Suppose I have an array, for example:
var myArray = ["Steve", "Bill", "Linus", "Bret"]
And later I want to push/append an element to the end of said array, to get:
["Steve", "Bill", "Linus", "Bret", "Tim"]
What method should I use?
And what about the case where I want to add an element to the front of the array? Is there a constant time unshift?
As of Swift 3 / 4 / 5, this is done as follows.
To add a new element to the end of an Array.
anArray.append("This String")
To append a different Array to the end of your Array.
anArray += ["Moar", "Strings"]
anArray.append(contentsOf: ["Moar", "Strings"])
To insert a new element into your Array.
anArray.insert("This String", at: 0)
To insert the contents of a different Array into your Array.
anArray.insert(contentsOf: ["Moar", "Strings"], at: 0)
More information can be found in the "Collection Types" chapter of "The Swift Programming Language", starting on page 110.
You can also pass in a variable and/or object if you wanted to.
var str1:String = "John"
var str2:String = "Bob"
var myArray = ["Steve", "Bill", "Linus", "Bret"]
//add to the end of the array with append
myArray.append(str1)
myArray.append(str2)
To add them to the front:
//use 'insert' instead of append
myArray.insert(str1, atIndex:0)
myArray.insert(str2, atIndex:0)
//Swift 3
myArray.insert(str1, at: 0)
myArray.insert(str2, at: 0)
As others have already stated, you can no longer use '+=' as of xCode 6.1
To add to the end, use the += operator:
myArray += ["Craig"]
myArray += ["Jony", "Eddy"]
That operator is generally equivalent to the append(contentsOf:) method. (And in really old Swift versions, could append single elements, not just other collections of the same element type.)
There's also insert(_:at:) for inserting at any index.
If, say, you'd like a convenience function for inserting at the beginning, you could add it to the Array class with an extension.
Use += and + operators :
extension Array {
}
func += <V> (inout left: [V], right: V) {
left.append(right)
}
func + <V>(left: Array<V>, right: V) -> Array<V>
{
var map = Array<V>()
for (v) in left {
map.append(v)
}
map.append(right)
return map
}
then use :
var list = [AnyObject]()
list += "hello"
list += ["hello", "world!"]
var list2 = list + "anything"
Here is a small extension if you wish to insert at the beginning of the array without loosing the item at the first position
extension Array{
mutating func appendAtBeginning(newItem : Element){
let copy = self
self = []
self.append(newItem)
self.appendContentsOf(copy)
}
}
In Swift 4.1 and Xcode 9.4.1
We can add objects to Array basically in Two ways
let stringOne = "One"
let strigTwo = "Two"
let stringThree = "Three"
var array:[String] = []//If your array is string type
Type 1)
//To append elements at the end
array.append(stringOne)
array.append(stringThree)
Type 2)
//To add elements at specific index
array.insert(strigTwo, at: 1)
If you want to add two arrays
var array1 = [1,2,3,4,5]
let array2 = [6,7,8,9]
let array3 = array1+array2
print(array3)
array1.append(contentsOf: array2)
print(array1)
Use Deque instead of Array
The main benefit of Deque over Array is that it supports efficient insertions and removals at both ends.
https://swift.org/blog/swift-collections/
var names:Deque = ["Steve", "Bill", "Linus", "Bret"]
Add 'Tim' at the end of names
names.append("Tim")
Add 'Tim' at the begining of names
names.prepend("John")
Remove the first element of names
names.popFirst() // "John"
Remove the last element of names
names.popLast() // "Tim"
From page 143 of The Swift Programming Language:
You can add a new item to the end of an array by calling the array’s append method
Alternatively, add a new item to the end of an array with the addition assignment operator (+=)
Excerpt From: Apple Inc. “The Swift Programming Language.” iBooks. https://itun.es/us/jEUH0.l
To add to the solutions suggesting append, it's useful to know that this is an amortised constant time operation in many cases:
Complexity: Amortized O(1) unless self's storage is shared with another live array; O(count) if self does not wrap a bridged NSArray; otherwise the efficiency is unspecified.
I'm looking for a cons like operator for Swift. It should return a new immutable array with the element tacked on the end, in constant time, without changing the original array. I've not yet found a standard function that does this. I'll try to remember to report back if I find one!
