Trying to enter the following text fails:
MERGE (people:People {Person:'Abe N. O'Sullivan'})
Replacing the apostrophe with a ’ works, but I wonder if there is a more ellegant solution.
Use double quotes, and it will work fine:
MERGE (people:People {Person:"Abe N. O'Sullivan"})
Note if this were the name of a property, you can use backticks to escape the name of a property that has spaces or special characters in it. For text literals, you can surround them with either single or double quotes. If you want to put a quote inside of a text literal quote, you either need to use the other kind of quote to surround the string, or you need to escape it with backslash, I believe.
Related
I have following regex handy to match all the lines containing console.log() or alert() function in any javascript file opened in the editor supporting PCRE.
^.*\b(console\.log|alert)\b.*$
But I encounter many files containing window.alert() lines for alerting important messages, I don't want to remove/replace them.
So the question how to regex-match (single line regex without need to run frequently) all the lines containing console.log() and alert() but not containing word window. Also how to escape round brackets(parenthesis) which are unescapable by \, to make them part of string literal ?
I tried following regex but in vain:
^.*\b(console\.log|alert)((?!window).)*\b.*$
You should use a negative lookhead, like this:
^(?!.*window\.).*\b(console\.log|alert)\b.*$
The negative lookhead will assert that it is impossible to match if the string window. is present.
Regex Demo
As for the parenthesis, you can escape them with backslashes, but because you have a word boundary character, it will not match if you put the escaped parenthesis, because they are not word characters.
The metacharacter \b is an anchor like the caret and the dollar sign.
It matches at a position that is called a "word boundary". This match
is zero-length.
There are three different positions that qualify as word boundaries:
Before the first character in the string, if the first character is a
word character.
After the last character in the string, if the last
character is a word character.
Between two characters in the string,
where one is a word character and the other is not a word character.
Apple's documentation states the followings about the value of a key.
Default value strings may contain extended ASCII characters.
...
Just as in C, some characters must be prefixed with a backslash before you can include them in the string. These characters include double quotation marks, the backslash character itself, and special control characters such as linefeed (\n) and carriage returns (\r).
In my experience it did't matter if I used ' or \', after calling the localizedStringForKey:value:table: method the result was the same.
question: why?
question: is there an explicit list somewhere which lists all the characters which must be escaped and which can be (meaning that the result will be the same)?
I want to define an array in ruby in following manner
A = ["\"]
I am stuck here for hours now. Tried several possible combinations of single and double quotes, forward and backward slashes. Alas !!
I have seen this link as well : here
But couldn't understand how to resolve my problem.
Apart from this what I need to do is -
1. Read a file character by character (which I managed to do !)
2. This file contains a "\" character
3. I want to do something if my array A includes this backslash
A.includes?("\")
Any help appreciated !
There are some characters which are special and need to be escaped.
Like when you define a string
str = " this is test string \
and this contains multiline data \
do you understand the backslash meaning here \
it is being used to denote the continuation of line"
In a string defined in a double quotes "", if you need to have a double quote how would you doo that? "\"", this is why when you put a backslash in a string you are telling interpretor you are going to use some special characters and which are escaped by backslash. So when you read a "\" from a file it will be read as "\" this into a ruby string.
char = "\\"
char.length # => 1
I hope this helps ;)
Your issue is not with Array, your question really involves escape sequences for special characters in strings. As the \ character is special, you need to first prepend it (escape it) with a leading backslash, like so.
"\\"
You should also re-read your link and the section on escape sequences.
You can escape backslash with a backslash in double quotes like:
["\\"].include?("\\")
Is there any difference between enclosing grep patterns in single and double quotes?
grep "abc" file.txt
and
grep 'abc' file.txt
I'm asking since there's no way I could test all possible cases on my own, and I don't want to stumble into a case that I get wrong :)
I see a difference if you have special characters :
Ex :
grep "foo$barbase" file.txt
The shell will try to expand the variable $barbase, this is maybe not what you intended to do.
If instead you type
grep 'foo$barbase' file.txt
$bar is taken literally.
Finally, always prefer single quotes by default, it's stronger.
In double quote, the following characters has special meanings: ‘$’,
‘`’, ‘\’, and, when history expansion is enabled, ‘!’.
The characters ‘$’ and ‘’ retain their special meaning within double
quotes ($ for variables and for executing).
The special parameters ‘*’ and ‘#’ retain their special meaning in
double quotes as inputs when proceeded by $.
‘$’, ‘`’, ‘"’, ‘\’, or newline can be escaped by preceding them with
a backslash.
The backslash retains its special meaning when followed by ‘$’, ‘`’,
‘"’, ‘\’, or newline. Backslashes preceding characters without a
special meaning are left unmodified.
Also it will be helpful to check shell expansions:
https://www.gnu.org/software/bash/manual/html_node/Shell-Expansions.html#Shell-Expansions
Single quote ignore shell expansions.
How do I remove this backslash?
s = "\""
I have tried s.gsub("\\", "") and that doesn't remove it, it returns the same string.
there's actually no backslash character in your String. The Backslash in your example simply escapes the following double quote and prevent's that it would terminate the string and thereby resulting in a syntax error (unterminated double quote ).
So what you see when you print that string in IRB is actually not the backslash as is, but the backslash in combination with the following dobule quote as an indication that the double quote is escaped. Kind of hard to grasp when you encounter it the first time. Have a look at http://en.wikibooks.org/wiki/Ruby_Programming/Strings#Escape_sequences
long story short: there is no backslash in your string so you can't remove it :)
gsub takes a regular expression as the first parameter. I believe that if you pass it a string, it will first convert it into a regex. This means you need extra escaping:
s.gsub("\\\\", "")
If you use regex notation, you can stop it from doubling up:
s.gsub(/\\/, "")
This is because you don't have to escape twice: once because double-quoted strings need you to escape the \ character, and once because the regular expression requires you to as well.
that's actually an escape quote sign (do a print s to see it)
I'm not sure if this is a solution to YOUR problem, but seeing that this is one of the first SO questions I looked at when trying to solve my problem and have in fact, solved it, here is what I did to fix my problem.
So I had some CSV.read output with a load of \ (backslashes) and unwanted quotation marks.
arr_of_arrays = CSV.read("path/to/file.csv")
processed_csv = arr_of_arrs.map {|t| eval(t)}
the key here is the eval() method.