Problems with Search Display Controller - ios

Question

I am learning to use Search Bars a Search Display Controllers in iOS. I made a simple test project with two views, one view contains a UITableView and a UISearchBar, when you select an row from the table view, the new view shows a label with the name of the row. I'm getting a couple of problems, first when I start to add text in the search bar and the search display appears, the search bar is gone. The filtered results are shown, but when I select a row it does not take me to the next view, this only happens when the table is filtered. Here is the code:
ViewController.h
#import <UIKit/UIKit.h>
#import "DetailViewController.h"
#interface ViewController : UIViewController <UITableViewDelegate, UITableViewDataSource, UISearchDisplayDelegate, UISearchBarDelegate>
#property (strong, nonatomic) IBOutlet UISearchBar *searchBar;
#property (strong, nonatomic) IBOutlet UITableView *tableView;
#end
ViewController.m
#import "ViewController.h"
#interface ViewController ()
#property (nonatomic, strong) NSArray *objects;
#property (nonatomic, strong) NSArray *filteredObjects;
#end
#implementation ViewController
- (void)viewDidLoad
{
[super viewDidLoad];
_objects = [[NSMutableArray alloc] initWithObjects:#"One", #"Two", #"Three", #"Four", #"Five", #"Six", #"Seven", #"Eight", #"Nine", #"Ten", nil];
_tableView.delegate = self;
_tableView.dataSource = self;
}
- (void)didReceiveMemoryWarning
{
[super didReceiveMemoryWarning];
}
-(NSInteger) numberOfSectionsInTableView:(UITableView *)tableView {
return 1;
}
- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
if (tableView == self.searchDisplayController.searchResultsTableView) {
return [_filteredObjects count];
} else {
return [_objects count];
}
}
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *CellIdentifier = #"Cell";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (!cell) {
cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
}
if (tableView == self.searchDisplayController.searchResultsTableView) {
cell.textLabel.text = [_filteredObjects objectAtIndex:indexPath.row];
} else {
cell.textLabel.text = [_objects objectAtIndex:indexPath.row];
}
return cell;
}
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([[segue identifier] isEqualToString:#"ToDetail"]) {
DetailViewController *detailViewController = [segue destinationViewController];
if (self.searchDisplayController.active) {
NSIndexPath *indexPath = [self.searchDisplayController.searchResultsTableView indexPathForSelectedRow];
detailViewController.detailString = [_filteredObjects objectAtIndex:indexPath.row];
} else {
NSIndexPath *indexPath = [_tableView indexPathForSelectedRow];
detailViewController.detailString = [_objects objectAtIndex:indexPath.row];
}
}
}
- (void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope
{
NSPredicate *resultPredicate = [NSPredicate predicateWithFormat:#"SELF contains[c] %#", searchText];
_filteredObjects = [_objects filteredArrayUsingPredicate:resultPredicate];
}
-(BOOL)searchDisplayController:(UISearchDisplayController *)controller shouldReloadTableForSearchString:(NSString *)searchString
{
[self filterContentForSearchText:searchString
scope:[[self.searchDisplayController.searchBar scopeButtonTitles]
objectAtIndex:[self.searchDisplayController.searchBar
selectedScopeButtonIndex]]];
return YES;
}
Thanks for the help!

Answer 1

when I select a row it does not take me to the next view, this only happens when the table is filtered
Because you have no implementation of tableView:didSelectRowAtIndexPath:.
Remember, there is really no such thing as a "filtered table view". There are two table views: the normal one, and the one that appears because of the search display controller. That is a different table view (basically appearing in front of yours), and you must configure it for whatever you want it to do and however you want it to look.