transform XML called by document function - xslt-2.0

Question

I'm calling in XML using document(). I need to transform the imported XML. Is this possible?
<xsl:copy-of select="document('C:\my.xml')/*"/>
<xsl:apply-templates/>
Thanks!

Answer 1

Use <xsl:apply-templates select="document('file:///c:/my.xml')/*"/>, then you only need to add templates for the nodes in the file.

Answer 2

For example, a my.xml is given below
<?xml version="1.0" standalone="no"?>
<root>
<a>XXX</a>
<b>YYY</b>
</root>
and the current xml is given below:
<?xml version="1.0" encoding="UTF-8"?>
<root_test>
<test1>123</test1>
<test2>456</test2>
</root_test>
when the following stylesheet is applied:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="root_test">
<xsl:copy>
<xsl:apply-templates/>
<xsl:apply-templates select="document('my.xml')/*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="a[document('my.xml')]">
<success><xsl:apply-templates/></success>
</xsl:template>
</xsl:stylesheet>
it outputs
<?xml version="1.0" encoding="utf-8"?>
<root_test>
123
456
<success>XXX</success>
YYY
</root_test>
notice that the templates for node a in my.xml has been applied.