Combining two fields into one hyperlink - hyperlink

So I have two columns in my database, "URL" and "Title".
The first one contains bare URL in the form of http://something.somewhere.com, the second is the descriptive name of it (quite intuitive).
I need to write a query which would combine these two columns into one "URL" like that A descriptive name.
I've tried with the # symbol this way:
descriptive_name#url#
and it works if you input it manually, but apparently it doesn't work with queries.
I've tried:
UPDATE table SET table.[URL] = (SELECT [Title] & "#" & [URL] & "#" FROM table);

Your UPDATE query syntax is wrong.
It should be:
UPDATE table SET table.[URL] = [Title] & "#" & [URL] & "#"

Related

Rails query to substitute field and query

could someone please help me to write a query to substitute hyphens in rails DB field with space?
For eg:
If I have a field called 'name' in a table User having a value 'asdc-sd bc', and want to remove special characters like '-' and replace it with space to match with a given name 'asdc sd bc'.
I tried using lower to convert the name to lowercase but am not able to find out how to substitute the hyphens with space. Please help!
You can use SQL REPLACE function to replace - with spaces(' ').
For example, if you are querying on name column of User model, you can write your query like below:
query_str = 'asdc sd bc'
User.where("REPLACE(name, '-', ' ') = ?", query_str)

Rails, Postgres 12, Query where pattern matches regex, and contains substring

I have a field in the database which contains strings that look like: 58XBF2022L1001390 I need to be able to query results which match the last letter(in this case 'L'), and match or resemble the last four digits.
The regular expression I've been using to find records which match the structure is: \d{2}[A-Z]{3}\d{4}[A-Z]\d{7}, So far I've tried using a scope to refine the results, but I'm not getting any results. Here's my scope
def self.filter_by_shortcode(input)
q = input
starting = q.slice!(0)
ending = q
where("field ~* ?", "\d{2}[A-Z]{3}\d{4}/[#{starting}]/\d{3}[#{ending}]\g")
end
Here are some more example strings, and the substring that we would be looking for. Not every string stored in this database field matches this format, so we would need to be able to first match the string using the regex provided, then search by substring.
36GOD8837G6154231
G4231
13WLF8997V2119371
V9371
78FCY5027V4561374
V1374
06RNW7194P2075353
P5353
57RQN0368Y9090704
Y0704
edit: added some more examples as well as substrings that we would need to search by.
I do not know Rails, but the SQL for what you want is relative simple. Since your string if fixed format, once that format is validated, simple concatenation of sub-strings gives your desired result.
with base(target, goal) as
( values ('36GOD8837G6154231', 'G4231')
, ('13WLF8997V2119371', 'V9371')
, ('78FCY5027V4561374', 'V1374')
, ('06RNW7194P2075353', 'P5353')
, ('57RQN0368Y9090704', 'Y0704')
)
select substr(target,10,1) || substr(target,14,4) target, goal
from base
where target ~ '^\d{2}[A-Z]{3}\d{4}[A-Z]\d{7}$';

How do i remove rows based on comma-separated list of values in a Power BI parameter in Power Query?

I have a list of data with a title column (among many other columns) and I have a Power BI parameter that has, for example, a value of "a,b,c". What I want to do is loop through the parameter's values and remove any rows that begin with those characters.
For example:
Title
a
b
c
d
Should become
Title
d
This comma separated list could have one value or it could have twenty. I know that I can turn the parameter into a list by using
parameterList = Text.Split(<parameter-name>,",")
but then I am unsure how to continue to use that to filter on. For one value I would just use
#"Filtered Rows" = Table.SelectRows(#"Table", each Text.StartsWith([key], <value-to-filter-on>))
but that only allows one value.
EDIT: I may have worded my original question poorly. The comma separated values in the parameterList can be any number of characters (e.g.: a,abcd,foo,bar) and I want to see if the value in [key] starts with that string of characters.
Try using List.Contains to check whether the starting character is in the parameter list.
each List.Contains(parameterList, Text.Start([key], 1)
Edit: Since you've changed the requirement, try this:
Table.SelectRows(
#"Table",
(C) => not List.AnyTrue(
List.Transform(
parameterList,
each Text.StartsWith(C[key], _)
)
)
)
For each row, this transforms the parameterList into a list of true/false values by checking if the current key starts with each text string in the list. If any are true, then List.AnyTrue returns true and we choose not to select that row.
Since you want to filter out all the values from the parameter, you can use something like:
= Table.SelectRows(#"Changed Type", each List.Contains(Parameter1,Text.Start([Title],1))=false)
Another way to do this would be to create a custom column in the table, which has the first character of title:
= Table.AddColumn(#"Changed Type", "FirstChar", each Text.Start([Title],1))
and then use this field in the filter step:
= Table.SelectRows(#"Added Custom", each List.Contains(Parameter1,[FirstChar])=false)
I tested this with a small sample set and it seems to be running fine. You can test both and see if it helps with the performance. If you are still facing performance issues, it would probably be easier if you can share the pbix file.
This seems to work fairly well:
= List.Select(Source[Title], each Text.Contains(Parameter1,Text.Start(_,1))=false)
Replace Source with the name of your table and Parameter1 with the name of your Parameter.

Issue regarding fetching only those records where field value contains only one occurrence of a particular character in rails

I need to write a rails active record where clause where I have to fetch those rows where name (name is a column in my table) contains only one occurrence of the character '.'
For example, if there is two rows in the table where name is "a.b" and "a.b.c", then my query should return the row having name "a.b" only.
Please help me to solve this.
Thanks in advance!
You can for example remove the dots and compare length.
SELECT * FROM table WHERE (char_length(name) - char_length(replace(name, '.', '')))=1
This is not very efficient though, because indexes can't be utilized.
To make things smoother, you could store the number of dots (depth?) in its own column with an index and query based on that. This could be done in insert/update trigger or in application layer, whatever suits your situation.
dbfiddle
with regexp ? you can try this :
select * from "table" where "name" ~ '^[^\.]*\.[^\.]*$'

Rails: how to split string after a specific character

I have a column name in database which holds strings like CVM™ what I want to do is to split it so everything after ampersand goes into a different column and everything before the string stays where it was. The final result should put ™ into a column called abbr and save CVM into name column.
Create a rake task file
lib/tasks/split_name.rake
Then paste in the following, and change "TableName" to your actual table name.
task :split_name => :environment do
TableName.all.each do |r|
a = r.name.split("&") #assuming exact same string format, and not null
r.update_attribute(:name, a[0])
r.update_attribute(:abbr, '&' + a[1])
end
end
Then run it as such
rake split_name
Must this be done Rails level? You can also do this with just Postgres with split_part function. I assume you're working with users table:
ALTER TABLE users ADD COLUMN abbr VARCHAR;
UPDATE users
SET name = SPLIT_PART(name, '™', 1),
abbr = '™' || SPLIT_PART(name, '™', 2);
You can also bake these queries into a Rake task if needed.
Update: Opps I assumed you were using Postgres. But other languages should have similar method that you can use.

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