Youtube api v3 Get list of user's videos - youtube

Question

With Youtube api v2, there's easy way to get videos. Just send a query like this:
http://gdata.youtube.com/feeds/mobile/videos?max-results=5&alt=rss&orderby=published&author=OneDirectionVEVO
The Youtube api v2 also has an interactive demo page for building query:
http://gdata.youtube.com/demo/index.html
With Youtube api v3, I don't know the corresponding way. Please point me the way with api v3.
Thank you!

Answer 1

The channels#list method will return a JSON with some information about the channel, including the playlist ID for the "uploads" playlist:
https://www.googleapis.com/youtube/v3/channels?part=contentDetails&forUsername=OneDirectionVEVO&key={YOUR_API_KEY}
With the playlist ID you can get the videos with the playlistItems#list method:
https://www.googleapis.com/youtube/v3/playlistItems?part=snippet&playlistId=UUbW18JZRgko_mOGm5er8Yzg&key={YOUR_API_KEY}
You can test those at the end of the documentation pages.

Answer 2

This should do it. This code just gets and outputs the title but you can get any details you want
// Get Uploads Playlist
$.get(
"https://www.googleapis.com/youtube/v3/channels",{
part : 'contentDetails',
forUsername : 'USER_CHANNEL_NAME',
key: 'YOUR_API_KEY'},
function(data) {
$.each( data.items, function( i, item ) {
pid = item.contentDetails.relatedPlaylists.uploads;
getVids(pid);
});
}
);
//Get Videos
function getVids(pid){
$.get(
"https://www.googleapis.com/youtube/v3/playlistItems",{
part : 'snippet',
maxResults : 20,
playlistId : pid,
key: 'YOUR_API_KEY'},
function(data) {
var results;
$.each( data.items, function( i, item ) {
results = '<li>'+ item.snippet.title +'</li>';
$('#results').append(results);
});
}
);
}
<!--In your HTML -->
<ul id="results"></ul>

Answer 3

If quota cost is a consideration, it may be beneficial to follow this simple algorithm.
First grab the data from https://www.youtube.com/feeds/videos.xml?channel_id=... This is a simple XML feed which will give you the video ID's, but you cannot specify further 'parts' (stats, etc).
Using the video ID's from that list, do a query on the /videos API endpoint which allows for a comma-separated-list of video ID's which should only result in 1 quota cost, plus 0-2 for any additional part parameters. As #chrismacp points out, using the /search endpoint is simpler but has a quota cost of 100, which can add up quickly.
There is a resource consideration here (cpu, memory, etc) as you are making a second call, but I believe in many scenarios this can be a useful method.

Answer 4

Things have changed alot in V3 of the API. Here is a video that walks you through the v3 API calls needed to get a list of the videos uploaded in a given channel, with live demos using the API Explorer.
YouTube Developers Live: Getting a Channel's Uploads in v3 - https://www.youtube.com/watch?v=RjUlmco7v2M

Answer 5

In case it helps anyone here this is what I discovered and so far seems to be working well for me. I am authenticating the member via OAuth 2.0 prior to making this request, which will give me the authenticated members videos. As always, your personal mileage may vary :D
curl https://www.googleapis.com/youtube/v3/search -G \
-d part=snippet \
-d forMine=true \
-d type=video \
-d order=date \
-d access_token={AUTHENTICATED_ACCESS_TOKEN}

Answer 6

The equivalent of the request you posted is actually a search in the 3.0 api, not a playlist request. It's easier too to do it that way. You do need to excange the username for a channel ID though.
ex. GET https://www.googleapis.com/youtube/v3/playlistItems?part=snippet&playlistId=UUGhCVGZ0ZSpe5hJHWyiLwHA&key={YOUR_API_KEY}

Answer 7

Here is some code using the offical Google APIs Node library (https://github.com/google/google-api-nodejs-client)
const readJson = require("r-json");
const google = require('googleapis');
const Youtube = google.youtube('v3');
// DONT store your credentials in version control
const CREDENTIALS = readJson("/some/directory/credentials.json");
let user = "<youruser>";
let numberItems = 10;
let channelConfig = {
key: CREDENTIALS.youtube.API_KEY,
part: "contentDetails",
forUsername: user
};
Youtube.channels.list(channelConfig, function (error, data) {
if (error) {
console.log("Error fetching YouTube user video list", error);
return;
}
// Get the uploads playlist Id
let uploadsPlaylistId = data.items[0].contentDetails.relatedPlaylists.uploads;
let playlistConfig = {
part : 'snippet',
maxResults : size,
playlistId : uploadsPlaylistId,
key: CREDENTIALS.youtube.API_KEY
};
// Fetch items from upload playlist
Youtube.playlistItems.list(playlistConfig, function (error, data) {
if (error) {
console.log("Error fetching YouTube user video list", error);
}
doSomethingWithYourData(data.items);
});
});

Answer 8

An alternative method may be to get the playlists for the currently oauth authenticated user via: property mine=true
where the oauth access_token is retrieved following authentification:
https://developers.google.com/youtube/v3/guides/authentication
https://www.googleapis.com/youtube/v3/playlists?part=id&mine=true&access_token=ya29.0gC7xyzxyzxyz

Answer 9

Please don't use playlistitems.list if you want to get the videos of playlist with more then 300 videos. You can try it live in google link "https://developers.google.com/youtube/v3/docs/playlistItems/list" in "Try it" section. It returns undefined.
I have used in my project also. It returns undefined only.