You could use
Myarray.insert("Data #\(index)", atIndex: index)
If you want to append unique object, you can expand Array struct
extension Array where Element: Equatable {
mutating func appendUniqueObject(object: Generator.Element) {
if contains(object) == false {
append(object)
}
}
}
If the array is NSArray you can use the adding function to add any object at the end of the array, like this:
Swift 4.2
var myArray: NSArray = []
let firstElement: String = "First element"
let secondElement: String = "Second element"
// Process to add the elements to the array
myArray.adding(firstElement)
myArray.adding(secondElement)
Result:
print(myArray)
// ["First element", "Second element"]
That is a very simple way, regards!
In Swift 4.2:
You can use
myArray.append("Tim") //To add "Tim" into array
or
myArray.insert("Tim", at: 0) //Change 0 with specific location
Example: students = ["Ben" , "Ivy" , "Jordell"]
1) To add single elements to the end of an array, use the append(_:)
students.append(\ "Maxime" )
2) Add multiple elements at the same time by passing another array or a sequence of any kind to the append(contentsOf:) method
students.append(contentsOf: ["Shakia" , "William"])
3) To add new elements in the middle of an array by using the insert(_:at:) method for single elements
students.insert("Liam" , at:2 )
4) Using insert(contentsOf:at:) to insert multiple elements from another collection or array literal
students.insert(['Tim','TIM' at: 2 )
Swift 5.3, I believe.
The normal array wasvar myArray = ["Steve", "Bill", "Linus", "Bret"]
and you want to add "Tim" to the array, then you can use myArray.insert("Tim", at=*index*)so if you want to add it at the back of the array, then you can use myArray.append("Tim", at: 3)
Related
I have a list of arrays look like this:
var lists = [[Category]]()
Each element in the "lists" represents an array of object (Category), I'm trying to reinit the "lists" (clear every element) after using it.
My approach:
lists.forEach { list in
list.removeAll()
}
Error: Can not mutate the "list" because "list" is a constant variable
Is there anyway I can achieve my goal in Swift?
Since arrays are value types and they have copy-on-write semantics, "clearing all the nested arrays of an array" is indistinguishable from "creating a new array with as many empty nested arrays as there are nested arrays in the old array, and reassigning it to the old array".
So you can do
lists = Array(repeating: [], count: lists.count)
Alternatively:
lists = lists.map { _ in [] }
From the comments, it seems like you are writing a function that clears all the nested arrays. In that case, you need an inout parameter:
func clearList(_ lists: inout [[Category]]) {
lists = Array(repeating: [], count: lists.count)
}
And to call it:
var myLists = [listCate1, listCate2]
clearList(&myLists)
// myLists will be [[], []], note that this does not change listCate1 or listCate2
If you really want your function to mutate an arbitrary number of lists that you pass in, you'd need to use unsafe pointers (very not recommended):
func clearList(_ lists: UnsafeMutablePointer<[Category]>...) {
for list in lists {
list.pointee = []
}
}
And clearList(&listCate1, &listCate2) would actually change listCate1 and listCate2, but this is a rather dirty trick.
You can assign an empty array literal which is written as [ ] (an empty pair of square brackets)
lists = []
lists is now an empty array, but still of type [[Category]]
You can remove all the element of an array and keep the capacity.
lists.removeAll(keepingCapacity: true)
or if you want to remove object from array based on some conditions then you can use this...
lists.removeAll { (obj) -> Bool in
if <check some condition { return true }
else { false }
}
I'd create an extension with mutable and immutable variants. By extending RangeReplaceableCollection rather than Array we don't need to constrain Array.Element to any specific type.
extension RangeReplaceableCollection where Element: RangeReplaceableCollection {
func stripped() -> Self {
return .init(repeating: .init(), count: count)
}
mutating func strip() {
self = stripped()
}
}
Now we can strip in place if our array is declared mutable:
var mutable: [[Category]] = []
mutable.strip()
Or we can use the immutable variant for let constants:
let immutable: [[Category]] = []
let stripped = immutable.stripped()
var someInts1 = [30,11,34]
var someInts2 = [30,11,34]
var someInts3 = [30,11,34]
var lists = [Any]()
lists = [someInts1, someInts2, someInts3]
print(lists) // [[30,11,34], [30,11,34], [30,11,34]]
lists = [] // this is where the list become empty
print(lists) // []
I am currently having a big issue sorting my Data alphabetically in a 2D array. I'm going to try to give you every detail to be as clear as possible.
Currently, I am fetching my contacts with the CNContactStore. This all works fine. I am able to retrieve all the data I want out of my contacts.
