Please help me to find the error, my code is
NSURL *url = [NSURL URLWithString: #"http://www.xxxx.com/xxxx_webservice/login.php?user=%#&pass=%#&format=json",Username,Password];
Do it like this. First make a proper string of your URL and then encode it and then finally make it a NSURL. Make sure your passing the correct and right set of parameters.
NSString *link = [NSString stringWithFormat:#"http://www.example.com/xx_webservice/login.php?user=%#&pass=%#&format=json",Username,Password];
NSString *encdLink = [link stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url=[NSURL URLWithString:encdLink];
Related
I have a URL which is in a string: http://bs.serving-sys.com/BurstingPipe/adServer.bs?cn=is&c=23&pl=VAST&pli=10226041&PluID=0&pos=6670&ord=%5B1423164382.84%5D&cim=1
I am trying to convert that string to NSURL.
I've tried several things, which are:
NSString *encodedString = [#"http://bs.serving-sys.com/BurstingPipe/adServer.bs?cn=is&c=23&pl=VAST&pli=10226041&PluID=0&pos=6670&ord=%5B1423164382.84%5D&cim=1" stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding];
NSURL *url = [NSURL URLWithString:encodedString];
When I follow the URL object with a breakpoint it assigns 0 => false.
What should I do to convert that string to NSURL?
The parameters in your given URL string are already URL encoded. So:
NSString *string = #"http://bs.serving-sys.com/BurstingPipe/adServer.bs?cn=is&c=23&pl=VAST&pli=10226041&PluID=0&pos=6670&ord=%5B1423164382.84%5D&cim=1";
NSURL *url = [NSURL URLWithString:string];
// url is not nil
i am NewBie in iOS Development. I want to Decode my NSURL With Pagination Here my Url Like as
http://www.janvajevu.com/webservice/categorylist.php?category=%E0%AA%B8%E0%AB%8D%E0%AA%B5%E0%AA%BE%E0%AA%B8%E0%AB%8D%E0%AA%A5%E0%AA%AF&page=0
And i Decode this URL Like as
NSURL *urls = [NSURL URLWithString:#"http://www.janvajevu.com/webservice/categorylist.php?category=%E0%AA%B8%E0%AB%8D%E0%AA%B5%E0%AA%BE%E0%AA%B8%E0%AB%8D%E0%AA%A5%E0%AA%AF&page=0"];
NSString *urlString = [urls absoluteString];
NSLog(#"UrlString %#",urlString);
NSURL * url=[NSURL URLWithString:urlString];
But it Give me Only 0 Page Url i want to Like as make my url as
NSURL *urls=[NSURL URLWithString:#"My Url &page=%d",pagenum];
Here i want at place of My Url as Decoding of my Original Url If it is Possible then Please Give me Solution for it.
you are doing it in wrong way.
this is the right way
NSString *urlString = #"http://www.janvajevu.com/webservice/categorylist.php?category=%E0%AA%B8%E0%AB%8D%E0%AA%B5%E0%AA%BE%E0%AA%B8%E0%AB%8D%E0%AA%A5%E0%AA%AF&page=";
NSURL *targetURL = [NSURL URLWithString:[NSString stringWithFormat:#"%#%d",urlString,pageNumber]];
NSLog(#"targetURL is : %#",targetURL);
Hope this will help you..
NSString *str=#"http://www.janvajevu.com/webservice/categorylist.php?category=%E0%AA%B8%E0%AB%8D%E0%AA%B5%E0%AA%BE%E0%AA%B8%E0%AB%8D%E0%AA%A5%E0%AA%AF&page=0";
NSString *result =[str stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *urls = [NSURL URLWithString:result] ;
I am trying to place strings inside my NSURL, I have tried most suggestions but all seem to fail, i'm trying to find a easy way to do it instead of having to use some long request with long code. I'm wondering is there anything small here i'm forgetting?
