Here is a simple lists where I like to change the numbers: the entries are as below and it got over 300 entries like it
tom112
smith113
harry114
linda115
cindy106
samantha147
It need to be changed to
tom212
smith213
harry214
...and so on.
Please assist using notepad++ regular expression.
Thanks.
Assuming it's just a matter of replacing a name followed by a number starting with 1 with the same number but starting with 2 instead:
Ctrl + H for search & replace.
Check Regular expression under Search Mode.
Next to Find what type or copy in ([a-zA-Z]+)1([0-9]+).
Next to Replace with type or copy in \12\2.
Click Replace All and that should do it.
Add any other characters that might appear in the name before the number inside the first set of brackets with a-zA-Z.
Related
Hello guys I want to convert my non delimited file into a delimited file
Example of the file is as follows.
Name. CIF Address line 1 State Phn Address line 2 Country Billing Address line 3
Alex. 44A. Biston NJ 25478163 4th,floor XY USA 55/2018 kenning
And so on all the data are in this format.
First three lines are metadata and then the data.
How can I make it delimited in proper format using logic.
There are two parts in the problem:
how to find the column widths
how to split each line into fields and output a new line with delimiters
I could not propose an automated solution for the first one, because (not knowing anything about the metadata format), there is no clear way to find where one column ends and the next one begins. Some of the column headings contain multiple space-separated words and space is also used as a separator between the headings (and apparently one cannot use the rule "more than one space means the end of a heading name" because there's only one space between "Address line 2" and "Country" - and they're clearly separate columns. Clearly, finding the correct column widths requires understanding English and this is not something that you can write a program for.
For the second problem, things are much easier - once you have the column positions. If you figure the column positions manually (or programmatically, if you know something about the metadata that I don't - and you have a simple method for finding what's a column heading), then a program written in AWK can do this, for example:
cols="8,15,32,40,53,66,83,105"
awk_prog='BEGIN {
nt=split(cols,tabs,",")
delim=","
ORS=""
}
{ o=1 ;
for (i in tabs) { t=tabs[i] ; f=substr($0,o,t-o); sub(" *$","",f) ; print f
delim ; o=t } ;
print substr($0, o) "\n"
}'
awk -v cols="$cols" "$awk_prog" input_file
NOTE that the above program does not deal correctly with the case when the separator character (e.g. ",") appears inside the data. If you decide to use this as-is, be sure to use a separator that is not present in the input data. It may be better to modify the code to escape any separator characters found in the input data (there are different ways to do this - depends on what you plan to feed the output file to).
I want to copy a table from iPython notebook into a Word doc. I'm using Word for Mac 2011. The table is a standard pandas output and looks like this:
If I use Apple+C to copy the table, and then paste it into a Word doc, I get this:
Surely there must be an easier way?
Creating a table with the same number of rows/columns in Word and then trying to paste the cells there doesn't work either.
I guess I could screenshot the table, but I'd like to include the raw data in the document if possible.
The problem in this case (from the Word perspective) is not the table layout - it's the paragraph layout. Each paragraph has a substantial indent on right and left, and more space before/after than you would normally want.
I don't think any of the Paste options (e.g. Paste Special) in Word is going to help, unless you paste as unformatted text, then select the text, convert to a table, then proceed from there.
But, even a simple Word VBA macro such as this one will leave you with something a bit more manageable. (Select a table you copied in, then run the macro). A little bit more work on the code would probably allow you to get most of the formatting you want, most of the time.
Sub fixupSelectedTable()
With Selection.Tables(1).Range.ParagraphFormat
.LeftIndent = 0
.RightIndent = 0
.SpaceBefore = 0
.SpaceAfter = 0
.LineSpacingRule = wdLineSpaceSingle
End With
End Sub
If you are more familiar with Applescript, the equivalent looks something like this:
-- you may need to fix up the application name
-- (I use this to ensure that the script uses the Open Word 2011 doc
-- and does not try to start Word for Mac 15 (2016))
tell application "/Applications/Microsoft Office 2011/Microsoft Word.app"
tell the paragraph format of the text object of table 1 of the text object of the selection
set paragraph format left indent to 0
set paragraph format right indent to 0
set space before to 0
set space after to 0
set line spacing rule to line space single
end tell
end tell
I am using TeXnicCenter to edit a LaTeX document.
I now want to remove a certain tag (say, emph{blabla}} which occurs multiple times in my document , but not tag's content (so in this example, I want to remove all emphasization).
What is the easiest way to do so?
May also be using another program easily available on Windows 7.
Edit: In response to regex suggestions, it is important that it can deal with nested tags.
Edit 2: I really want to remove the tag from the text file, not just disable it.