Now, I created the following struct:
struct FavoritableContact {
let contact: CNContact
var hasFavorited: Bool
}
With this, I declared and initialized the following array:
var favoritableContacts = [FavoritableContact]()
Once I retrieved my contacts, I simply appended them to favoritableContacts;
try store.enumerateContacts(with: request, usingBlock: { (contact, stopPointerIfYouWantToStopEnumerating) in
favoritableContacts.append(FavoritableContact(contact: contact, hasFavorited: false))
})
To sort them in alphabetical order in the same array, I simply did the following:
var sortedContacts = favoritableContacts.sorted { $0.contact.familyName < $1.contact.familyName }
Now if possible, I want to create the following 2D array,
var 2D = [
[FavoritableContact] //"A"
[FavoritableContact], //"B"
[FavoritableContact], //"C"
[FavoritableContact], //"D"
...
]
I am just not sure how to take my sortedContacts array and separate alphabetically.
I am very new here, If I forgot something, or I didn't do somethign right please let me know.
As was pointed out in the comments, a dictionary with first letters as keys is probably the better way to go as it is much easier to access, though perhaps you have a reason for wanting to use a 2d array instead. To achieve that you could do something like this:
//Create an empty array filled with 26 arrays of FavorableContact
var array2d = Array<[FavoritableContact]>(repeating: [FavoritableContact](), count: 26)
//Find the ascii value for "A" to use as your base
let aAscii = Int("A".unicodeScalars.filter({ $0.isASCII }).map({ $0.value })[0]) //This returns 65, btw, so you could also just hardcode
//Go through your original array, find the first letter of each contact, and append to the correct array
favoritableContacts.forEach { (contact) in
//Get the ascii value for the first letter
let firstLetter = Int(contact.contact.familyName.prefix(1).uppercased().unicodeScalars.filter({ $0.isASCII }).map({ $0.value })[0])
//Append to the array for this letter by subtracting the ascii value for "A" from the ascii value for the uppercased version of this letter.
array2d[firstLetter - aAscii].append(contact)
}
This is not the cleanest thing in the world, and it assumes standard English language alphabet with no diacritics, symbols, numbers or anything else. Assuming that is true it gets the job done.
Could use something like this.
var contactsLeftToSort : [FavoritableContact] = []
var doubleArray : [[FavoritableContact]?] = [[FavoritableContact]?]()
var index : Int = 0
for char in "ABCDEFGHIJKLMNOPQRSTUV" {
doubleArray.append(nil)
var i = 0
while i < contactsLeftToSort.count {
let contact = contactsLeftToSort[i]
if contact.name.first == char {
doubleArray[index] == nil ? doubleArray[index] = [contact] : doubleArray[index]!.append(contact)
contactsLeftToSort.remove(at: i)
}
//assuming original list is alphabetized.. if not, delete this line.
if contact.name.first! > char { break }
i += 1
}
index += 1
}
As I wrote in the comments above, I think you can achieve this in a much more elegant way by using a dictionary instead of an array.
SWIFT 4
let sortedContacts: [FavoritableContact] = ... // An array of FavoritableContact objects, they should be sorted
let groupedContacts = Dictionary(grouping: contacts, by { $0.familyName.first! })
You now have a dictionary of all your contacts where the keys are the alphabetical letters (ie. A-Z) and the values are arrays of sorted FavoritableContact objects (assuming you sorted the big array of FavoritableContacts before creating the dictionary).
If you wanted to use this as the datasource for your tableview, you would make the number of sections all the possible first letters of family names. For the number of rows in each section, you return the count of the array for the key like so:
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int
let letterForSection = letterForSection() // Custom method to get the section of the letter
return contactsDict[letterForSection].count
}
The rest of the datasource methods would work in a similar way.
Man, all of these answers are really over-complicating this. All you need is something along the lines of:
let groupedContacts = Dictionary(grouping: contacts, by: { $0.contact.firstName.first! })
for initial, contacts in groupedContacts.lazy.sorted().{ $0.key < $1.key} {
print("#################", initial)
contacts.forEach{ print($0) }
}
Suppose I have an array, for example:
var myArray = ["Steve", "Bill", "Linus", "Bret"]
And later I want to push/append an element to the end of said array, to get:
["Steve", "Bill", "Linus", "Bret", "Tim"]
What method should I use?
And what about the case where I want to add an element to the front of the array? Is there a constant time unshift?
As of Swift 3 / 4 / 5, this is done as follows.
To add a new element to the end of an Array.
anArray.append("This String")
To append a different Array to the end of your Array.
anArray += ["Moar", "Strings"]
anArray.append(contentsOf: ["Moar", "Strings"])
To insert a new element into your Array.
anArray.insert("This String", at: 0)
To insert the contents of a different Array into your Array.
anArray.insert(contentsOf: ["Moar", "Strings"], at: 0)
More information can be found in the "Collection Types" chapter of "The Swift Programming Language", starting on page 110.
