How do i display all data in a UILabel?
I am currently using this :
for (NSManagedObject *obj in matchingData)
{
lastname = [obj valueForKey:#"lastname"];
name = [obj valueForKey:#"name"];
NSLog(#"Name:%#\n Last Name %#\n", [obj valueForKey:#"name"],[obj valueForKey:#"lastname"]);
}
self.displayLabel2.text = [NSString stringWithFormat:#"Guest : %# %#" ,name, lastname];
}
In the console I get all my data but in UILabel (displayLabel2) I just get one name…i just don't get it…
The way that your code reads, on each loop through the obj NSManagedObject, the name and lastname will be reset. So the label will only display the final loop's data.
try creating a string within the loop
NSMutableString *stringText = [NSMutableString string];
for (NSManagedObject *obj in matchingData)
{
lastname = [obj valueForKey:#"lastname"];
name = [obj valueForKey:#"name"];
NSLog(#"Name:%#\n Last Name %#\n", [obj valueForKey:#"name"],[obj valueForKey:#"lastname"]);
stringText = [NSString stringWithFormat:#"%# %#", stringText, [NSString stringWithFormat:#"Guest : %# %#" ,name, lastname]];
}
self.displayLabel2.text = stringText;
}
Related
I query and get a NSSet which contains customer address from web. Since I'm new to objective c development I don't know how to get country,zip code etc from that set.So I followed Objective-C How to print NSSet on one line (no trailing comma / space) but my output is in the form of object "0x7f99997b7a50". How can I print all the strings in the set? Thanks in advance.
I tried like this
NSArray *ar = [customer.addresses allObjects];
for (int i = 0; i<ar.count; i++)
{
NSLog(#"arr %#",ar[i]);
}
But the output is arr:
<BUYAddress: 0x7fd451f6e050>
If you have a custom object, you may need to override description
Without overriding:
-(void) testCustomObjects
{
CustomObject *co1 = [[CustomObject alloc] init];
co1.name = #"James Webster";
co1.jobTitle = #"Code Monkey";
CustomObject *co2 = [[CustomObject alloc] init];
co2.name = #"Holly T Canine";
co2.jobTitle = #"Pet Dog";
NSSet *set = [NSSet setWithObjects:co1, co2, nil];
NSLog(#"%#", [set allObjects]);
}
produces:
2016-12-02 11:45:55.342 Playground[95359:4188387] (
"<CustomObject: 0x600000037a20>",
"<CustomObject: 0x60000003ae20>"
)
However, if I override the description method in my CustomObject class:
-(NSString*) description
{
return [NSString stringWithFormat:#"%# (%#)", self.name, self.jobTitle];
}
I get the following:
(
"Holly T Canine (Pet Dog)",
"James Webster (Code Monkey)"
)
If for whatever reason, you can't add a description method, you'd just have to access the relevant parts of the object; something like the following:
NSArray *ar = [customer.addresses allObjects];
for (int i = 0; i<ar.count; i++)
{
NSLog(#"arr %# (%#)",ar[i].name, ar[i].address);
}
I've had a little look at the library you're using. Try the following:
for (BUYAddress *address in customer.addresses)
{
NSLog(#"Address: %#, %#, %#", address.address1, address.address2, address.city);
}
Consider NSSet below,
NSSet *theNSSet = [NSSet setWithObjects:#"Chennai",#"Mumbai",#"Delhi", nil];
Convert it into NSArray using
NSArray *array = [theNSSet allObjects]; // theNSSet is replaced with your NSSet id
Then print it like
NSLog(#"%#",array);
Output im getting
(
Chennai,
Delhi,
Mumbai
)
In your case:
- (NSMutableSet *)addressesSet {
[self willAccessValueForKey:#"addresses"];
NSMutableSet *result = (NSMutableSet *)[self mutableSetValueForKey:#"addresses"];
[self didAccessValueForKey:#"addresses"];
NSLog(#"%#",[result allObjects]); // printing the nsset
return result;
}
I have an NSDictionary with the following data:
(lldb) po allFriends
{
71685207018702188 = {
id = 71685207018702188;
name = "mikeziri ";
username = mi;
};
93374822540641772 = {
id = 93374822540641772;
name = "Alan Weclipse";
username = zuka;
};
96553685978449395 = {
id = 96553685978449395;