Answer 10

In PHP:
I used pageToken attribute to go to all page of playlist.I hope it can help you.
//step 1: get playlist id
$response = file_get_contents("https://www.googleapis.com/youtube/v3/channels?key={$api_key}&forUsername={$channelName}&part=contentDetails");
$searchResponse = json_decode($response,true);
$data = $searchResponse['items'];
$pid = $data[0]['contentDetails']['relatedPlaylists']['uploads'];
//step 2: get all videos in playlist
$nextPageToken = '';
while(!is_null($nextPageToken)) {
$request = "https://www.googleapis.com/youtube/v3/playlistItems?key={$api_key}&playlistId={$pid}&part=snippet&maxResults=50&pageToken=$nextPageToken";
$response = file_get_contents($request);
$videos = json_decode($response,true);
//get info each video here...
//go next page
$nextPageToken = $videos['nextPageToken'];
}

Answer 11

In node.js, it can be achieved with following code.
Requires authKey and channelId as options object parameter.
cb callback is called after data is fetched.
async function fetchChannelInfo(options) {
const channelUrl = `https://www.googleapis.com/youtube/v3/channels?part=contentDetails,statistics&id=${
options.channelId
}&key=${options.authKey}`;
const channelData = await axios.get(channelUrl);
return channelData.data.items[0];
}
function fetch(options, cb) {
fetchChannelInfo(options).then((channelData) => {
options.playlistId = channelData.contentDetails.relatedPlaylists.uploads;
const paylistUrl = `https://www.googleapis.com/youtube/v3/playlistItems?part=snippet&playlistId=${
options.playlistId
}&key=${options.authKey}`;
axios
.get(paylistUrl)
.then((response) => {
const payloadData = ;
const videoList = [];
response.data.items.forEach((video) => {
videoList.push({
publishedAt: video.snippet.publishedAt,
title: video.snippet.title,
thumbnails: thumbnails,
videoId: video.snippet.resourceId.videoId,
});
});
cb(null, videoList);
})
.catch((err) => {
cb(err, null);
});
});
}
Note: axios is used for RESTful requests. To install
npm install axios

Answer 12

$.get(
"https://www.googleapis.com/youtube/v3/channels",{
part: 'snippet,contentDetails,statistics,brandingSettings',
id: viewid,
key: api},
function(data){
$.each(data.items, function(i, item){
channelId = item.id;
pvideo = item.contentDetails.relatedPlaylists.uploads;
uploads(pvideo);
});
});
Uploads Function can be
function uploads(pvideo){
$.get(
"https://www.googleapis.com/youtube/v3/playlistItems",{
part: 'snippet',
maxResults:12,
playlistId:pvideo,
key: api},
function(data){
$.each(data.items, function(i, item){
videoTitle = item.snippet.title;
videoId = item.id;
description = item.snippet.description;
thumb = item.snippet.thumbnails.high.url;
channelTitle = item.snippet.channelTitle;
videoDate = item.snippet.publishedAt;
Catagoryid = item.snippet.categoryId;
cID = item.snippet.channelId;
})
}
);
}

Answer 13

function tplawesome(e,t){res=e;for(var n=0;n<t.length;n++){res=res.replace(/\{\{(.*?)\}\}/g,function(e,r){return t[n][r]})}return res}
$(function() {
$(".form-control").click(function(e) {
e.preventDefault();
// prepare the request
var request = gapi.client.youtube.search.list({
part: "snippet",
type: "video",
q: encodeURIComponent($("#search").val()).replace(/%20/g, "+"),
maxResults: 20,
order: "viewCount",
publishedAfter: "2017-01-01T00:00:00Z"
});
// execute the request
request.execute(function(response) {
var results = response.result;
$("#results").html("");
$.each(results.items, function(index, item) {
$.get("tpl/item.html", function(data) {
$("#results").append(tplawesome(data, [{"title":item.snippet.title, "videoid":item.id.videoId ,"descrip":item.snippet.description ,"date":item.snippet.publishedAt ,"channel":item.snippet.channelTitle ,"kind":item.id.kind ,"lan":item.id.etag}]));
});
});
resetVideoHeight();
});
});
$(window).on("resize", resetVideoHeight);
});
function resetVideoHeight() {
$(".video").css("height", $("#results").width() * 9/16);
}
function init() {
gapi.client.setApiKey("YOUR API KEY .... USE YOUR KEY");
gapi.client.load("youtube", "v3", function() {
// yt api is ready
});
}
Check the Complete code here https://thecodingshow.blogspot.com/2018/12/youtube-search-api-website.html