You can also pass in a variable and/or object if you wanted to.
var str1:String = "John"
var str2:String = "Bob"
var myArray = ["Steve", "Bill", "Linus", "Bret"]
//add to the end of the array with append
myArray.append(str1)
myArray.append(str2)
To add them to the front:
//use 'insert' instead of append
myArray.insert(str1, atIndex:0)
myArray.insert(str2, atIndex:0)
//Swift 3
myArray.insert(str1, at: 0)
myArray.insert(str2, at: 0)
As others have already stated, you can no longer use '+=' as of xCode 6.1
To add to the end, use the += operator:
myArray += ["Craig"]
myArray += ["Jony", "Eddy"]
That operator is generally equivalent to the append(contentsOf:) method. (And in really old Swift versions, could append single elements, not just other collections of the same element type.)
There's also insert(_:at:) for inserting at any index.
If, say, you'd like a convenience function for inserting at the beginning, you could add it to the Array class with an extension.
Use += and + operators :
extension Array {
}
func += <V> (inout left: [V], right: V) {
left.append(right)
}
func + <V>(left: Array<V>, right: V) -> Array<V>
{
var map = Array<V>()
for (v) in left {
map.append(v)
}
map.append(right)
return map
}
then use :
var list = [AnyObject]()
list += "hello"
list += ["hello", "world!"]
var list2 = list + "anything"
Here is a small extension if you wish to insert at the beginning of the array without loosing the item at the first position
extension Array{
mutating func appendAtBeginning(newItem : Element){
let copy = self
self = []
self.append(newItem)
self.appendContentsOf(copy)
}
}
In Swift 4.1 and Xcode 9.4.1
We can add objects to Array basically in Two ways
let stringOne = "One"
let strigTwo = "Two"
let stringThree = "Three"
var array:[String] = []//If your array is string type
Type 1)
//To append elements at the end
array.append(stringOne)
array.append(stringThree)
Type 2)
//To add elements at specific index
array.insert(strigTwo, at: 1)
If you want to add two arrays
var array1 = [1,2,3,4,5]
let array2 = [6,7,8,9]
let array3 = array1+array2
print(array3)
array1.append(contentsOf: array2)
print(array1)
Use Deque instead of Array
The main benefit of Deque over Array is that it supports efficient insertions and removals at both ends.
https://swift.org/blog/swift-collections/
var names:Deque = ["Steve", "Bill", "Linus", "Bret"]
Add 'Tim' at the end of names
names.append("Tim")
Add 'Tim' at the begining of names
names.prepend("John")
Remove the first element of names
names.popFirst() // "John"
Remove the last element of names
names.popLast() // "Tim"
From page 143 of The Swift Programming Language:
You can add a new item to the end of an array by calling the array’s append method
Alternatively, add a new item to the end of an array with the addition assignment operator (+=)
Excerpt From: Apple Inc. “The Swift Programming Language.” iBooks. https://itun.es/us/jEUH0.l
To add to the solutions suggesting append, it's useful to know that this is an amortised constant time operation in many cases:
Complexity: Amortized O(1) unless self's storage is shared with another live array; O(count) if self does not wrap a bridged NSArray; otherwise the efficiency is unspecified.
I'm looking for a cons like operator for Swift. It should return a new immutable array with the element tacked on the end, in constant time, without changing the original array. I've not yet found a standard function that does this. I'll try to remember to report back if I find one!
You could use
Myarray.insert("Data #\(index)", atIndex: index)
If you want to append unique object, you can expand Array struct
extension Array where Element: Equatable {
mutating func appendUniqueObject(object: Generator.Element) {
if contains(object) == false {
append(object)
}
}
}
If the array is NSArray you can use the adding function to add any object at the end of the array, like this:
Swift 4.2
var myArray: NSArray = []
let firstElement: String = "First element"
let secondElement: String = "Second element"
// Process to add the elements to the array
myArray.adding(firstElement)
myArray.adding(secondElement)
Result:
print(myArray)
// ["First element", "Second element"]
That is a very simple way, regards!