name = "Monica Weclipse";
username = amonica;
};
96556113096345076 = {
id = 96556113096345076;
name = Xavier;
username = branko;
};
97017008427632119 = {
id = 97017008427632119;
name = "Dario Weclipse";
username = tarzan;
};
}
I'm sorting these objects based on the name, if they don't have a name, i will use the username. To do that, i create a new NSDictionary with the name and id and at the end of the method i sort them by name. The code to sort them is the following:
- (NSArray*)orderFriends
{
NSMutableDictionary* newFriendsDict = [[NSMutableDictionary alloc] init];
for (int i=0; i<[allFriends count];i++)
{
NSMutableDictionary* friendsDict = [[NSMutableDictionary alloc] init];
NSDictionary* friend = [allFriends objectForKey:[NSString stringWithFormat:#"%#", [sortedKeysFriends objectAtIndex:i]]];
if ([[friend objectForKey:#"name"] length] != 0)
{
[friendsDict setObject:[friend objectForKey:#"id"] forKey:#"id"];
[friendsDict setObject:[NSString stringWithFormat:#"%#", [friend objectForKey:#"name"]] forKey:#"name"];
}
else
{
[friendsDict setObject:[friend objectForKey:#"id"] forKey:#"id"];
[friendsDict setObject:[NSString stringWithFormat:#"%#", [friend objectForKey:#"username"]] forKey:#"name"];
}
[newFriendsDict setObject:friendsDict forKey:[NSNumber numberWithInt:i]];
}
NSArray* sp = nil;
sp = [[newFriendsDict allValues] sortedArrayUsingComparator:^(id obj1, id obj2){
NSString *one = [NSString stringWithFormat:#"%#", [obj1 objectForKey:#"name"]];
NSString *two = [NSString stringWithFormat:#"%#", [obj2 objectForKey:#"name"]];
return [one compare:two];
}];
return sp;
}
The problem is that the end result is wrong:
(lldb) po sp
<__NSArrayI 0x160491a0>(
{
id = 93374822540641772;
name = "Alan Weclipse";
},
{
id = 97017008427632119;
name = "Dario Weclipse";
},
{
id = 96553685978449395;
name = "Monica Weclipse";
},
{
id = 96556113096345076;
name = Xavier;
},
{
id = 71685207018702188;
name = "mikeziri ";
},
)
Case sensitive. make all string small or big.
You could also just change
return [one compare:two];
to
return [one compare:two options: options:NSCaseInsensitiveSearch];
Than it will be ordered alphabetically, no matter if upper or lower case...
Several things: There is no reason to build different dictionaries in order to sort, and good reason NOT to do so.
You already found the method sortedArrayUsingComparator. That takes a block that is used to compare pairs of objects, and returns a sorted array. You can use that method to implement any sorting criteria you want.
I would suggest writing a comparator block that compares the name properties of your objects unless it's blank, and uses username if that's blank. It would only be a few lines of code:
NSArray *sortedFriends = [[allFriends allValues] sortedArrayUsingComparator:
^(NSDictionary *obj1, NSDictionary *obj2)
{
NSString* key1 = obj1[#"name"] ? obj1[#"name"] : obj1[#"username"];
NSString* key2 = obj2[#"name"] ? obj2[#"name"] : obj2[#"username"];
return [key1 caseInsensitiveCompare: key2];
}];
EDIT: I just noticed (from your edit of my post) that you are starting from a dictionary, not an array. So what you want to do is to create a sorted array of all the values in the dictionary? Is it acceptable to discard the keys for all the items in your dictionary, and end up with a sorted array of the values?
The other thing you could do would be to build an array of the dictionary keys, sorted based on your sort criteria. Then you could use the array of keys to fetch the items from your dictionary in sorted order.
I have a name textfield in my app, where both the firstname maybe a middle and a lastname is written. Now I want to split these components by the first whitespace, the space between the firstname and the middlename/lastname, so I can put it into my model.
For example:
Textfield Text: John D. Sowers
String 1: John
String 2: D. Sowers.
