There is a Customer controller, it has the DeleteCustomer action method.
public class CustomerController : Controller
{
[HttpGet]
public IActionResult Index()
{
IEnumerable<CustomerViewModel> customers =
_customerRepository.GetAllCustomers().Select(s => new
CustomerViewModel
{
CustomerId = s.CustomerId,
Name = s.Name,
Adress = s.Adress
});
return View("Index", customers);
}
[HttpPost]
public IActionResult DeleteCustomer(int id)
{
_customerRepository.Delete(id);
return LocalRedirect("~/Customer/Index");
}
}
Here is the link, when clicked, the action method should work, the Id of the user I want to delete should fly into the method. But he writes an error 405. Somewhere I was mistaken I can not understand exactly where. I would be grateful for your help. I think the tag "a" is a Get request. Use #Html.ActionLink()?
<a asp-action="DeleteCustomer" asp-route-id="#item.CustomerId">Delete</a>
The problem is that DeleteCustomer only responds to POST, but HTML links are always requested via GET. However, DeleteCustomer should require a POST, so don't change that. Instead, you need to use a form like:
<form asp-action="DeleteCustomer" method="post">
<input type="hidden" name="id" value="#item.CustomerId" />
<button type="submit">Delete</button>
</form>
Then, if you want the button to look like a link, you can simply style it to look that way. If you're using Bootstrap, you can just apply the btn-link class to it.
I have a ASP.NET MVC website and a "Configuration" view with a form.
When I submit the form, I would like to do some stuff and then Redirect to my "Initialization" ViewResult... How to do it ?
My form :
#using (Html.BeginForm("Save", "Home", FormMethod.Post, new { id = "Config" }))
{
// Some fields
<input type="submit" value="Save" />
}
then, the "Save" action :
[HttpPost]
[ValidateAntiForgeryToken()]
public async Task<RedirectToRouteResult> Save(Config websiteConfiguration)
{
// Do some stuff
bool ok = await myMethod();
if(ok)
{
return RedirectToAction("Initialization");
}
}
I tried other possibilities but I don't manage to get it work...
Up, I still have the problem...
Not sure if this issue was with an earlier version of MVC, but I have often forgotten that the [HttpPost] label may be placed above an ActionResult in the controller and not just above a JsonResult.
So the simplest MVC-style answer would be just use Html.BeginForm and post to the ActionResult (with the [HttpPost] attribute), wherein you execute your logic, then call RedirectToAction at end after you have handled the post controller side.
This seems far easier than all the client-side fiddles, e.g. window.location.href = '' etc...
This is what your Form Post method should look like
<HttpPost>
<ActionName("Respond")>
Function Respond_post(viewModel As FormsRespondModel) As ActionResult
viewModel.form.formId = Guid.Parse(Request("formId"))
viewModel.form.loadForm(Guid.Parse(Request("formId")))
If (viewModel.form.formNotifications.onSuccess = "redirectOnSuccess") Then
Return Redirect(viewModel.form.formNotifications.redirectUrl)
End If
Return RedirectToRoute("form_finished")
End Function
Try this :
<input id="btnSave" name="btnSave" type="submit" value="Save" onclick="window.location = '#Url.Action("Action_Name", "Controller_Name")'; return false;" />
I am learning MVC, following THIS tutorial. (link will take you directly to where i'm stuck). so far I have learnt, there's a controller for every view. Now i have to take input from user through web entry form as mentioned in tutorial. In my project, i have a controller named Default1 and i can run it as localhost:xyz/Default1/Index. it runs perfect.
