I created a Refinery::Carts engine which is in a separate directory all by itself. It has a Cart model. Now I wanted to create a LineItem model. I tried to run
rails generate model LineItem cart:references product_id:string qty:integer 'unit_price:decimal{6,2}' 'virtual:boolean{false}' address:references
However it complained
Please first run 'rake refinery:testing:dummy_app' to create a dummy Refinery CMS application.
So I ran that and bundle install, but now that I ran the rails generate model, it put the model into spec/dummy folder! I tried to use rails generate model Refinery::Carts::LineItem ... but it complained the files already existed
/usr/local/rvm/gems/ruby-2.0.0-p247#bk_development/gems/factory_girl-4.2.0/lib/factory_girl/decorator.rb:10:in `method_missing': Factory alrea dy registered: line_item (FactoryGirl::DuplicateDefinitionError)
So how do I use rails generate model to create additional models for a RefineryCMS engine/extension? Must I do it all manually?
You'll want to check out this guide from refinerycms http://refinerycms.com/guides/multiple-resources-in-an-extension
Taken from that guide: To add a Place model to an extension named Events
rails g refinery:engine place name:string --extension events --namespace events
Related
I am learning to build a Rails API app with the 6.1 version. I created a rails app in the following way
rails new book-gallery --api --mysql
The app created successfully. I proceeded next doing the following
rails g scaffold Author name:string country:string
This created the controller and model with the crud. But I want API to be versioned instead
Requirement:
/v1/authors
If I pass versioning on the scaffold, the model is also getting versioned which should not be
rails g scaffold v1/Author name:string country:string
The controller path is correct, but the model I got v1.rb and folder of name v1.
I don't need versioning in the model, I am trying to keep it as author.rb
Any guidance will be grateful.
Thank you
You can't achieve what you want with 1 command.
You could do a scaffold_controller and create the model without scaffolding:
rails g model Author name country
rails g scaffold_controller v1/Author
You can also skip the :string for the model attributes. Without given the datatype it will set it to string by default.
I was attempting to add a tagging model to my rails blog. But I accidentally generated a "Tags.rb" model as opposed to "Tag.rb", after reading the guide I realized that making "tag" plural was a mistake when it comes to model. I rolled back the migration using
rake db:rollback
and then
rails destroy model Tags.rb
and this was what i got back
invoke active_record
remove /home/migration/templates/create_table_migration.rb
remove app/models/tags.rb.rb
invoke test_unit
remove test/models/tags.rb_test.rb
remove test/fixtures/tags.rbs.yml
When I come back to the model folder though its still there.
Please help :)
Just give
rails destroy model Tag
Try using tags plural without the additional .rb, like
rails destroy model Tags
Hope this helps
You can manually delete the files, or just manually remove the "s"s.
try this
bundle exec rake db:rollback
and then delete your model as
rails destroy model <model_name>
now totaly deleted.
You can delete the migration files in migrate folder and model in your model folder and then you can again create new one which you wants.
you have to run that commands
rails g model tag
Then migrate database
rake db:migrate
First off, when generating a Rails model using rails generate model, don't add .rb to the end of the model name. Rails automatically does that so if you add .rb yourself then you end up with a model named Tag.rb.rb, which is invalid.
You're running the remove generator with "Tags.rb". Did you generate the model originally using rails generate model Tags.rb? If you did, then running rails destroy model Tags.rb will hopefully remove all the files, but since the model name is invalid, it might not work as expected (your use case is outside the intended use case of the generator). If you originally generated the model using rails generate model Tags, then running rails destroy model Tags should work.
If you originally invoked rails generate model Tags.rb, and running the remove command isn't working (which again, in understandable given that Tags.rb is an invalid name--would have been nice if the generator had originally prohibited you from generating a Tags.rb.rb file, but you can't have everything):
If you can afford to destroy your database and rerun all the migrations, the easy solution will be to manually remove the added files, destroy the database, and rerun all migrations. Then you can add the correct model using rails generate model Tag.
If you can't afford to destroy your database, then you'll need to manually find the problem migration in the migration's folder, run the down command on that migration, and then manually delete that migration file and all the other files.
I have generated two scaffold using the following two commands:
$:- rails generate scaffold User user:string gender:string
$:- rails generate scaffold Microposts microposts:string
Is there any command that will list me the different scaffolds i have generated so far?
It should give me the output similar to this:
Scaffold generated:
User
Microposts
Not that I know of, but you can see the direct result in your application, plus after each scaffold you see which files are generated. To quote RoR guides:
A scaffold in Rails is a full set of model, database migration for that model, controller to manipulate it, views to view and manipulate the data, and a test suite for each of the above.
A scaffold in itself is not one thing, it's a collection. What would be the point of only displaying the name you used to scaffold all these files?
I don't think so - scaffolding generates models, views and controllers for a given class (in your case User and Microposts) - if you look at app/models you'll see User.rb and Microposts.rb. So maybe that's nearly the same thing?