Using a regular expression do something like s/\\emph\{([^\}]*)\}/\1/g. If you are not familiar with regular expressions this says:
s -- replace
/ -- begin match section
\\emph\{ -- match \emph{
( -- begin capture
[^\}]* -- match any characters except (meaning up until) a close brace because:
[] a group of characters
^ means not or "everything except"
\} -- the close brace
and * means 0 or more times
) -- end capture, because this is the first (in this case only) capture, it is number 1
\} -- match end brace
/ -- begin replace section
\1 -- replace with captured section number 1
/ -- end regular expression, begin extra flags
g -- global flag, meaning do this every time the match is found not just the first time
This is with Perl syntax, as that is what I am familiar with. The following perl "one-liners" will accomplish two tasks
perl -pe 's/\\emph\{([^\}]*)\}/\1/g' filename will "test" printing the file to the command line
perl -pi -e 's/\\emph\{([^\}]*)\}/\1/g' filename will change the file in place.
Similar commands may be available in your editor, but if not this will (should) work.
Crowley should have added this as an answer, but I will do that for him, if you replace all \emph{ with { you should be able to do this without disturbing the other content. It will still be in braces, but unless you have done some odd stuff it shouldn't matter.
The regex would be a simple s/\\emph\{/\{/g but the search and replace in your editor will do that one too.
Edit: Sorry, used the wrong brace in the regex, fixed now.
\renewcommand{\emph}[1]{#1}
any reasonably advanced editor should let you do a search/replace using regular expressions, replacing emph{bla} by bla etc.
Could anybody help me make a proper regular expression from a bunch of text in Ruby. I tried a lot but I don't know how to handle variable length titles.
The string will be of format <sometext>title:"<actual_title>"<sometext>. I want to extract actual_title from this string.
I tried /title:"."/ but it doesnt find any matches as it expects a closing quotation after one variable from opening quotation. I couldn't figure how to make it check for variable length of string. Any help is appreciated. Thanks.
. matches any single character. Putting + after a character will match one or more of those characters. So .+ will match one or more characters of any sort. Also, you should put a question mark after it so that it matches the first closing-quotation mark it comes across. So:
/title:"(.+?)"/
The parentheses are necessary if you want to extract the title text that it matched out of there.
/title:"([^"]*)"/
The parentheses create a capturing group. Inside is first a character class. The ^ means it's negated, so it matches any character that's not a ". The * means 0 or more. You can change it to one or more by using + instead of *.
I like /title:"(.+?)"/ because of it's use of lazy matching to stop the .+ consuming all text until the last " on the line is found.
It won't work if the string wraps lines or includes escaped quotes.
In programming languages where you want to be able to include the string deliminator inside a string you usually provide an 'escape' character or sequence.
If your escape character was \ then you could write something like this...
/title:"((?:\\"|[^"])+)"/
This is a railroad diagram. Railroad diagrams show you what order things are parsed... imagine you are a train starting at the left. You consume title:" then \" if you can.. if you can't then you consume not a ". The > means this path is preferred... so you try to loop... if you can't you have to consume a '"' to finish.
I made this with https://regexper.com/#%2Ftitle%3A%22((%3F%3A%5C%5C%22%7C%5B%5E%22%5D)%2B)%22%2F
but there is now a plugin for Atom text editor too that does this.
vi treats dash - and space as word separators for commands such as dw and cw.
Is there a way to add underscore _ as well?
I quite often want to change part of a variable name containing underscores, such as changing src_branch to dest_branch. I end up counting characters and using s (like 3sdest), but it would be much easier to use cw (like cwdest).
Is there a way to add underscore _ as well?
:set iskeyword-=_
What is, and is not a member character to keywords depends on the language. For help on iskeyword use :help iskeyword.
In case you're using vim, you can change that by setting the iskeyword option (:he iskeyword). If that is not an option, you can always use ct_ instead of counting.
One other good option in such cases is to use camelcasemotion plugin.
It adds new motions ,b, ,e, and ,w, which work analogously with b, e, and w, except that they recognize CamelCase and snake_case words. With it you can use
c,edest
and this will replace "src_branch" with "dest_branch" if your cursor was on first character of "src_branch".
You could type cf_dest_ and save the counting part.
Edit: or as suggested: ct_ changes text until right before the underline character. (I'm using the f motion more, so it came more naturally to me)
Or you could redefine 'iskeyword' (:help iskeyword for details).
I was just looking at this myself and added this to my .vimrc:
set iskeyword=!-~,^*,^45,^124,^34,192-255,^_
My .vimrc had issues with ^| and ^", which was part of the default iskeyword for my setup, so I changed to their ascii values and it works fine. My main modification was to add "^_" to the end of the default setting to keep vim from seeing underscore as being part of a word.
To delete to the next underscore enter "df_"
To change to the next underscore enter "cf_"
NOTE: don't include the double quotes.