Then i created a new Controller, named Default2 and bound it to some view to display some data, and it worked perfect as localhost:xyz/Default2/Displaycustomer. the customer information was static (hard coded). and controller is as:
public ViewResult DisplayCustomers()
{
Customer cobj = new Customer();
cobj.Code = "12";
cobj.Name = "Zeeshan";
cobj.Amount = 7000;
return View("DisplayCustomers",cobj);
}
Now i have to take input from User, regarding cutomer iformation, using html page as mentioned in tutorial. so i tried adding a new webform under view folder, and and modified my controller as:
[HttpPost]
public ViewResult DisplayCustomers()
{
Customer cobj = new Customer();
cobj.Code = Request.Form["Id"].ToString();
cobj.Name = Request.Form["Name"].ToString();
cobj.Amount = Convert.ToDouble(Request.Form["Amount"].ToString());
return View("DisplayCustomers",cobj);
}
My Question is: How can i make my project stared, so that it takes input first, and then displays it, using above controller? Did i add the webform at right location? What would be the link to run it? i tried localhost:xyz/Default2/entryform etc. but failed.
(in my entryform.aspx, i have mentioned form action="DisplayCustomer" )
It sounds like what you're missing is an action to just display the form. In otherwords, you just need an action to display a form. That form's POST action should reference your controller's DisplayCustomers action.
So in your controller code:
public class CustomerController : Controller
{
[HttpGet]
public ViewResult New()
{
return View("NewCustomer"); //Our view that contains the new customer form.
}
// Add your code for displaying customers below
}
And in your view, you have code like this
#using(Html.BeginForm("DisplayCustomers", "Customer")) {
<!-- Add your form controls here -->
}
Notice that I'm using the version of the BeginForm helper that specifies the action method and controller to call. This will write the form tag to post back to your DisplayCustomers action. Here is the equivalent HTML:
<form method="POST" action="/Customer/DisplayCustomers">
You would then access your form using the URL http://test.server/Customer/New.
This may not be the best example in the world...but this will at least get you rolling..
url would be:localhost:1234/Home/Customer
the controller
public ActionResult Customer()
{
return View();
}
[HttpPost]
public ActionResult Customer(FormCollection frm)
{
var name = frm["name"].ToString();
var address = frm["address"].ToString();
ViewBag.Name = name;
ViewBag.Address = address;
return View();
}
The view
<div>
#using (Html.BeginForm())
{
<input type="text" name="name" id="name" />
<input type="text" name="address" id="address"/>
<input type="submit" name="submit" value="submit" />
<input type="text" name="namedisplay" value='#ViewBag.Name'/>
<input type="text" name="addressdisplay" value='#ViewBag.Address'/>
}
</div>
Can anyone tell me how can I submit values to Controller using ActionLink and POST method?
I don't want to use buttons.
I guess it has something with jquery.
If you're using ASP MVC3 you could use an Ajax.ActionLink(), that allows you to specify a HTTP Method which you could set to "POST".
You can't use an ActionLink because that just renders an anchor <a> tag.
You can use a jQuery AJAX post.
Or just call the form's submit method with or without jQuery (which would be non-AJAX), perhaps in the onclick event of whatever control takes your fancy.
You can use jQuery to do a POST for all your buttons. Just give them the same CssClass name.
Use "return false;" at the end of your onclick javascript event if you want to do a server side RedirectToAction after the post otherwise just return the view.
Razor Code
#using (Html.BeginForm())
{
#Html.HiddenFor(model => model.ID)
#Html.ActionLink("Save", "SaveAction", "MainController", null, new { #class = "saveButton", onclick = "return false;" })
}
JQuery Code
$(document).ready(function () {
$('.saveButton').click(function () {
$(this).closest('form')[0].submit();
});
});
C#
[AcceptVerbs(HttpVerbs.Post)]
public ActionResult SaveAction(SaveViewModel model)
{
// Save code here...
return RedirectToAction("Index");
//return View(model);
}
#Aidos had the right answer just wanted to make it clear since it is hidden inside a comment on his post made by #CodingWithSpike.
#Ajax.ActionLink("Delete", "Delete", new { id = item.ApkModelId }, new AjaxOptions { HttpMethod = "POST" })
Here was an answer baked into the default ASP.NET MVC 5 project I believe that accomplishes my styling goals nicely in the UI. Form submit using pure javascript to some containing form.