I have tried using [[self componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]] firstObject]; & [[self componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]] lastObject];
But these only work if have a name without a middlename. Since it gets the first and the last object, and the middlename is ignored.
So how would I manage to accomplish what I want?
/*fullNameString is an NSString*/
NSRange rangeOfSpace = [fullNameString rangeOfString:#" "];
NSString *first = rangeOfSpace.location == NSNotFound ? fullNameString : [fullNameString substringToIndex:rangeOfSpace.location];
NSString *last = rangeOfSpace.location == NSNotFound ? nil :[fullNameString substringFromIndex:rangeOfSpace.location + 1];
...the conditional assignment (rangeOfSpace.location == NSNotFound ? <<default value>> : <<real first/last name>>) protects against an index out of bounds error.
Well that method is giving you an array with all the words split by white space, so then you can grab the first object as the first name and the rest of the objects as middle/last/etc
NSArray *ar = [self componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
NSString *firstName = [ar firstObject];
NSMutableString *rest = [[NSMutableString alloc] init];
for(int i = 1; i < ar.count; i++)
{
[rest appendString:[ar objectAtIndex:i]];
[rest appendString:#" "];
}
//now first name has the first name
//rest has the rest
There might be easier way to do this, but this is one way..
Hope it helps
Daniel
I think this example below I did, solves your problem.
Remember you can assign values from the array directly, without transforming into string.
Here is an example:
NSString *textField = #"John D. Sowers";
NSArray *fullName = [textField componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#" "]];
if (fullName.count)
{
if (fullName.count > 2)
{
NSLog(#"Array has more than 2 objects");
NSString *name = fullName[0];
NSLog(#"Name:%#",name);
NSString *middleName = fullName[1];
NSLog(#"Middle Name:%#",middleName);
NSString *lastName = fullName[2];
NSLog(#"Last Name:%#",lastName);
}
else if(fullName.count == 2)
{
NSLog(#"Array has 2 objects");
NSString *name = fullName[0];
NSLog(#"Name:%#",name);
NSString *lastName = fullName[1];
NSLog(#"Last Name:%#",lastName);
}
else
{
NSString *name = fullName[0];
}
}
I found this to be most robust:
NSString *fullNameString = #"\n Barnaby Marmaduke \n \n Aloysius ";
NSMutableArray *nameArray = [[fullNameString componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]] mutableCopy];
[nameArray removeObject:#""];
NSString *firstName = [nameArray firstObject];
if(nameArray.count)
{
[nameArray removeObjectAtIndex:0];
}
NSString *nameRemainder = [nameArray componentsJoinedByString:#" "];
Bob's your uncle.
this is what i am using:
it works if address, city, zip.....length >0.(these field may grow in future)
self.addressInfoLbl.text = [NSString stringWithFormat:#"%#\n%#\n%#\n%#\n%#", address, city, zip, state, country];(numberofline == 0)
but if any of them length =0 then i got unnecessary new line.
i am working on manually preparing(appending \n).if there are more and more fields then doing it manuallt is really hard.
Is there any other proper way.Am i doing it right.
Thanks
Try following code. It creates array of your strings, removes empty strings and then concatenates them with componentsJoinedByString :
NSArray *strings = #[address, city, zip, state, country];
strings = [strings filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:#"length > 0"]];
NSString *resultString = [strings componentsJoinedByString:#"\n"];
You can join an array of objects into a string with a separator:
NSArray *props = [NSArray arrayWithObjects: address, city, state, nil];
NSString *joinedString = [props componentsJoinedByString:#"\n"];
and you will get:
"6th avenue\nAtlanta\nGeorgia"
If you don't know the amount of properties, use NSMutableArray instead of NSArray and add your properties at runtime.
