrite = j;
}
}
}
if(keep)
{
if(overwrite >= 0)
{
lines_filtered[overwrite] = lines[i];
}
else
{
lines_filtered.push_back(lines[i]);
}
}
}
for( size_t i = 0; i < lines_filtered.size(); i++ )
{
cv::line( output, cv::Point(lines_filtered[i][0], lines_filtered[i][10]),
cv::Point(lines_filtered[i][11], lines_filtered[i][3]), cv::Scalar(155,255,155), 2, 8 );
}
cv::imshow("g thres", g_thres);
cv::imwrite("HoughLinesP_out.png", output);
cv::resize(output, output, cv::Size(), 0.5,0.5);
cv::namedWindow("output"); cv::imshow("output", output);
cv::waitKey(-1);
std::cout << "finished" << std::endl;
return 0;
}

Answer 3

You should try the Hough Line Transform. And here is an example from this website
#include "opencv2/highgui/highgui.hpp"
#include "opencv2/imgproc/imgproc.hpp"
#include <iostream>
using namespace cv;
using namespace std;
int main()
{
Mat src = imread("building.jpg", 0);
Mat dst, cdst;
Canny(src, dst, 50, 200, 3);
cvtColor(dst, cdst, CV_GRAY2BGR);
vector<Vec2f> lines;
// detect lines
HoughLines(dst, lines, 1, CV_PI/180, 150, 0, 0 );
// draw lines
for( size_t i = 0; i < lines.size(); i++ )
{
float rho = lines[i][0], theta = lines[i][1];
Point pt1, pt2;
double a = cos(theta), b = sin(theta);
double x0 = a*rho, y0 = b*rho;
pt1.x = cvRound(x0 + 1000*(-b));
pt1.y = cvRound(y0 + 1000*(a));
pt2.x = cvRound(x0 - 1000*(-b));
pt2.y = cvRound(y0 - 1000*(a));
line( cdst, pt1, pt2, Scalar(0,0,255), 3, CV_AA);
}
imshow("source", src);
imshow("detected lines", cdst);
waitKey();
return 0;
}
With this you should be able to tweak and get the proprieties you are looking for (vertices).