#using (Html.BeginForm("Logout", "Account", FormMethod.Post, new { id = "logoutForm", #class = "navbar-right" }))
{
<a href="javascript:document.getElementById('logoutForm').submit()">
<span>Sign out</span>
</a>
}
The fully shown use case is a logout dropdown in the navigation bar of a web app.
#using (Html.BeginForm("Logout", "Account", FormMethod.Post, new { id = "logoutForm", #class = "navbar-right" }))
{
#Html.AntiForgeryToken()
<div class="dropdown">
<button type="button" class="btn btn-default dropdown-toggle" data-toggle="dropdown">
<span class="ma-nav-text ma-account-name">#User.Identity.Name</span>
<i class="material-icons md-36 text-inverse">person</i>
</button>
<ul class="dropdown-menu dropdown-menu-right ma-dropdown-tray">
<li>
<a href="javascript:document.getElementById('logoutForm').submit()">
<i class="material-icons">system_update_alt</i>
<span>Sign out</span>
</a>
</li>
</ul>
</div>
}
ActionLink will never fire post. It always trigger GET request.
Use the following the Call the Action Link:
<%= Html.ActionLink("Click Here" , "ActionName","ContorllerName" )%>
For submitting the form values use:
<% using (Html.BeginForm("CustomerSearchResults", "Customer"))
{ %>
<input type="text" id="Name" />
<input type="submit" class="dASButton" value="Submit" />
<% } %>
It will submit the Data to Customer Controller and CustomerSearchResults Action.
This is taken from the MVC sample project
#if (ViewBag.ShowRemoveButton)
{
using (Html.BeginForm("RemoveLogin", "Manage"))
{
#Html.AntiForgeryToken()
<div>
#Html.Hidden("company_name", account)
#Html.Hidden("returnUrl", Model.returnUrl)
<input type="submit" class="btn btn-default" value="Remove" title="Remove your email address from #account" />
</div>
}
}
Use this link inside Ajax.BeginForm
#Html.ActionLink(
"Save",
"SaveAction",
null,
null,
onclick = "$(this).parents('form').attr('action', $(this).attr('href'));$(this).parents('form').submit();return false;" })
;)
My Solution to this issue is a fairly simple one. I have a page that does a customer search one by the whole email and the other by a partial, the partial pulls and displays a list the list has an action link that points to a actionresult called GetByID and passes in the id
the GetByID pulls the data for the selected customer then returns
return View("Index", model);
which is the post method
This has been a difficult problem for me to solve. How can I build a dynamic link in razor and html that can call an action method and pass a value or values to a specific action method? I considered several options including a custom html helper. I just came up with a simple and elegant solution.
The view
#model IEnumerable<MyMvcApp.Models.Product>
#using (Html.BeginForm()) {
<table>
<thead>
<tr>
<td>Name</td>
<td>Price</td>
<td>Quantity</td>
</tr>
</thead>
#foreach (Product p in Model.Products)
{
<tr>
<td>#p.Name</td>
<td>#p.Price.ToString()</td>
<td>#p.Quantity.ToString()</td>
</tr>
}
</table>
}
The action method
public ViewResult Edit(Product prod)
{
ContextDB contextDB = new ContextDB();
Product product = contextDB.Products.Single(p => p.ProductID == prod.ProductId);
product = prod;
contextDB.SaveChanges();
return View("Edit");
}
The point here is that Url.Action does not care whether the action method is a GET or a POST. It will access either type of method. You can pass your data to the action method using
#Url.Action(string actionName, string controllerName, object routeValues)
the routeValues object. I have tried this and it works. No, you are not technically doing a post or submitting the form but if the routeValues object contains your data, it doesnt matter if its a post or a get. You can use a particular action method signature to select the right method.
I have done the same issue using following code:
#using (Html.BeginForm("Delete", "Admin"))
{
#Html.Hidden("ProductID", item.ProductID)
<input type="submit" value="Delete" />
}
This is my solution for the problem.
