try this.
in cell A1 10/8/2013 Mike1, 2013, 0
now Split(A1,",")
now change A1 and add a colon 10/8/2013 Mike:1, 2013, 0
Split(A1,",") ... notice how Mike:1 is gone. Bug?
I need to split something with a colon in it and it is chopping off part of the text
The problem is that "10/8/2013 Mike:1" is interpreted as a date, it seems to be something like: "dd/mm/yyyy hhhh:mm". (if you change the display of the first cell to raw text you'll see he is giving you a number: 41496).
try this formula:
=arrayformula(SUBSTITUTE(arrayformula(split(REGEXREPLACE(A1;":";"###");","));"###";":"))
in a easier way: As I suppose you can't change the way it's displayed, the possible workaround that I see here is to first split around the ":", then split with the "," and then join the two first elements.
I can't reproduce this issue, either with function SPLIT or with Split text into columns... and with or without formatting as dd/mm/yyyy hhhh:mm.
Select A1, Data > Split text into columns... is all that is required.
Related
I need to add a 0 before all cells in the A column on Google Sheets. Is there a code or formatting function I can add in? I need them to look like A2. A3 is what I have right now. There are a total of 783 that were extracted like this and I don't wanna do this manually
I tried formatting a few ways but I'm still a beginner in Sheets & Excel
You can try with ARRAYFORMULA in another column:
=ARRAYFORMULA(0&A1:A)
=INDEX(0&A1:A)
(PS: you may change A1:A with A1:A783)
If you want to just change the values in that column, you may use FIND AND REPLACE --> (Edit -> Find and Replace), be sure you tick "Search using regular expressions". Put to find ^ and to replace 0
NOTE: thanks to #rockinfreakshow, prior this second option, first format to plain text:
And then do the replacement:
You can use this formula in the adjacent cell:
Then you apply it across all your rows.
Do not forget to copy and paste as values.
Here is a screenshot of and a link to my test spreadsheet. It makes the requirements very clear:
https://docs.google.com/spreadsheets/d/1rZr2zHaSkff9SFpwpx83_4TawruotA1jhOKqW6uYDz0/edit?usp=sharing
The formula I have come up with is very close to what I need, but "linkText" is a placeholder for the value of the array item. Here is my formula:
=if(A2="","","<a href='https://samplewebsite.com/search?q=" & trim(lower(substitute(A2,",","'>linkText</a>, <a href='https://samplewebsite.com/search?q="))) & "'>linkText</a>")
try:
=index(join(","&char(10), SUBSTITUTE($B$1, "linkText", split(A3, ","))))
Drag down to column.
Result:
First using SPLIT to split the strings between comma from the column A. Then using SUBSTITUTE to find the string "linkText" from the text in B1 and replace it with the strings from the returned strings from the split function. Then joining them all together.
NOTE: Just keep the reference string in a fixed cell in your sheet. <a href='https://samplewebsite.com/search?q=linkText'>linkText</a> to be used in the formula. As seen in above screenshot it is fixed in cell B1.
Alternate Solution using ArrayFormula:
You can also use it with arrayformula so you only have to put it in the first row and no need to drag down the formula to the column, it will automatically be expanded down just make sure to clear the cells below or it will throw an error.
=arrayformula(regexreplace(substitute(transpose(query(transpose(IF(IFERROR(SPLIT(A2:A, ","))<>"", "♦<a href='https://samplewebsite.com/search?q="&SPLIT(A2:A, ",")&"'>"&SPLIT(A2:A, ",")&"</a>", )),,9^9)), "♦", char(10)), "^\s", ""))
Result:
You may also have a look in below references for more information.
References:
SUBSTITUTE
SPLIT
JOIN
Comma separated list into matched columns pairings
I have a data set wherein emails are populated. I would like to list all the surnames extracted in the emails per cell and will be all joined to a one single cell but I want to put a separator or delimeter to the emails obtaine per cell.
Here is the data set:
A
B
john.smith#gmail.com, jane.doe#gmail.com
UPDATE
john.smith#gmail.com
CLOSE
And here is the formula to extract
=ARRAYFORMULA(
PROPER(
REGEXEXTRACT(
A:A,
REGEXREPLACE(
A:A,
"(\w+)#","($1)#"
)
)
)
)
This initially yields the ff:
C
D
Smith
Doe
Smith
I would like to use JOIN() inside the ARRAYFORMULA() but it is not working as I seem to think it would since it outputs an error that it only accepts one row or one column of data. My initial understanding of ARRAYFORMULA() is that it iterates through the course of the data, so I thought it will JOIN() first, and then move on to the next element/row but I guess it doesn't work that way. I can use FLATTEN() but I want to have delimiters or separators in between the row elements. I need help in obtaining my intended final result which will look like this:
UPDATE:
Smith
Doe
CLOSE:
Smith
All are located in one cell, C1. UPDATE and CLOSE are from column B.
