NSMutableArray with int values from 1 to 100 - ios

Question

This should be dead easy, but somehow it doesn't want to work for me. Using iOS 7 and XCode 5.
All I'm trying to do is create an array with values from 1 to 100.
NSMutableArray *array;
for (int i = 0; i < 100; i++)
{
[array addObject:i];
}
This doesn't work. I get a "Implicit conversion of 'int' to 'id' is disallowed with ARC.
I get it, I can't add primitive types to an NSMutableArray.
[array addObject:#i];
This doesn't work either. I get a "unexpected '#' in program"
[array addObject:[NSNumber numberWithInt:i]];
[array addObject:[NSNumber numberWithInteger:i]];
(either case) This "works" (compiles) but it really doesn't "work". The problem with this is that the value from NSNumber is really not a 1-100. What I get for each row is "147212864", 147212832", "147212840"...not what I want.
Lastly:
for (NSNumber *i = 0; i < [NSNumber numberWithInteger:100]; i++)
{
[array addObject:i];
}
This also doesn't compile. I get an error on the i++. "Arithmetic on pointer to interface 'NSNumber', which is not a constant size for this architecture and platform"
Any suggestions on how to do this extremely simple thing on obj-c?

Answer 1

Either one of these should work:
NSMutableArray *array = [NSMutableArray array];
for (int i = 0; i < 100; i++) {
[array addObject:#(i)];
}
or
NSMutableArray *array = [NSMutableArray array];
for (int i = 0; i < 100; i++) {
[array addObject:[NSNumber numberWithInt:i]];
}
Here are the reasons why your code snippets did not work:
[array addObject:i] - You cannot add primitives to Cocoa collections
[array addObject:#i] - You forgot to enclose the expression i in parentheses
NSNumber *i = 0; i < [NSNumber numberWithInteger:100]; i++ - You cannot increment NSNumber without "unwrapping" its value first.

Answer 2

If memory serves, I think you're simply missing parenthesis around the NSNumber shorthand expression.
NSMutableArray *array = [[NSMutableArray alloc] init];
for (NSUInteger i = 0; i < 100; i++)
{
[array addObject:#(i)];
}

Answer 3

Minimally, #i should be #(i) as described here. You are also forgetting to allocate and initialise your array
NSMutableArray *array = [[NSMutableArray alloc] init];
for (int i = 0; i < 100; i++) {
[array addObject:#(i)];
}
And since you are getting: "147212864", 147212832", "147212840"...not what I want., I think you are probably printing out your information wrongly or because the array is unallocated, that's simply garbage. Can you show us how you are outputting?

Answer 4

NSMutableArray *array = [[NSMutableArray alloc] init];
NSNumber *myNum;
for (int i = 0; i < 100; i++) {
myNum = [[NSNumber alloc]initWithInt:i];
[array addObject:myNum];
}
NSLog(#"%#", array); // 1 - 99 as expected
Worked for me :)

Answer 5

Just saying: Turn on all reasonable warnings in your Xcode project. Then read what the warnings are saying and do something about them. When you write something like
for (NSNumber *i = 0; i < [NSNumber numberWithInteger:100]; i++)
What does a for loop do? An object is in the end a pointer. So you initalise i to nil. Then you compare a pointer with a random pointer: [NSNumber numberWithInteger:100] returns a pointer to an object which could be anywhere in memory, and you compare pointers. Next the i++: No, you can't increment a pointer to an NSNumber. It doesn't make sense.