I am new to Ruby on Rails . This might be a very foolish question.
I have created a migration using
rails generate migration Kapol name:string position:integer
rake db:migrate
Then using phpmyadmin i copied the database already present
I then opened up rails console
My question is can i use the method Kapol.find(1)??
because when i tried it using singular or plural it says
unitialized constant:Kapol
I know that there has to be a method but where to specify it?
You must generate a model in case to create a table for it, because the migration is usually used to modify existing tables.
It might be confusing that the model generator also creates migration file in your migrations folder. The only difference is that the model generator also generates initial code to create table, on the other hand, the migration generator creates only migration file without initial code.
rails generate model Kapol name:string position:integer
More information: http://guides.rubyonrails.org/getting_started.html#generating-a-model
If you're very new to Ruby on Rails, probably the best thing for you to do is create a scaffold, which gives you your migration file, your model file, your controller file, and various view files, test files, etc. etc., which all work well together. Then you can play with these and build up from there.
rails generate scaffold Kapol name:string position:integer
If you're happy with the migration that was automatically generated, then rake db:migrate and you're all set.
As Andrew says below, you can also just generate any of those files one at a time by replacing 'scaffold' with 'model', etc.
Your Kapol.find(1) is correct.
I'm new to Rails so my current project is in a weird state.
One of the first things I generated was a "Movie" model. I then started defining it in more detail, added a few methods, etc.
I now realize I should have generated it with rails generate scaffold to hook up things like the routing, views, controller, etc.
I tried to generate the scaffolding but I got an error saying a migration file with the same name already exists.
What's the best way for me to create scaffolding for my "Movie" now? (using rails 3)
TL;DR: rails g scaffold_controller <name>
Even though you already have a model, you can still generate the necessary controller and migration files by using the rails generate option. If you run rails generate -h you can see all of the options available to you.
Rails:
controller
generator
helper
integration_test
mailer
migration
model
observer
performance_test
plugin
resource
scaffold
scaffold_controller
session_migration
stylesheets
If you'd like to generate a controller scaffold for your model, see scaffold_controller. Just for clarity, here's the description on that:
Stubs out a scaffolded controller and its views. Pass the model name,
either CamelCased or under_scored, and a list of views as arguments.
The controller name is retrieved as a pluralized version of the model
name.
To create a controller within a module, specify the model name as a
path like 'parent_module/controller_name'.
This generates a controller class in app/controllers and invokes helper,
template engine and test framework generators.
To create your resource, you'd use the resource generator, and to create a migration, you can also see the migration generator (see, there's a pattern to all of this madness). These provide options to create the missing files to build a resource. Alternatively you can just run rails generate scaffold with the --skip option to skip any files which exist :)
I recommend spending some time looking at the options inside of the generators. They're something I don't feel are documented extremely well in books and such, but they're very handy.
Great answer by Lee Jarvis, this is just the command e.g; we already have an existing model called User:
rails g scaffold_controller User
For the ones starting a rails app with existing database there is a cool gem called schema_to_scaffold to generate a scaffold script.
it outputs:
rails g scaffold users fname:string lname:string bdate:date email:string encrypted_password:string
from your schema.rb our your renamed schema.rb. Check it
In Rails 5, you can still run
$rails generate scaffold movie --skip
to create all the missing scaffold files or
rails generate scaffold_controller Movie
to create the controller and view only.
For a better explanation check out rails scaffold
This command should do the trick:
$ rails g scaffold movie --skip
You can make use of scaffold_controller and remember to pass the attributes of the model, or scaffold will be generated without the attributes.
rails g scaffold_controller User name email
# or
rails g scaffold_controller User name:string email:string
This command will generate following files:
create app/controllers/users_controller.rb
invoke haml
create app/views/users
create app/views/users/index.html.haml
create app/views/users/edit.html.haml
create app/views/users/show.html.haml
create app/views/users/new.html.haml
create app/views/users/_form.html.haml
invoke test_unit
create test/controllers/users_controller_test.rb
invoke helper
create app/helpers/users_helper.rb
invoke test_unit
invoke jbuilder
create app/views/users/index.json.jbuilder
create app/views/users/show.json.jbuilder
I had this challenge when working on a Rails 6 API application in Ubuntu 20.04.
I had already existing models, and I needed to generate corresponding controllers for the models and also add their allowed attributes in the controller params.
Here's how I did it:
I used the rails generate scaffold_controller to get it done.
I simply ran the following commands:
rails generate scaffold_controller School name:string logo:json motto:text address:text
rails generate scaffold_controller Program name:string logo:json school:references
This generated the corresponding controllers for the models and also added their allowed attributes in the controller params, including the foreign key attributes.
create app/controllers/schools_controller.rb
invoke test_unit
create test/controllers/schools_controller_test.rb
create app/controllers/programs_controller.rb
invoke test_unit
create test/controllers/programs_controller_test.rb
That's all.
I hope this helps