This is controller with 2 action methods
public class FeedbackController : Controller
{
public ActionResult Index()
{
var feedbacks =dataFromSomeSource.getData;
return View(feedbacks);
}
[System.Web.Mvc.HttpDelete]
[System.Web.Mvc.Authorize(Roles = "admin")]
public ActionResult Delete([FromBody]int id)
{
return RedirectToAction("Index");
}
}
In View I render construct following structure.
<html>
..
<script src="~/Scripts/bootbox.min.js"></script>
<script>
function confirmDelete(id) {
bootbox.confirm('#Resources.Resource.AreYouSure', function(result) {
if (result) {
document.getElementById('idField').value = id;
document.getElementById('myForm').submit();
}
}.bind(this));
}
</script>
#using (Html.BeginForm("Delete", "Feedback", FormMethod.Post, new { id = "myForm" }))
{
#Html.HttpMethodOverride(HttpVerbs.Delete)
#Html.Hidden("id",null,new{id="idField"})
foreach (var feedback in #Model)
{
if (User.Identity.IsAuthenticated && User.IsInRole("admin"))
{
#Html.ActionLink("Delete Item", "", new { id = #feedback.Id }, new { onClick = "confirmDelete("+feedback.Id+");return false;" })
}
}
...
</html>
Point of interest in Razor View:
JavaScript function confirmDelete(id) which is called when the link generated with #Html.ActionLink is clicked;
confirmDelete() function required id of item being clicked. This item is passed from onClick handler confirmDelete("+feedback.Id+");return false; Pay attention handler returns false to prevent default action - which is get request to target. OnClick event for buttons could be attached with jQuery for all buttons in the list as alternative (probably it will be even better, as it will be less text in the HTML page and data could be passed via data- attribute).
Form has id=myForm, in order to find it in confirmDelete().
Form includes #Html.HttpMethodOverride(HttpVerbs.Delete) in order to use the HttpDelete verb, as action marked with the HttpDeleteAttribute.
In the JS function I do use action confirmation (with help of external plugin, but standard confirm works fine too. Don't forget to use bind() in call back or var that=this (whatever you prefer).
Form has a hidden element with id='idField' and name='id'. So before the form is submitted after confirmation (result==true), the value of the hidden element is set to value passed argument and browser will submit data to controller like this:
Request URL:http://localhost:38874/Feedback/Delete
Request Method:POST Status Code:302 Found
Response Headers
Location:/Feedback
Host:localhost:38874
Form Data X-HTTP-Method-Override:DELETE id:5
As you see it is POST request with X-HTTP-Method-Override:DELETE and data in body set to "id:5". Response has 302 code which redirect to Index action, by this you refresh your screen after delete.
I would recommend staying pure to REST principles and using an HTTP delete for your deletes. Unfortunately HTML Specs only has HTTP Get & Post. A tag only can a HTTP Get. A form tag can either do a HTTP Get or Post. Fortunately if you use ajax you can do a HTTP Delete and this is what i recommend. See the following post for details: Http Deletes
Calling $.post() won't work as it is Ajax based. So a hybrid method needs to be used for this purpose.
Following is the solution which is working for me.
Steps:
1. Create URL for href which calls the a method with url and parameter
2. Call normal POST using JavaScript method
Solution:
In .cshtml:
View
Note: the anonymous method should be wrapped in (....)()
i.e.
(function() {
//code...
})();
postGo is defined as below in JavaScript.
Rest are simple..
#Url.Action("View") creates url for the call
{ 'id': #receipt.ReceiptId } creates parameters as object which is in-turn converted to POST fields in postGo method. This can be any parameter as you require
In JavaScript:
(function ($) {
$.extend({
getGo: function (url, params) {
document.location = url + '?' + $.param(params);
},
postGo: function (url, params) {
var $form = $("<form>")
.attr("method", "post")
.attr("action", url);
$.each(params, function (name, value) {
$("<input type='hidden'>")
.attr("name", name)
.attr("value", value)
.appendTo($form);
});
$form.appendTo("body");
$form.submit();
}
});
})(jQuery);
Reference URLs which I have used for postGo
Non-ajax GET/POST using jQuery (plugin?)
http://nuonical.com/jquery-postgo-plugin/
jQuery.post() will work if you have custom data. If you want to post existing form, it's easier to use ajaxSubmit().