Try this once,
NSMutableString *joinedString=[NSMutableString string];
NSArray *arr = [NSArray arrayWithObjects: address, city, state, nil];
for(NSString *str in arr)
{
if([str length]>0) [joinedString appendFormat:#"\n%#", str];
}
NSString *resultString=[joinedString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
NSLog(#"%#", resultString);
Lbl.numberOfLines=0;
Lbl.lineBreakMode=NSLineBreakByCharWrapping;
try this code, it not optimal but it can resolve youy issue
NSArray *arr = [NSArray arrayWithObjects: #"address", #"", #"state", nil];
NSString *addressInfo = #"";
for (NSString *str in arr) {
if (str.length > 0) {
addressInfo = [addressInfo stringByAppendingString:[NSString stringWithFormat:#"\n%#", str]];
}
}
if (addressInfo && ![#"" isEqualToString:addressInfo])
addressInfo = [addressInfo substringFromIndex:1];
NSLog(#"address Info = %#", addressInfo);
Ok I get and store a Json feed to an array called jsonArray. I then loop over the jsonArray pulling out the array keys and storing them as strings. I then add those strings to an inner dictionary called innerDict, I then add that dictionary to the info dictionary with the key thePostCode using the below. So basically innerDict is stored inside infoDict.
-(void)pointInfo{
infoDict = [[NSMutableDictionary alloc]init];
for (int i = 0; i < jsonArray.count; i++) {
innerDict = [[NSMutableDictionary alloc]init];
info = [[jsonArray objectAtIndex:i]objectForKey:#"inf"];
thePostCode = [[jsonArray objectAtIndex:i]objectForKey:#"pc"];
mail = [[jsonArray objectAtIndex:i]objectForKey:#"mail"];
url = [[jsonArray objectAtIndex:i]objectForKey:#"url"];
type = [[jsonArray objectAtIndex:i]objectForKey:#"items"];
[innerDict setObject:type forKey:#"Items"];
[innerDict setObject:info forKey:#"Info"];
[innerDict setObject:mail forKey:#"Mail"];
[innerDict setObject:url forKey:#"Url"];
[infoDict setObject:innerDict forKey:thePostCode];
}
the output of infoDict looks like this:
infoDict is {
"ME14 4NN" = {
Info = "";
Items = 4;
Mail = "";
Url = "";
};
"ME15 6LG" = {
Info = af;
Items = "0,6,9";
Mail = "";
Url = "";
};
"ME15 6YE" = {
Info = "";
Items = "4,5,6,7,11";
Mail = "";
Url = "";
};
}
Now what I want to do is get the values of the innerDict object i.e "ME15 6YE" above and use that as the query to pull out the associated data for Info, Items, Mail and Url keys. I have been staring at my screen for a few hours but I am just not getting it.
I can pull out the last object of the inner dict using the below however I would like to grab all the values associated with a particular postcode which would be the innerDict key. Completely brain fried at the moment!
for (NSMutableDictionary *dictionary in infoDict) {
NSLog(#"URL %#", [innerDict objectForKey:#"Url"]);
NSLog(#"MAIL %#", [innerDict objectForKey:#"Mail"]);
NSLog(#"ITEMS %#", [innerDict objectForKey:#"Items"]);
NSLog(#"ITEMS %#", [innerDict objectForKey:#"Info"]);
}
To get the correct inner dictionary, use objectForKey:
NSDictionary *innerDict = [infoDict objectForKey:#"ME15 6YE"];
NSLog(#"Url %#", [innerDict objectForKey:#"Url"]);
NSLog(#"Mail %#", [innerDict objectForKey:#"Mail"]);
NSLog(#"Items %#", [innerDict objectForKey:#"Items"]);
NSLog(#"Info %#", [innerDict objectForKey:#"Info"]);
Maybe I'm misunderstanding something, but I think this should answer your questions.
You're using dictionary in the for loop, but trying to access it via innerDict. Change it to:
for (NSMutableDictionary *dictionary in infoDict) {
NSLog(#"URL %#", [dictionary objectForKey:#"Url"]);
NSLog(#"MAIL %#", [dictionary objectForKey:#"Mail"]);
NSLog(#"ITEMS %#", [dictionary objectForKey:#"Items"]);
NSLog(#"ITEMS %#", [dictionary objectForKey:#"Info"]);
}
Or, for a single one,
NSMutableDictionary *inner = [infoDict objectForKey:#"POST CODE HERE"];
NSLog(#"URL %#", [inner objectForKey:#"Url"]);
NSLog(#"MAIL %#", [inner objectForKey:#"Mail"]);
NSLog(#"ITEMS %#", [inner objectForKey:#"Items"]);
NSLog(#"ITEMS %#", [inner objectForKey:#"Info"]);