Add node into XML if another node doesn't exist - xslt-2.0

Question

I am new to XSLT and working on transformation from one XML to another and facing below issue
If Book 1 node exist then I should not see Book 2 node into transformed XML. I tried different phrases but doesn't work.
Input XML
<?xml version="1.0" encoding="UTF-8"?>
<Catalog>
<book1>Wise Otherwise</book1>
<book2>Great Expectations</book2>>
</Catalog>
Expected XML
Wise Otherwise
Below is my XSL
<?xml version="1.0" encoding="UTF-8"?>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:if test="book1">
<xsl:template match="book2" />
</xsl:if>
<xsl:if test="not(book1)">
<xsl:template match="book2">
<book2>
<xsl:apply-templates />
</book2>
</xsl:template>
</xsl:if>
</xsl:stylesheet>
I even tried xsl:Choose
<xsl:choose>
<xsl:when test="/catalog/book1">
<xsl:template match="book2" />
</xsl:when>
<!-- more xsl:when here, if needed -->
<xsl:otherwise>
<xsl:template match="book2">
<book2>
<xsl:apply-templates />
</book2>
</xsl:template>
</xsl:otherwise>
</xsl:choose>
Book1 and Book2 are mutual exclusion from transformed xml.
Book2 should be in transformed XML if and only if Book1 is not in input XML.
I hope this will give you better picture
Thanks

Answer 1

Use a stylesheet with the identity transformation template
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
and the template <xsl:template match="Catalog[Book-1]/Book-2"/>.
Based on your provided XML sample a complete XSLT stylesheet is
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Catalog[book1]/book2"/>
</xsl:stylesheet>
which transforms
<Catalog>
<book1>Wise Otherwise</book1>
<book2>Great Expectations</book2>
</Catalog>
into
<Catalog>
<book1>Wise Otherwise</book1>
</Catalog>