And you don't have to setup this code in the ActionLink itself, since you can attach link handler in the document.ready() event (which is a preferred method anyway), for example using $(function(){ ... }) jQuery trick.
Came across this needing to POST from a Search (Index) page to the Result page. I did not need as much as #Vitaliy stated but it pointed me in the right direction. All I had to do was this:
#using (Html.BeginForm("Result", "Search", FormMethod.Post)) {
<div class="row">
<div class="col-md-4">
<div class="field">Search Term:</div>
<input id="k" name="k" type="text" placeholder="Search" />
</div>
</div>
<br />
<div class="row">
<div class="col-md-12">
<button type="submit" class="btn btn-default">Search</button>
</div>
</div>
}
My Controller had the following signature method:
[HttpPost]
public async Task<ActionResult> Result(string k)
I'm working on a bit of MVC where I'm needing to dynamically route a form to a certain action and parameter combination. So far, I've got this:
PageViewModel
{
public string Action {get;set;}
public string Parameter {get;set;}
/*... other properties for the form */
}
PageController
{
public ViewResult MyAction(string myParamterName) {
return View("CommonView",
new PageViewModel{Action="MyAction", Parameter="myParameterName"));
}
public ViewResult YourAction(string yourParamterName) {
return View("CommonView",
new PageViewModel{Action="YourAction", Parameter="yourParameterName"));
}
/* ... and about 15 more of these */
}
CommonView.aspx:
<%-- ... --%>
<% using (Html.BeginForm(Model.Action,"PageController",FormMethod.Get)) {%>
<%=Html.TextBox(Model.Parameter)%>
<input id="submit" type="submit" value="Submit" />
<%}%>
<%-- ... --%>
This works, but it's got a lot of strings floating around to tell it where to go.
What I'd like to have is a type-safe way of defining the form parameters inside the view, but I'm a bit lost on how to accomplish this. Perhaps something that looks like this -
<% using (Html.BeginForm<PageController>(Model.??ExpressionToGetAction??)) {%>
<%=Html.TextBox(Model.??ExpressionToGetParameter??)%>
<input id="submit" type="submit" value="Submit" />
<%}%>
Or, is there a way to get the action and parameter used to generate this view, perhaps from route data?
Or should there be a custom routing scheme that can handle all of this automagically?
So, what I'm really wanting is the most elegant and type-safe way to accomplish this. Thanks!
EDIT
As Josh points out, the form will submit back to the action. This trims the code somewhat :
PageViewModel
{
public string ParameterName {get;set;}
/*... other properties for the form */
}
PageController
{
public ViewResult MyAction(string myParamterName) {
return View("CommonView",
new PageViewModel{ParameterName ="myParameterName"));
}
public ViewResult YourAction(string yourParamterName) {
return View("CommonView",
new PageViewModel{ParameterName ="yourParameterName"));
}
/* ... and about 15 more of these */
}
CommonView.aspx:
<%-- ... --%>
<% using (Html.BeginForm(FormMethod.Get)) {%>
<%=Html.TextBox(Model.ParameterName)%>
<input id="submit" type="submit" value="Submit" />
<%}%>
<%-- ... --%>
It is still unclear how to have the textbox bind a parameter by name back to the action from which the view was created without explicitly specifying it.
Or, is there a way to get the action and parameter used to generate this view
If you leave the action and controller portion of the BeginForm arguments empty, it will to post back to where it came from. You can have two action with the same name, one decorated as HttpGet and the other HttpPost, as long as they have different parameters. Usually the get has one or none, and the post has several or a model bind.