EDIT: I would like to clarify that the email entries in column A are dynamic and maybe more than two.
I think this will work:
=arrayformula(flatten(if(A2:A<>"",regexreplace(trim(split(B2:B&":"&char(9999)®exreplace(Proper(A2:A),"#[\w\.]+,\ ?|#.*",char(9999)&" "),char(9999))),".*\.",),)))
NOTES:
Proper(A2:A) changes the capitalisation.
The regexreplace "#[\w\.]+,\ ?|#.*" finds:
# symbol...
then any number of A-Z, a-z, 0-9, _ [using \w] or . [using \.]
then a comma
then 'optionally' a space \ [the optional bit is ?]
or [using |], the # symbol then an number of characters [using .*]
The result is replaced with a character that you won't expect to have in your text - char(9999) which is a pencil icon, and a trailing space (used later on when the flatten keeps a gap between lines). The purpose is to get all of the 'name.surname' and 'nameonly' values in front of any # symbol and separate them with char(9999).
Then infront of the regexreplace is B2:B&":"&char(9999)& which gets the value from column B, the : chanracter and char(9999).
The split() function then separates then into columns. Trim() is used to get rid of spaces in front of names that don't contain ..
The next regexreplace() function deletes anything before, and including . to keep surname or name without ..
The if(A2:A<>"" only process rows where there is a value in col A. The arrayformula() function is required to cascade the formula down the sheet.
I didn't output the results in a single cell, but it looks like you've sorted that with textjoin.
Here's my version of getting the results into a single cell.
=arrayformula(textjoin(char(10),1,if(A2:A<>"",REGEXREPLACE(B2:B&":"&char(10)®exreplace(Proper(A2:A),"#[\w\.]+,\ ?|#.*",char(10)),".*\.",),)))
Assuming that your A:A cells will always contain only contiguous email addresses separated by commas, you could place this in, say, C1 (being sure that both Columns C and D are otherwise empty beforehand):
=TRANSPOSE(FILTER({B:B,IFERROR(REGEXEXTRACT(SPLIT(PROPER(A:A),","),"([^\.]+)#"))},A:A<>""))
If this produces the desired result and you'd like to know how it works, report back. The first step, however, is to make sure it works as expected.
use:
=INDEX(REGEXREPLACE(TRIM(QUERY(FLATTEN(QUERY(TRANSPOSE({{B1; IF(B2:B="",,"×"&B2:B)},
PROPER(REGEXEXTRACT(A:A, REGEXREPLACE(A:A, "(\w+)#", "($1)#")))})
,,9^9)),,9^9)), " |×", CHAR(10)))
In A1 cell I have A,B,C,,E. I want to split the cell into five cells: A , B, C, , E
This formula =split(A1,",") splits into four cells A, B, C, E and skips over the blank.
How do I tell it to split "properly"?
I don't think you can specify that directly, though here is a workaround:
Add another delimiter character to your string. So replace , with say ,|
Now when you split with ,, we know for sure that even empty columns will have a character (in this case |)
Use replace to substitute the extra delimiter | with a blank string
Since output of split is an array, you will need to use arrayformula
Here is what the final formula would look like
=arrayformula(substitute(split(substitute(A1,",",",|"),","), "|",""))
If you use FALSE as the fourth argument, it will work as expected.
Try using
=SPLIT(A2,",", TRUE, FALSE)
and you won't need to do work arounds
For a workaround I have an alternative suggestion: Replace ,, with , , prior to =split.
However the 'proper' way is probably is to override the default remove_empty_text parameter:
=split(A1,",",,)
An alternative is to skip the SPLIT function and apply Split text into columns... instead (under Data). This will leave D1 of length 0.
I am trying to do a calculation of two cells, where one of them contains a number like this: 1 250.
If the number is written like that, and not 1250, then I cannot get the spreadsheet to do any calculations with it. Google suddenly do not treat it as a legit number anymore.
Why not just type 1250 instead of 1 250?
Well, I am getting the cell values from a html import function.
Any good advice on how to get around this?
Try something like this:
=Substitute(A2," ","")
In this formula, A2 is a cell. You are finding any spaces in that cell and then replacing it with a "non-space".
Use the substitute function to transform your number before using it in a formula. For instance, let's say you wanted to multiple F8 by 2, but F8 may contain spaces. You would then do:
=substitute(F8, " ","") * 2
Substitute didn't work form me. But these steps did:
Select one or several columns of data
Press Ctrl + H to get the "Find and Replace" dialog
Make sure "Search using regular expressions" is checked ✅
Enter \s to the "Find" field, and leave "Replace with" empty
Click on the "Replace all" button
Explanation:
\s is a regular expression matching any kind of whitespace character. There may have been some other kind of whitespace in my spreadsheet, not a regular " " (space) character, and that's why regex worked for me, while SUBSTITUTE() didn't.
I've also tried the REGEXREPLACE(A2, "\s", "") function, but it didn't seem to to anything in my case.