How to create a predicate that compares all properties of an object? - ios

Question

For example, I have an object that has three properties: firstName, middleName, lastName.
If I want to search a string "john" in all the properties using NSPredicate.
Instead of creating a predicate like:
[NSPredicate predicateWithFormat:#"(firstName contains[cd] %#) OR (lastName contains[cd] %#) OR (middleName contains[cd] %#)", #"john", #"john", #"john"];
Can I do something like:
[NSPredicate predicateWithFormat:#"(all contains[cd] %#), #"john"];

Answer 1

"all contains" does not work in a predicate, and (as far as I know) there is no similar syntax to get the desired result.
The following code creates a "compound predicate" from all "String" attributes in the entity:
NSString *searchText = #"john";
NSEntityDescription *entity = [NSEntityDescription entityForName:#"Entity" inManagedObjectContext:context];
NSMutableArray *subPredicates = [NSMutableArray array];
for (NSAttributeDescription *attr in [entity properties]) {
if ([attr isKindOfClass:[NSAttributeDescription class]]) {
if ([attr attributeType] == NSStringAttributeType) {
NSPredicate *tmp = [NSPredicate predicateWithFormat:#"%K CONTAINS[cd] %#", [attr name], searchText];
[subPredicates addObject:tmp];
}
}
}
NSPredicate *predicate = [NSCompoundPredicate orPredicateWithSubpredicates:subPredicates];
NSLog(#"%#", predicate);
// firstName CONTAINS[cd] "john" OR lastName CONTAINS[cd] "john" OR middleName CONTAINS[cd] "john"

Answer 2

You can do it in such way like,
NSMutableArray *allTheContaint = [[NSMutableArray alloc] init];
[allTheContaint addObject:allTheContaint.firstName];
[allTheContaint addObject:allTheContaint.middleName];
[allTheContaint addObject:allTheContaint.lastName];
NSPredicate *predicateProduct = [NSPredicate predicateWithFormat:#"SELF CONTAINS[cd] %#", #"john"];
NSArray *filteredArray = [self.listOfProducts filteredArrayUsingPredicate:predicateProduct];
NSLog(#"%#", filteredArray);
But it is fix. :( not for dynamic :)