I am trying to compile some java code on Windows 7 pc, I have installed java JDK and I am trying to use the javac command in cmd but I get output saying that
'javac' is not recognized as an internal or external command,
operable program or batch file.
What do I have to do to enable compiler in cmd or is it possible to do in Windows?
1)Go to properties by right click on icon Computer , then navigate to Advanced System Settings.
2)Click Environment Variables.
3)Click on New , set Variable name as path and Variable path as the path of java jdk installation directory which could be something like this -
C:\Program Files\Java\jdk1.6.0_23\bin;
where C:** is the drive where JDK is installed and **Program Files\java is the directory where it resides.
look out for semi-colon(;) at the last.
4)Click ok
5)Restart cmd and run javac , it should work now.
Look for Screenshots here for more help.
Regards
Anshul
you have to set a new system variable for your JAVA_HOME in windows.
See here for further information.
Add the path to bin folder of JDK in your PATH variable. For instructions to set PATH variable follow this tutorial.
Your java directory is not on the path. Here are some helpful screenshots to show how to set it up:
http://vietpad.sourceforge.net/javaonwindows.html
When I'm trying run below code,
D:\apache-tomcat\bin>service.bat install
I got this error.
The JAVA_HOME environment variable is not defined correctly
This environment variable is needed to run this program
NB: JAVA_HOME should point to a JDK not a JRE
How could I solve this ?
I have found answer for my question. I should add,
set JAVA_HOME=<JAVA INSTALLED Location>
just before set "CURRENT_DIR=%cd%" in service.bat file locate in bin directory in tomcat installed directory.
You need to define environment variable JAVA_HOME and point it to java installed location.
or
you can add below line in in TOMCAT_HOME\bin\startup.bat
set 'JAVA_HOME=<JAVA INSTALLED Location>'
2.If JDK is not installed in your machine, define JRE_HOME and point to installed JRE
I have been trying to install Maven v 3.0.4 on my machine win 7 for the first time.I have a problem setting the path environment System variable I have the following 4 entries :
PATH
%SystemRoot%\system32;%SystemRoot%;%SystemRoot%\System32\Wbem;%SYSTEMROOT%\System32\WindowsPowerShell\v1.0\;C:\Program Files\Java\jdk1.7.0_04;C:\Program Files\apache-maven-3.0.4\bin;M2_HOME;%M2%
M2_HOME
C:\Program Files\apache-maven-3.0.4\bin
M2
%M2_HOME%\bin
JAVA_HOME
C:\Program Files\Java\jdk1.7.0_04\bin
when I do mvn --version
I get the error:
JAVA_HOME not found in your environment, please set the JAVA_HOME variable in your environment to match the location of your java installation
The java -version displays the java version fine,
what am I doing so horribly wrong? Is the PATH ok?
Help appreciated, thanks.
It is only necessary to set the path to the Maven binary and to the JDK correctly:
set PATH %SystemRoot%\system32;%SystemRoot%;%SystemRoot%\System32\Wbem;%SYSTEMROOT%\System32\WindowsPowerShell\v1.0\;C:\Program Files\Java\jdk1.7.0_04\bin;C:\Program Files\apache-maven-3.0.4\bin
Furthermore you need to set the JAVA_HOME correctly which is done under windows like this:
SET JAVA_HOME=C:\Program Files\Java\jdk1.7.0_04
Be aware of setting JAVA_HOME to the root of the installed JDK and not to bin folder it.
The settings of M2 and M2_HOME is not necessary.
from command prompt run the following
set M2_HOME= C:\Program Files\apache-maven-3.0.4
set PATH=%PATH%;%M2_HOME%\bin
set JAVA_HOME=C:\Program Files\Java\jdk1.7.0_04
set PATH=%PATH%;%JAVA_HOME%\bin
cmd.exe
mvn -version
The environmental variables should point to the installation directory of each program respectively, and their corresponding bin folders should be added to the PATH:
Make sure that your JAVA_HOME points to the C:\Program Files\Java\jdk1.7.0_04 (or whatever directory you have installed your JDK to).
Add the %JAVA_HOME%\bin folder to your PATH (e.g. by replacing the part with C:\Program Files\Java\jdk1.7.0_04). Make sure that you use ; to separate different path components.
Likewise, the M2_HOME variable should be assigned Maven's installation directory, e.g. C:\Program Files\apache-maven-3.0.4 and you should add %M2_HOME%\binto the PATH (the part with C:\Program Files\apache-maven-3.0.4\bin;M2_HOME;%M2% can be removed.
The advantage of adding the environmental variables %JAVA_HOME%\bin and %M2_HOME%\bin on the path rather than the fully qualified path is that it will be easy to update Java and Maven (or to have several versions installed in parallell). All you need to do is to update the environmental variable, and the PATH variable will fallow automatically.
I ran into the same issue as the original poster. I checked, double checked, and triple checked everything to conform to what everyone has (correctly) indicated the setup needs to be. I still got the same error. In the end, I ran SET JAVA_HOME=C:\Program Files\Java\jdk1.7.0_45 from the command line and then ran the mvn command and viola.
