so here is my question what i want to do is that searchbynamelike property should give the exact result
as my string is "Hello"
so the findByNameLike("%Hello%")
it will all the result even if h is here or e or l and so on
but what i want is that if i have full hello then only it should give result
the reason being is i have hello in various places in a db table so when someone search for hello it should return all results where hello is found, but not when even if "h" is searched..
how can i achieve this in grails ...help..!!!
In your case, don't use %...% sign in string. It'll give you all results matching anywhere hello is found in your string.
use: findByNameIlike("Hello")
I have done similar search by using Criteria Query .
Just use nodes like eq or like according to your need.
Related
I am currently using this formula to get all the data from everyone whose first name is "Peter", but my problem is that if someone is called "Simon Peter" this data is gonna show up on the formula output.
=QUERY('Data'!1:1000,"select * where B contains 'Peter'")
I know that for the other formulas if I add an * to the String this issue is resolved. But in this situation for the QUERY formula the same logic do not applies.
Do someone knows the correct syntax or a workaround?
How about classic SQL syntax
=QUERY('Data'!1:1000,"select * where B like 'Peter %'")
The LIKE keyword allows use of wildcard % to represent characters relative to the known parts of the searched string.
See the query reference: developers.google.com/chart/interactive/docs/querylanguage You could split firstname and lastname into separate columns, then only search for firstnames exactly equal to 'Peter'. Though you may want to also check if lowercase/uppercase where lower(B) contains 'peter' or whitespaces are present in unexpected places (e.g., trim()). You could also search only for values that start with Peter by using starts with instead of contains, or a regular expression using matches. – Brian D
It seems that for my case using 'starts with' is a perfect fit. Thank you!
Im having issues with rails with the code
if #turno.chop == res[:department].to_s
where turno contains strings like ABC1 and department like ABC, im trying to filter if turno its equal of department but i need reduce the string of turno for that.
Every time what i try to do that the code dont finish and stuck in other part of code, when i delete the condition, the code works perfectly but dont do the filter.
i tryid to to do like
if #turno.include?(res[:department].to_s)
But appears the same error.
I believe something very similar to this was answered in the stackoverflow.com question. How to check whether a string contains a substring in Ruby?
The include? command sounds like what you should use.
my_string = "abcdefg"
if my_string.include? "cde"
puts "String includes 'cde'"
end
To be more accurate, #turno can contain a string like "ABC1" and res[:department] contains a string with "ABC" i need reduce the string in #turno to the first X characters and compare it with the content of res[:department]
So I am trying to use a simple QUERY function in Google Sheets where I want to select based on TWO parameters. Simple logic, and documentation says use the AND operator. The problem is I am searching for text via Cell Reference.
So here is my function
=QUERY(A1:D6,"select A where C='" &K1&'"" & "and D='" &K2"'")
Unfortunately it throws up an ERROR. I understand that Cell References that are text based need to be in single quotes (which themselves need to be in double quotes), but I am unable to join two WHERE statements.
What is the right syntax for this?
Very close indeed, please try:
=query(A1:D6,"select A where C='"&K1&"' and D='"&K2&"' ")
Welp! I was missing an concatenation symbol (&) at the end of the final cell reference K2.
=QUERY(A1:D6,"select A where C='" &K1&'"" & "and D='" &K2&"'")
I am trying example provided in Graph Databases book (PDF page 51-52)with Neo4j 2.0.1 (latest). It appears that I cannot just copy paste the code sample from the book (I guess the syntax is no longer valid).
START bob=node:user(username='Bob'),
charlie=node:user(username='Charlie')
MATCH (bob)-[e:EMAILED]->(charlie)
RETURN e
Got #=> Index `user` does not exist.
So, I tried without 'user'
START bob=node(username='Bob'),
charlie=node(username='Charlie')
MATCH (bob)-[e:EMAILED]->(charlie)
RETURN e
Got #=> Invalid input 'u': expected whitespace, an unsigned integer, a parameter or '*'
Tried this but didn't work
START bob=node({username:'Bob'}),
(charlie=node({username:'Charlie'})
MATCH (bob)-[e:EMAILED]->(charlie)
RETURN e
Got #=> Invalid input ':': expected an identifier character, whitespace or '}'
I want to use START then MATCH to achieve this. Would appreciate little bit of direction to get started.
From version 2.0 syntax has changed.
http://docs.neo4j.org/chunked/stable/query-match.html
Your first query should look like this.
MATCH (bob {username:'Bob'})-[e:EMAILED]->(charlie {username:'Charlie'})
RETURN e
The query does not work out of the box because you'll need to create the user index first. This can't be done with Cypher though, see the documentation for more info. Your syntax is still valid, but Lucene indexes are considered legacy. Schema indexes replace them, but they are not fully mature yet (e.g. no wildcard searches, IN support, ...).
You'll want to use labels as well, in your case a User label. The query can be refactored to:
MATCH (b:User { username:'Bob' })-[e:EMAILED]->(c:User { username:'Charlie' })
RETURN e
For good performance, add a schema index on the username property as well:
CREATE INDEX ON :User(username)
Start is optional, as noted above. Given that it's listed under the "deprecated" section in the Cypher 2.0 refcard, I would try to avoid using it going forward just for safety purposes.
However, the refcard does state that you can prepend your Cypher query with "CYPHER 1.9" (without the quotes) in order to make explicit use of the older syntax.
I'm just starting to learn the Cypher query language and GraphDb in general. I've created some indexes using the class name of my nodes like:
"com.acme.node.SomeNodeType"
I can't for the life of me figure out how to reference this index in Cypher. I found this thread but using ` didn't work for me.
So I guess I have 2 questions:
Is it possible to use an index with dots in the name?
If so, how do I specify the name in the query?
can you try to query them with '' like
start n = node:`my.index`('name:test') return n
?