In Swift 4.2:
You can use
myArray.append("Tim") //To add "Tim" into array
or
myArray.insert("Tim", at: 0) //Change 0 with specific location
Example: students = ["Ben" , "Ivy" , "Jordell"]
1) To add single elements to the end of an array, use the append(_:)
students.append(\ "Maxime" )
2) Add multiple elements at the same time by passing another array or a sequence of any kind to the append(contentsOf:) method
students.append(contentsOf: ["Shakia" , "William"])
3) To add new elements in the middle of an array by using the insert(_:at:) method for single elements
students.insert("Liam" , at:2 )
4) Using insert(contentsOf:at:) to insert multiple elements from another collection or array literal
students.insert(['Tim','TIM' at: 2 )
Swift 5.3, I believe.
The normal array wasvar myArray = ["Steve", "Bill", "Linus", "Bret"]
and you want to add "Tim" to the array, then you can use myArray.insert("Tim", at=*index*)so if you want to add it at the back of the array, then you can use myArray.append("Tim", at: 3)
I have an array of strings for one variable, and a string as another variable. I'd like to append all of the strings in the collection to the single string.
So for example I have:
var s = String()
//have the CSV writer create all the columns needed as an array of strings
let arrayOfStrings: [String] = csvReport.map{GenerateRow($0)}
// now that we have all the strings, append each one
arrayOfStrings.map(s.stringByAppendingString({$0}))
the line above fails. I've tried every combination I can think of, but at the end of the day, I can't get it unless I just create a for loop to iterate through the entire collection, arrayOfStrings, and add it one by one. I feel like I can achieve this the same way using map or some other function.
Any help?
Thanks!
You can use joined(separator:):
let stringArray = ["Hello", "World"]
let sentence = stringArray.joined(separator: " ") // "Hello World"
You could convert your array to string using joinWithSeparator(String)
here is an example
var array = ["1", "2", "3"]
let stringRepresentation = array.joinWithSeparator("-") // "1-2-3"
source: [ How do I convert a Swift Array to a String? ]
There are at least two options here. The most semantic choice is likely joinWithSeparator on the [String] object. This concatenates every string in the array, placing the separator provided as a parameter between each string.
let result = ["a", "b", "c", "d"].joinWithSeparator("")
An alternative is to use a functional reduce and the + function operator which concatenates strings. This may be preferred if you want to do additional logic as part of the combine. Both example code produce the same result.
let result = ["a", "b", "c", "d"].reduce("", combine: +)
It's also worth noting the second options is transferrable to any type that can be added, whereas the first only works with a sequence of strings, as it is defined on a protocol extension of SequenceType where Generator.Element == String.
Two faceted question:
var array = [1,2,3,4,5]
contains(array, 0) // false
var array2: NSArray = [1,2,3,4,5]
array2.containsObject(4) // true
Is there any way to search an Array for more than 1 value? ie. Can I write below to search the array for multiple values and return true if any of the values are found? Second part to the question is how can I do that for an NSArray as well?
var array = [1,2,3,4,5]
contains(array, (0,2,3)) // this doesn't work of course but you get the point
You can chain contains together with a second array:
// Swift 1.x
contains(array) { contains([0, 2, 3], $0) }
// Swift 2 (as method)
array.contains{ [0, 2, 3].contains($0) }
// and since Xcode 7 beta 2 you can pass the contains function which is associated to the array ([0, 2, 3])
array.contains([0, 2, 3].contains)
// Xcode 12
array.contains(where: [0, 2, 3].contains)
One option would be to use a Set for the search terms:
var array = [1,2,3,4,5]
let searchTerms: Set = [0,2,3]
!searchTerms.isDisjointWith(array)
(You have to negate the value of isDisjointWith, as it returns false when at least one of the terms is found.)
Note that you could also extend Array to add a shorthand for this:
extension Array where Element: Hashable {
func containsAny(searchTerms: Set<Element>) -> Bool {
return !searchTerms.isDisjointWith(self)
}
}
array.containsAny([0,2,3])
As for the NSArray, you can use the version of contains which takes a block to determine the match:
var array2: NSArray = [1,2,3,4,5]
array2.contains { searchTerms.contains(($0 as! NSNumber).integerValue) }
Explanation of closure syntax (as requested in comments): you can put the closure outside the () of method call if it's the last parameter, and if it's the only parameter you can omit the () altogether. $0 is the default name of the first argument to the closure ($1 would be the second, etc). And return may be omitted if the closure is only one expression. The long equivalent:
array2.contains({ (num) in
return searchTerms.contains((num as! NSNumber).integerValue)
})
Swift 5.7 +
A quick syntax fix to the accepted answer for the latest version of swift:
extension Array where Element: Hashable {
func containsAny(searchTerms: Set<Element>) -> Bool {
return !searchTerms.isDisjoint(with: self)
}
}