So, for what ever reason, pss's suggestion did the trick. Obviously, this doesn't really change what everyone else said, because that's exactly what my environment variables look like...just had to hit the JAVA_HOME from the command line.
Oddness.
I followed all the steps but it was not working for me. But as soon i have set the JAVA_HOME Path, in Command prompt just type:
C:>SET JAVA_HOME=C:\Program Files (x86)\Java\jdk1.8.0_91
It is working fine in fraction of seconds. Thanks Everyone.
I faced the same problem on local installation. I tried out all the suggested methods including the SET method but that didn't work for me. In the end, I had to manually add another environment variable to the system, and then after that
mvn -v
gave the appropriate response:
Apache Maven 3.3.3 (7994120775791599e205a5524ec3e0dfe41d4a06; 2015-04-22T04:57:37-07:00)
Maven home: C:\Program Files (x86)\apache-maven-3.3.3-bin\apache-maven-3.3.3\bin\..
Java version: 1.8.0_45, vendor: Oracle Corporation
Java home: C:\Program Files\Java\jdk1.8.0_45\jre
Default locale: en_US, platform encoding: Cp1252
OS name: "windows 8", version: "6.2", arch: "amd64", family: "dos"
If, like me, you are running mvn -version from the command prompt, and then adding any missing environment variables from the GUI, it is possible that you just have to reload the command prompt after adding the environment variables.
Just exit and run cmd.exe
You need to make a variable of name JAVA_HOME in your Environment and set its value as path to jdk.
Right click on My Computer/ This PC -> Properties
Choose Advance system settings
Open Environment variables
Under System variables click on New... button and give the name
as JAVA_HOME and value as c:/path/to/jdk
Version that I always use. Double click and you get the maven up and running
#echo off
title Maven 3.0.5
set JAVA_HOME=C:\Users\hutingung\Development\jdk\jdk1.6.0_33
set MAVEN_OPTS=-Xmx1024m -Xms512m -XX:MaxPermSize=192m -Dfile.encoding=utf-8
set MAVEN_HOME=C:\Users\hutingung\Development\tools\apache-maven-3.0.5\bin
set PATH=%MAVEN_HOME%;%JAVA_HOME%\bin;%PATH%
#cmd /k
Yes, Appending that path C:\programfiles\maven\bin to path variable in system variables is enough, it will work. No need to add user variables.
I have already done my homework before posting this question. I am trying to build Portico-1.0.2 on Red-Hat Linux 64 bit machine using apache ant. Initially I was setting JAVA_HOME path to jre-1.6.0_31/bin folder but it threw an error that : Unable to locate tools.jar. Expected to find it in jre1.6.0_31/lib/tools.jar.
Then after exploring stackoverflow I found few posts explaining to install jdk and set its folder as the JAVA_HOME path. So I have installed Jdk-1.6.0 in Redhat Linux and after installing jdk I located tools.jar file in it's lib folder. Now when I set the JAVA_HOME path to : /usr/lib/jvm/jre-1.6.0-openjdk.x86_64, it throws an error : portico-1.0.2/codebase/build.xml:55: The JAVA_HOME environment variable must be set
But I have set the JAVA_HOME in .bashrc file as follows :
JAVA_HOME=/usr/lib/jvm/jre-1.6.0-openjdk.x86_64
PATH=$JAVA_HOME:$PATH
I am not sure what to do. Any advice on how to solve this problem.
Confusingly the JDK also contains a JRE, the latter you've set as JAVA_HOME thereby repeating your problem...
The Red hat docs describe how to set the JAVA_HOME
hi open the bashrc file in the root directory and add the path to your jdk and you will be good to go..
eg
export JAVA_HOME=/usr/java/jdk1.6.0_19
export PATH=$PATH:$JAVA_HOME/bin
I am trying to install grails in my windows 7, I have installed JDK 1.7.0 and downloaded grails from its site and extracted in path "C:\grails", i have jdk in "C:\Program Files\Java\jdk1.7.0". I have set environment variable JAVA_HOME = "C:\Program Files\Java\jdk1.7.0\bin" and GRAILS_HOME = "C:\grails" and added "%GRAILS_HOME%\bin" and JAVA_HOME to path from advanced settings. But when i try to run "grails -v" or "grails help" i get the error "The system cannot find the path specified.". I even changed my directory to "C:\grails" and ran "grails -v" but it is still giving me the same error.
I dont know what is wrong with it, please help me installing this thing.
Thanks
JAVA_HOME = "C:\Program Files\Java\jdk1.7.0\bin" mustn't include 'bin'
You'll want to verify that Java is working correctly first by entering "java -version" at the command line.
When you say you extracted the zip into "C:\grails" does that directory now just have a single sub directory (i.e. "grails-2.5.0" or whatever version you downloaded), or does it contain a bunch of sub directories (bin, conf, dist, doc. etc)?
If the answer is the former, your GRAILS_HOME should point to "C:\grails\grails-2.5.0" instead of just C:\grails\