I have a set of nodes with a property, myproperty = "James" I want to update that property from (myproperty) to (name).
Is there any way to this with Cypher?
Solved by myself, heres what I did:
MATCH (n:term)
SET n.name = n.label
REMOVE n.label
RETURN n
You can change your old column name by using following query
MATCH (n:term)
SET n.name = n.myproperty
REMOVE n.myproperty
RETURN n
match (a:employee {employeeId:123,location:1})
set a.newProperty=a.oldProperty
remove a.oldProperty
return a;
Related
I am new with Neo4j and I am stucked trying to get a query with two conditions, where I want to get all the "Autors" related to "Pixar" and "Fox". So far I have tried the following two ways:
MATCH (a:Autor)- [:AUTOR_DE]-> (t:Título) -[:PRODUCIDO_POR] ->( p:Productora {Nombre: "Pixar"}),
and
MATCH (a:Autor)- [:AUTOR_DE]-> (t:Título) -[:PRODUCIDO_POR] ->( p:Productora {Nombre: "Fox"}),
return a,p
and
MATCH (a:Autor)- [:AUTOR_DE]-> (t:Título) -[:PRODUCIDO_POR] ->( p:Productora)
WHERE ( (p:Productora) = "Fox" OR (p:Productora) = "Pixar")
return a,p
Thanks in advance
Assuming that a Productora node stores its name in a name property, and that every Productora node has a unique name, this should work:
MATCH (a:Autor)-[:AUTOR_DE]->(:Título)-[:PRODUCIDO_POR]->(p:Productora)
WHERE p.name = "Fox" OR p.name = "Pixar"
WITH a, COLLECT(DISTINCT p) AS ps
WHERE SIZE(ps) = 2
return a, ps
And this should also work:
MATCH (fox:Productora), (pixar:Productora), (a:Autor)
WHERE fox.name = "Fox" AND pixar.name = "Pixar" AND
(a)-[:AUTOR_DE]->(:Título)-[:PRODUCIDO_POR]->(fox) AND
(a)-[:AUTOR_DE]->(:Título)-[:PRODUCIDO_POR]->(pixar)
return a, fox, pixar
I have this kind of graph:
I want to retrieve all Products that have pending or open requests. This is how Im trying
MATCH (s:ServiceRequest {srStatus: "Open"} OR {srStatus: "Pending"}) -[:FOR]->(p:Product) RETURN p
But this does not work. How can I do that?
This should work:
MATCH (s:ServiceRequest)-[:FOR]->(p:Product)
WHERE s.srStatus IN ["Open", "Pending"]
RETURN p;
and so should this:
MATCH (s:ServiceRequest)-[:FOR]->(p:Product)
WHERE s.srStatus = "Open" OR s.srStatus = "Pending"
RETURN p;
I'm trying to get Total(Sum) of a property of "df" object.I have attached screen shot of sample database I'm using
I tried to get the graph using following query
MATCH P= (n:Org)-[:O_CH*0..]->()-[:LEAF*0..]->()-[:CH*0..]->()-[:FOR*0..]->() RETURN P
To create objects
create(n:Org{name:'Root',id:1})
create(n:Org{name:'L1.1',id:2,parent:1})
create(n:Org{name:'L1.2',id:3,parent:1})
create(n:Org{name:'L1.3',id:4,parent:1})
create(n:Org{name:'L2.1',id:5,parent:3})
create(n:Org{name:'L2.2',id:6,parent:4})
create(n:Op{name:'CH1',id:7,orgId:5})
create(n:Op{name:'CH2',id:8,orgId:5 ,parent:'CH1'})
create(n:Proj{name:'P1',id:9,opp:'CH2'})
create(n:Proj{name:'P2',id:10,opp:'CH1'})
create(n:R{name:'R1',id:200,orgId:2 })
create (n:df{id:100,map:8,forecast:toFloat(10)})
create (n:df{id:101,map:7,forecast:toFloat(10)})
create (n:df{id:102,map:9,forecast:toFloat(10)})
create (n:df{id:103,map:10,forecast:toFloat(10)})
create (n:df{id:104,map:200,forecast:toFloat(10)})
To Crate relationships
MATCH (c:Org),(p:Org) WHERE c.parent = p.id create (p)-[:O_CH]->(c)
MATCH (c:Op),(p:Op) WHERE c.parent = p.name create (p)-[:CH]->(c)
MATCH (c:Op),(p:Org) WHERE c.orgId = p.id create (p)-[:LEAF]->(c)
MATCH (c:Proj),(p:Op) WHERE c.opp = p.name create (p)-[:CH]->(c)
MATCH (c:R),(p:Org) WHERE c.orgId = p.id create (p)-[:LEAF]->(c)
MATCH (c:df),(p:) WHERE c.map = p.id create (p)-[:FOR]->(c)
I'm expecting 60 as total where I get 260 as total. Please let me know where I'm wrong . Need your help to figure out.
I'm trying to get Total(Sum) of a property of "df" object.
I believe you needs a simple query that match all nodes with label :df and return the sum of node.forecast. Try it:
// Match all nodes with :df label
MATCH(n:df)
// Return the sum of the property 'forecast' of each matched node
RETURN sum(n.forecast)
From comments:
Thank you Bruno.But the thing i need to get the aggregated value as a
example if i select L2.1 , i need to get the sum of df objects which
are under that node
This should work:
MATCH({name:'L2.1'})-[*]->(n)
RETURN SUM(n.forecast)
How do I get with cypher the minimum value of array with properties?
MATCH (n)-[r]->(m) RETURN n,m,min(r.timestamps)
Above query does not work.
r has an array with timestamps r.timestamps
How to get the lowest value of timestamps?
You can use unwind:
MATCH (n)-[r]->(m)
UNWIND r.timestamps as timestampts
RETURN n, m, min(timestampts)
I found an answer like this, but it looks ugly
MATCH
(h1)-[r]-(h2)
RETURN h1, h2,
reduce(minTimestamp = 999999999999999999, t IN r.timestamps | CASE WHEN minTimestamp < t THEN minTimestamp ELSE t END)
The following query fails:
MATCH n:User
WHERE n.email = "test"
SET n = {data}, n.created = timestamp()
RETURN n
Is this expected? Is it a bug? Is there a workaround? Do I have to compute the timestamp and send it along with {data}?
A slight modification of your statement using 2 SET clauses works:
MATCH n:User
WHERE n.email = "test"
SET n = {data}
SET n.created = timestamp()
RETURN n