NSString *lat = #"53.350628";
NSString *lng = #"-6.254997";
NSURL *blogURL = [NSURL URLWithString:#"http://url.com/jsontest.php?lat=%#&lng=%#&max=5", lat, lng];
NSData *jsonData = [NSData dataWithContentsOfURL:blogURL];
Thanks,
Curtis
+[NSURL URLWithStirng:] does not take a format string and a variable argument list. It just takes a string, so you should use something like +[NSString stringWithFormat:] first before passing it to URLWithString, like this:
NSURL *blogURL = [NSURL URLWithString:[NSString stringWithFormat:#"http://url.com/jsontest.php?lat=%#&lng=%#&max=5", lat, lng]];
Format the string, than add that to the NSURL
NSString *lat = #"53.350628";
NSString *lng = #"-6.254997";
//Format String
NSString *urlString = [NSString stringWithFormat:#"http://url.com/jsontest.php?lat=%#&lng=%#&max=5", lat, lng];
NSURL *blogURL = [NSURL URLWithString:urlString];
NSData *jsonData = [NSData dataWithContentsOfURL:blogURL];
I am generating a URL as given by string parameters but url gives null value.
For generating URL I have implemented the following code .
NSURL *url = [[NSURL alloc] init];
NSString *strURL = #"ftp://Administrat:ABC(R%-#TRDOP#xx.xx.xx.xx/arrows.png";
url = [NSURL URLWithString:[NSString stringWithString:strURL]];
NSLog(#"URL :: %#",url);
Thanks
You need to escape the special characters in the url query string.
Use:
NSString *strURL = #"ftp://www.jerox.com/Administrator:#123#TRDOP#%$/arrows.png";
strURL =[strURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [NSURL URLWithString:strURL];
NSLog(#"URL :: %#",url);
Also I need to mention some mistakes in your code:
No need to allocate and init the NSURL object, because you are again assigning another object to that pointer
No need of using stringWithString: there
Make use of the following code.
NSString *sURL = #"ftp://www.jerox.com/Administrator:#123#TRDOP#%$/arrows.png";
NSURL *url = [[NSURL alloc] initWithString:[sURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
NSLog(#"URL :: %#",url);
From your posted code sample, here is the problem:
NSString *strURL = #"ftp://Administrat:ABC(R%-#TRDOP#xx.xx.xx.xx/arrows.png";
Look carefully at the authority component (username, password and host). An # symbol is used in URLs to separate username & password from the host. Because your password contains an # character, it must be percent escaped. The percent encoding of # is %40, giving you instead the code:
NSString *strURL = #"ftp://Administrat:ABC(R%-%40TRDOP#xx.xx.xx.xx/arrows.png";
You really ought to be escaping other URL-specific characters in there too, like the lone % symbol.
I need to use a NSURL object to reach different ressources on the same host.
Here is what I do:
#define MY_HOST #"my.server.eu"
NSURL *url = [[NSURL alloc] initWithScheme:#"http" host:MY_HOST path:#"/"];
Now I need to deal with
http://my.server.eu/path1
http://my.server.eu/path2
http://my.server.eu/path3
How can I modify the path of my NSURL object ?
Why can't we simply do url.path = #"path1" ?
How can I modify the path of my NSURL object ?
Why can't we simply do url.path = #"path1" ?
Because NSURL is an immutable object, and you can't change its properties afterwards. NSMutableURL does not exist, but is on the wish list of many.
In order to achieve what you're after, you're going to have to make 3 separate NSURL objects I'm afraid. To do so, you can convenience the paths within an array:
NSString *host = #"http://my.server.eu/";
NSArray *paths = #[#"path1", #"path2", #"path3"];
NSURL *path1 = [NSURL URLWithString:[NSString stringWithFormat:#"%#%#", host, path[0]]];
NSURL *path2 = [NSURL URLWithString:[NSString stringWithFormat:#"%#%#", host, path[1]]];
NSURL *path3 = [NSURL URLWithString:[NSString stringWithFormat:#"%#%#", host, path[2]]];
You should make the base URL as you're doing and then build the others relative to it using +[NSURL URLWithString:relativeToURL:].